MATHEMATICS HIGH SCHOOL

The sum of two numbers is 19, and their difference is 55. What are the two numbers?

Answers

Answer 1

Answer:

Answer:

37 and -18

Step-by-step explanation:

Let one number be x and other y

1 x + 1 y = 19 .............1

1 x -1 y = 55 .............2

Eliminate y

multiply (1)by 1

Multiply (2) by 1

1 x 1 y = 19

1 x + -1 y = 55

Add the two equations

2 x = 74

/ 2

x = 37

plug value of x in (1)

1 x + 1 y = 19

37 + 1 y = 19

1 y = 19 -37

1 y = -18

y = -18

37 and -18

Answer 2

Answer:

Final answer:

The two numbers, which sum to 19 and have a difference of 55, are 37 and -18.

Explanation:

The sum and difference of two numbers can provide the solution to the problem. In this case, the sum of the two numbers is 19 and the difference is 55. To solve this, we start by setting up two equations based on the problem: x + y = 19 and x - y = 55.

Then we solve these equations simultaneously. We can add the two equations together to eliminate 'y'. This gives us 2x = 74, or x = 37. Substituting x = 37 into the first equation, we get 37 + y = 19, which gives y = -18.

So, the two numbers are 37 and -18.

Learn more about Solving Simultaneous Equations

brainly.com/question/148035

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Uh- I don't understand

Answers

Answer:

16000

5(I'm not 100 percent sure its 5 )

Step-by-step explanation:

hope this helps! :)

Help please it's due 11:59 pmSuppose there are two car dealerships, A and B. At A, each member of the sales staff is paid a fixed monthly amount of
$2,000 plus a $200 bonus for each car he or she sells. At B, each salesperson is paid a fixed monthly amount of $2,500 but
does not receive a bonus for each car he or she sells. In which setting will a member of the sales staff be more likely to
work harder? Why is this important?

Answers

They would work harder at A because if they sell 3 cars they would get paid more than if they worked at B

15 POINTS!!!HELP!! JUST TELL ME THE FORMULA I NEED TO USE !!!

Answers

Answer: No.

Step-by-step explanation: It's obviously a quiz of some sort. If it's not, then why would it be timed? Please don't do this :(

a teacher and 10 students are to be seated along a bench in the bleachers at a basketball game. In how many ways can this be done if the teacher must be seated in the middle and a difficult student must sit to the teachers immediate left?

Answers

Wow !

OK. The line-up on the bench has two "zones" ...

-- One zone, consisting of exactly two people, the teacher and the difficult student.
   Their identities don't change, and their arrangement doesn't change.

-- The other zone, consisting of the other 9 students.
   They can line up in any possible way.

How many ways can you line up 9 students ?

The first one can be any one of 9.   For each of these . . .
The second one can be any one of the remaining 8. For each of these . . .
The third one can be any one of the remaining 7. For each of these . . .
The fourth one can be any one of the remaining 6. For each of these . . .
The fifth one can be any one of the remaining 5. For each of these . . .
The sixth one can be any one of the remaining 4. For each of these . . .
The seventh one can be any one of the remaining 3. For each of these . . .
The eighth one can be either of the remaining 2. For each of these . . .
The ninth one must be the only one remaining student.

   The total number of possible line-ups is

   (9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1) = 9! = 362,880 .

But wait ! We're not done yet !

For each possible line-up, the teacher and the difficult student can sit

-- On the left end,
-- Between the 1st and 2nd students in the lineup,
-- Between the 2nd and 3rd students in the lineup,
-- Between the 3rd and 4th students in the lineup,
-- Between the 4th and 5th students in the lineup,
-- Between the 5th and 6th students in the lineup,
-- Between the 6th and 7th students in the lineup,
-- Between the 7th and 8th students in the lineup,
-- Between the 8th and 9th students in the lineup,
-- On the right end.

That's 10 different places to put the teacher and the difficult student,
in EACH possible line-up of the other 9 .

So the total total number of ways to do this is

   (362,880) x (10) = 3,628,800 ways.

If they sit a different way at every game, the class can see a bunch of games
without duplicating their seating arrangement !

Answer:

Step-by-step explanation:

362,880

What is the completely factored form of the expression 16x2 + 8x + 32?

Answers

8 is a common factor for all coeficients so we factor it out first: 8(2x^2 + x + 4). Now we have to check can we factor the quadratic equasion in the brackets to linear factors. To do that we need to check is the discriminant D=b^2 - 4ac > 0 where a=2, b=1 and c=4. When we insert our numbers, we get: D= -31. We see that D < 0 so 8(2x^2 + x + 4) is the completely factored form.

Answer:

8(2x^2 + x + 4)

Step-by-step explanation:

edge2020

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.True or False?

Answers

With the center and the point (-6,2) you can deduce the equation of the circle

(x-xo)^2 + (y-yo)^2 = r^2

(x+3)^2 + (y-4)^ = r^2

r^2 is otained from the center and the point (-6,2)

r^2 = (-6 -(-3))^2 + (2-4)^2 = (-6+3)^2 + (-2)^2 = (-3)^2 + 4 = 9 + 4 = 13.

Then the equation of the circle is

(x+3)^2 + (y-4)^ = 13

Now we subsitute the point (10,4) into that equation and see whether it belongs to it:

(10+3)^2 + (4-4)^2 = 13^2

13^2 ≠ 13, so the point does not belong to the equation.

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