How do molecules move to the location of the chemical change
Answers
In a chemical change, the molecules in the reactants interact to form new substances. In a physical change, like a state change or dissolving, no new substance is formed.
hope this helped
Final answer:
Molecules move to the location of a chemical change due to the process of diffusion. In this physical phenomenon, molecules move from an area of high concentration to an area of lower concentration. This diffusion leads to interaction between reactant molecules causing the chemical change.
Explanation:
The movement of molecules to the location of a chemical change is a fundamental concept in Chemistry. In a chemical reaction, molecules move due to a physical phenomenon known as diffusion. Diffusion is the process by which molecules of a substance move from an area of high concentration to an area of lower concentration. For example, if you open a perfume bottle at one end of a room, eventually the perfume molecules will spread throughout the room. These perfume molecules move to areas of lower concentration via diffusion. In the context of a chemical reaction, the reactant molecules diffuse to interact with each other, leading to the chemical change or reaction.
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A physical property is one that cannot be observed can be observed by altering the identity can be changed without altering the identity of a substance must be observed through chemical means
14 Which statement describes a multiple covalent bond?(1) Two electrons are shared.(2) Four electrons are shared.(3) Two electrons are transferred.(4) Four electrons are transferred.
Answers
Answer:
355 ml
Explanation:
because a can of soda could't hold more than that measure.
How many molecules are in 2.47 moles of CC14? *
Answers
1.49x10^24 molecules
Answers
The equation for power is,
Power
Where P is power is Watts
I is current in Amperes
V is voltage in volts
Given, power of the camcorder = 16 Watts
Output voltage from its battery = 8 Volts
Calculating the current in Amperes from power and voltage,
I =
= 2 A
Therefore the current used will be 2 A.
Power is defined as product of current multiplying voltage, that is
P=I×V
Here, P is the power,
I is the current
While V is the voltage
Here,
P is 16 watt
V is 8 volt
I is the current, that needs to be determined,
Putting the values in the equation
16=I× 8
I=2
So, When a camcorder has a power rating of 16 watts. If the output voltage from its battery is 8 volts, what current is 2 A
Answers
Answer:
Explanation:
PCl₅ ⇄ PCl₃ + Cl₂
1 mole 1 mole 1 mole
molecular weight of PCl₅ = 208.5
molecular weight of PCl₃ = 137.5
molecular weight of Cl₂ = 71
moles of PCl₅ = .0185
moles of PCl₃ = .0924
moles of Cl₂ = .1873
Total moles = .2982 moles
mole fraction of PCl₅ = .062
mole fraction of PCl₃ = .31
mole fraction of Cl₂ = .628
If total pressure be P
partial pressure of PCl₅ = .062 P
partial pressure of PCl₃ = .31 P
partial pressure of Cl₂ = .628 P
Kp = .31 P x .628 P / .062 P
= 3.14 P
To calculate Total pressure P
PV = nRT
P x 4 x 10⁻³ = .2982 x 8.31 x 600
P = 371.7 x 10³
= 3.717 x 10⁵ Pa
Kp = 3.14 P = 3.14 x 3.717 x 10⁵ Pa
= 11.67 x 10⁵ Pa
Kp = Kc x
= 1
11.67 x 10⁵ = Kc x
Kc = 234
Answers
In this context, by decreasing the temperature, the system will shift in the direction that produces more heat, essentially favoring the exothermic reaction. This shift allows the system to absorb the added heat and counteract the temperature decrease.
Answers
90 /30 = 3
3 x (CH2O) = C3H6O3
Final answer:
The molecular formula of a compound with an empirical formula of CH₂O and a molar mass of 90 g/mol is C₃H₆O₃. This is found by dividing the compound's molar mass by the molar mass of the empirical formula, and using the ratio to multiply the subscripts in the empirical formula.
Explanation:
The molecular formula of a compound can be determined using the molar mass and the empirical formula given. The empirical formula for the compound is CH₂O, which has a molar mass of approximately 30 g/mol (12 g for C, 1 g for H, and 16 g for O). If the molar mass of the compound is 90 g/mol, we can find the ratio of the molar mass of the compound to the empirical formula by dividing 90 g/mol by 30 g/mol, which gives us 3.
This means the molecular formula of this compound is three times the empirical formula. So, to obtain the molecular formula, you multiply each subscript in the empirical formula by 3. If you do this for CH₂O, you get C₃H₆O₃ which is the molecular formula of the compound.
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