CHEMISTRY HIGH SCHOOL

Solutions of lead(II) nitrate and potassium iodide were combined in a test tube.Write a net ionic equation for the reaction between lead(II) nitrate and
potassium iodide.
Solutions of lead(II) nitrate and potassium iodide were combined in - 1

Answers

Answer 1
Answer:

The net ionic equation for the reaction that occurs when solutions of lead(II) nitrate and potassium iodide are combined in a test tube is:

Pb²⁺(aq) + 2 I⁻(aq) ⇒ PbI₂(s)

Solutions of lead(II) nitrate and potassium iodide were combined in a test tube. This is a double displacement reaction. The complete ionic equation is:

Pb²⁺(aq) + 2 NO₃⁻(aq) + 2 K⁺(aq) + 2 I⁻(aq) ⇒ 2 K⁺(aq) + 2 NO₃⁻(aq) + PbI₂(s)

Spectator ions are those that appear both in the reactants and in the products. They do not participate in the reaction, so they do not appear in the net ionic equation. The net ionic equation is:

Pb²⁺(aq) + 2 I⁻(aq) ⇒ PbI₂(s)

The net ionic equation for the reaction that occurs when solutions of lead(II) nitrate and potassium iodide are combined in a test tube is:

Pb²⁺(aq) + 2 I⁻(aq) ⇒ PbI₂(s)

Learn more: brainly.com/question/21883718
Answer 2
Answer:

Answer:

Explanation: When solutions of potassium iodide and lead nitrate are combined?

The lead nitrate solution contains particles (ions) of lead, and the potassium iodide solution contains particles of iodide. When the solutions mix, the lead particles and iodide particles combine and create two new compounds, a yellow solid called lead iodide and a white solid called potassium nitrate. Chemical Equation Balancer Pb(NO3)2 + KI = KNO3 + PbI2. Potassium iodide and lead(II) nitrate are combined and undergo a double replacement reaction. Potassium iodide reacts with lead(II) nitrate and produces lead(II) iodide and potassium nitrate. Potassium nitrate is water soluble. The reaction is an example of a metathesis reaction, which involves the exchange of ions between the Pb(NO3)2 and KI. The Pb+2 ends up going after the I- resulting in the formation of PbI2, and the K+ ends up combining with the NO3- forming KNO3. NO3- All nitrates are soluble. ... (Many acid phosphates are soluble.)

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Compare and contrast a chemical reaction and a nuclear reaction.

Answers

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When 20. milliliters of 1.0 M HCL is diluted to a total volume of 60. milliliters, the concentration of the resulting solution is 1. 1.0 M 2. 0.50 M 3. 0.33 M 4. 0.25 M

Answers

The concentration of the resulting solution is 0.33 M. The correct option is 3. 0.33 M

Dilution

From the question, we are to determine the concentration of the resulting solution

From the dilution law,

M₁V₁ = M₂V₂

Where M₁ is the initial concentration

V₁ is the initial volume

M₂ is the final concentration

V₂ is the final volume

From the given information

M₁ = 1.0 M

V₁ = 20 mL

M₂ = ?

V₂ = 60 mL

Then,

1 × 20 = M₂ × 60

20 = M₂ × 60

Therefore,

M₂ = 20 ÷ 60

M₂ = 0.33 M

Hence, the concentration of the resulting solution is 0.33 M. The correct option is 3. 0.33 M

Learn more on Dilution here: brainly.com/question/5685564
C₁ * V₁ = C₂ * V₂

1.0 * 20 = C₂ * 60

20 = C₂ * 60

C₂ = 20 / 60

C₂ = 0.33 M

hope this helps!

What is the ∆G for the following reaction under standard conditions (T = 298 K) for the formation of NH4NO3(s)? 2NH3(g) + 2O2(g) NH4NO3(s) + H2O(l)Given:
NH4NO3(s): ∆Hf = -365.56 kJ ∆Sf = 151.08 J/K.
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H2O(l): ∆Hf = -285.830 kJ ∆Sf = 69.91 J/K.
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Answers

∆G =  ∆H - T∆S

NH3: ∆G = -46.11x10^3 - (298)(192.45) = -103460.1 J
O2: ∆G = 0 - (298)(205) = -61090 J
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H2O: ∆G = -285.830x10^3 - (298)69.91) = -306663.18 J

∆Grex = ∆Gproducts - ∆Greactants
∆Grex = (-410581.84 +  -306663.18) - (-103460.1/2 + -61090/2)
∆Grex =-634969.97 J/mol = -634.97 kJ/mol

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Answers

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A mixture of uneven distribution and easy separation is called_____. homogeneous heterogeneous a solution a pure substance

Answers

the correct answer is heterogeneous.

Answer:

heterogeneous

Explanation:
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