Find the value of x (3x+38)5x

Answers

Answer 1
Answer:

Answer:

19

Step-by-step explanation:

3x = -38 + 5x

3x + -5x = -38 + 5x + 5x

3x + -5x = -2x

-2x = -38 + 5x + -5x

5x + 5x =0

-2x = -38 + 0

-2x = -38

-2x / -12 = 38 / -2

x=19


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Solve for c ab+c=5 c=5/ab c=5-ab c=5+ab

The product of two integers is 50. one integer is twice the other. find the integers.

Answers

(1) -5*(-10)=50
(2) 5*10=50
use what they are telling. 

a*b=50 (one integer times the other give you a product of 50. we're randomly calling these integers "a" and "b")

2a=b (one integer is twice the amount of the other. we're randomly selecting "b" to be twice the amount of "a")

plug in what we know 

a*(2a)=50 (we replaced "b" with "2a" because we know from the info they gave us that b=2a)

now solve for "a"

a*2a=50
2a²=50
a²=50/2
a²=25
√a²=√25
a=5

which because 2a=b we know that b=10 

Find all relative extrema of the function. use the second derivative test where applicable. (if an answer does not exist, enter dne.) f(x) = x3 − 9x2 + 2

Answers

First find the derivative of the function.  The derivative is f'(x)=3 x^(2) -18x.  Now set it equal to 0 to find the critical numbers.  0=3 x^(2) -18x.  Factor to solve for the zeros of the derivative.  0=3x(x-6).  So 3x = 0, and x = 0, or x - 6 = 0 and x = 6.  We will make a table with values for -∞<x<0, 0<x<6, 6<x<∞.  Pick a value within those boundaries for each interval and find the sign, positive or negative, that results from subbing that number into the derivative.  If we choose -1 in the first interval f'(-1)=21, so the function is increasing from negative infinity to 0.  If we choose 1 in the second interval, f'(1)=-15, so the function is decreasing from 0 to 6.  If we choose 10 in the last interval, f'(10)=120, so the function is increasing from 6 to infinity.  The points of extrema are found by subbing the critical x values into the original function. We know the function is increasing from negative infinity to 0, so f(0)=2, and our max point is (0, 2).  We know the function is decreasing from 6 to infinity, so f(6)=-106, and our min point is (6, -106).  I do this instead of the second derivative test, but they both work.

All four sided polygons are quadrilaterals

Answers

This is a true statement (:

If (m, 1) is on a circle with center (8, 1) and radius 7, what is a value of m?A)m=1
B)m=-1
C)m=14
D)m=-8=-+sqrt33

Answers

A) m=1

The equation for the circle is:

(x-8)^2 + (y-1)^2 = 49

If we take 'y' as 1, then

(x-8)^2 + 0 = 49

x-8 = √49

x = ±7 + 8

x = 15 or x = 1

What is the quotient (x^3+8)/(x+2)

Answers

Answer:

Step-by-step explanation:

The easiest way to do this is by using synthetic division (I really hope you know what I'm talking about!)

If the factor is x + 2 = 0, then the solution or the root is x = -2.  We will put -2 outside the "box" and the coefficients from the terms of the polynomial inside the "box":

-2|   1    0    0    8

Bring down the first number and multiply it by the -2.  Put the product up under the first 0 and add:

-2|   1    0    0    8

           -2

      1   -2  

Now multiply the -2 by the -2, put the product up under the next 0 and add:

-2|   1    0    0    8

           -2    4

      1    -2    4

Now multiply the 4 by the -2, put the product up under the 8 and add:

-2|   1    0    0    8

           -2   4    -8

     1    -2   4    0

Those bold numbers are the coefficients to the quotient, which is another polynomial, but is one degree less than the one you started with:

x² - 2x + 4 = 0

Since there is no remainder, then x = -2 is a zero of x³ + 8, and (x + 2) is a factor.

There is a whole world of stuff to learn about quadratics!!

Simplify the expression. 12^–3 • 12^10 • 12^0A. 1

B. 1728^7

C. 12^7

D. 36^7

Answers

since they have the same base we can just add all the exponents

-3+ 10= 7

keep the base so the answer is
12^7