Guys i need a long inforation about....
"Formation of colloids"
Please and thank you ​

Answers

Answer 1
Answer:

Answer:

Colloids

There are two basic methods of forming a colloid: reduction of larger particles to colloidal size, and condensation of smaller particles (e.g., molecules) into colloidal particles. Some substances (e.g., gelatin or glue) are easily dispersed (in the proper solvent) to form a colloid; this spontaneous dispersion is called peptization. A metal can be dispersed by evaporating it in an electric arc; if the electrodes are immersed in water, colloidal particles of the metal form as the metal vapor cools. A solid (e.g., paint pigment) can be reduced to colloidal particles in a colloid mill, a mechanical device that uses a shearing force to break apart the larger particles. An emulsion is often prepared by homogenization, usually with the addition of an emulsifying agent. The above methods involve breaking down a larger substance into colloidal particles. Condensation of smaller particles to form a colloid usually involves chemical reactions—typically displacement, hydrolysis, or oxidation and reduction.


Related Questions

Which of the following statements is true with regard to transverse and longitudinal waves?Group of answer choices Both transverse waves and longitudinal waves have motion parallel to velocity. Both transverse waves and longitudinal waves have motion perpendicular to velocity. Transverse waves have motion parallel to velocity, while longitudinal waves have motion perpendicular to velocity. Transverse waves have motion perpendicular to velocity, while longitudinal waves have motion parallel to velocity.
Arrange the following substances in order of increasing solubility of water. C6H14, C6H13Br, C6H13OH, C6H12(OH)2.
What is the mass, in grams, of 1.20×1021 molecules of aspirin, c9h8o4?
Draw a well-labelled diagram showing how your body digests food​
When the chemical equation is balanced what is the ratio of the coefficient of Ag(s) to the cofficient of H2O(l)?___Ag(s)+____NO3-(aq)+____H+(aq)→ ___Ag+(aq)+____NO(g)+______H2O(l)a. 1:1b. 2:1c. 3:1d. 3:2

How many moles of CO2 form when 4.0 mol of ethane, C2H6, react?2C2H6 + 702 + 4CO2 + 6H20
A. 8 mol
B. 2 mol
C. 6 mol
D. 4 mol

Answers

Answer:

The amswer would be A due to the ratio between ethane and carbon dioxide being 1:2. Due to this, you double the moles that are reacting

A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration of a solution equals the mass of what's dissolved divided by the total volume of the solution. Here's how the student prepared the solution: The label on the graduated cylinder says: empty weight: 4.5 g She put some solid sodium hydroxide into the graduated cylinder and weighed it. With the sodium hydroxide added, the cylinder weighed 48.772 g. She added water to the graduated cylinder and dissolved the sodium hydroxide completely. Then she read the total volume of the solution from the markings on the graduated cylinder. The total volume of the solution was 152.3 mL. What concentration should the student write down in her lab notebook? Be sure your answer has the correct number of significant digits.

Answers

Answer:

sorry I don't know

better any one else say you

What is the value for the kinetic energyfor a n = 2 Bohr orbit electron in Joules?

Answers

Answer:

K.E. = 5.4362 × 10⁻¹⁹ J

Explanation:

The expression for Bohr velocity is:

v=(Ze^2)/(2 \epsilon_0* n* h)

Applying values for hydrogen atom,  

Z = 1

Mass of the electron (m_e) is 9.1093×10⁻³¹ kg

Charge of electron (e) is 1.60217662 × 10⁻¹⁹ C

\epsilon_0 = 8.854×10⁻¹² C² N⁻¹ m⁻²

h is Plank's constant having value = 6.626×10⁻³⁴ m² kg / s

We get that:

v=\frac {2.185* 10^6}{n}\ m/s

Given, n = 2

So,

v=\frac {2.185* 10^6}{2}\ m/s

v=1.0925* 10^6\ m/s

Kinetic energy is:

K.E.=\frac {1}{2}* mv^2

So,

K.E.=\frac {1}{2}* 9.1093* 10^(-31)* ({1.0925* 10^6})^2

K.E. = 5.4362 × 10⁻¹⁹ J

Consider an element Z that has two naturally occurring isotopes with the following percent abundances: the isotope with a mass number of 19.0 is 55.0% abundant; the isotope with a mass number of 21.0 is 45.0% abundant. What is the average atomic mass for element Z?Average atomic mass of Z = [mass]

Answers

Answer:

Average atomic mass = 19.9 amu

Explanation:

Isotopes can be defined as two or more forms of a chemical element that are made up of equal numbers of protons and electrons but different numbers of neutrons.

Generally, the isotopes of a chemical element have the same chemical properties because of their atomic number but different physical properties due to their atomic weight (mass number).

Given the following data;

Relative abundance of Z-19 = 55%

Relative abundance of Z-21 = 45%

Atomic mass of Z-19 = 19 amu

Atomic mass of Z-21 = 21 amu

To find the average atomic mass;

Average atomic mass = 19 * (55/100) + 21 * (45/100)

Average atomic mass = 19*0.55 + 21*0.45

Average atomic mass = 10.45 + 9.45

Average atomic mass = 19.9 amu

Therefore, the average atomic mass for element Z is 19.9 amu.

Determine the number of moles of oxygen atoms in each of the following.1) 4.93 mol H2O2
2) 2.01 mol N2O

Answers

Answer :

Part 1: 4.93 moles of H_2O_2 contains 9.86 moles of oxygen atoms.

Part 2: 2.01 moles of N_2O contains 2.01 moles of oxygen atoms.

Explanation :

Part 1: 4.93 mol H_2O_2

In 1 mole of H_2O_2, there are 2 atoms of hydrogen and 2 atoms of oxygen.

As, 1 mole of H_2O_2 contains 2 moles of oxygen atoms.

So, 4.93 moles of H_2O_2 contains 4.93* 2=9.86 moles of oxygen atoms.

Thus, 4.93 moles of H_2O_2 contains 9.86 moles of oxygen atoms.

Part 2: 2.01 mol N_2O

In 1 mole of N_2O, there are 2 atoms of nitrogen and 1 atom of oxygen.

As, 1 mole of N_2O contains 1 mole of oxygen atoms.

So, 2.01 moles of N_2O contains 2.01* 1=2.01 moles of oxygen atoms.

Thus, 2.01 moles of N_2O contains 2.01 moles of oxygen atoms.

Which statements about freshwater sources are true? Check all that apply.Only about 3 percent of Earth's water is fresh water.
Most of the fresh water on Earth is groundwater.
About 75 percent of the fresh water on Earth is frozen in ice sheets.
The largest source of usable fresh water is groundwater.
More fresh water is in the atmosphere than in rivers and lakes.

Answers

Answer: A., C., and D.

Explanation: On Edge!!

I will keep all the true statements bold, so you can understand that those are true.

Answer:

Only about 3 percent of Earth's water is fresh water.

Most of the fresh water on Earth is groundwater.

About 75 percent of the fresh water on Earth is frozen in ice sheets.

The largest source of usable fresh water is groundwater.

More fresh water is in the atmosphere than in rivers and lakes.