Answers
Answer:
1.7820210165667731 your welcome :)
Explanation:
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Cyclohexanecarboxylic acid, C6H11COOH (pKa 4.90), is only slightly soluble in water, but its sodium salt, C6H11COO-Na , is quite soluble in water. Describe the solubility of cyclohexanecarboxylic acid in solutions of sodium hydroxide, sodium bicarbonate (NaHCO3), and sodium carbonate (Na2CO3). The pKa values for the conjugate acids of sodium hydroxide, sodium bicarbonate (NaHCO3), and sodium carbonate (Na2CO3) are 15.7, 6.36, and 10.33, respectively.
Answers
Answer : The conversion used is,
Explanation :
The conversion used :
For example : To convert 10 feet into inches.
From this we conclude that, the conversion factor used in the numerator and denominator for 1 feet should be,
Final answer:
When converting from feet to inches, use the conversion factor 12 inches/1 foot. This way, the unit 'foot' cancels out and leaves 'inches', performing the conversion. An example is converting 5 feet to inches is 5 times 12, which equals to 60 inches.
Explanation:
When you're converting units, such as feet to inches, the main guideline is to set up your conversion factor in a way that cancels out the unit you want to convert from and leaves you with the unit you want to convert to. In this case, since you're converting from feet to inches, you'll be using the fact that there are 12 inches in 1 foot as your conversion factor. Therefore, when converting, the conversion factor should be set up as 12 inches/1 foot. This in essence means you're multiplying by the number 1, which doesn't change the value, just the units.
For instance, if you have 5 feet and you want to convert this to inches, you'll set your conversion factor up as 12 inches/1 foot, with inches in the numerator and feet in the denominator, to cancel out feet. Multiply 5 feet by the conversion factor (12 inches/1 foot), the result would be 60 inches. Here, the 'feet' units cancel leaving the answer in inches, completing the conversion.
Learn more about Unit Conversion here:
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Answers
Answer:
compaction and cementation
Explanation:
sedimentary rock is layered rock, in order to become sedimentary it most be compacted to form layers and cemented to become hard. This is what i think. Hope i can help :)
c) potassium, K(s)
b) manganese, Mn(s)
d) boron, B(s)
Answers
Answer:
The molar mass of:
Helium = 4.00 g/mol
Potassium = 39.0983 g/mol
Manganese = 54.94 g/mol.
Boron = 10.81 g / mol
Explanation:
Helium = 4.00 g/mol
Potassium = 39.0983 g/mol
Manganese = 54.94 g/mol.
Boron = 10.81 g / mol
Answers
The dilution of each tube are as follows;
- Tube 2; 8.26 × 10-³
- Tube 3; 7.5 × 10-⁴
- Tube 4; 6.83 × 10-⁵
For each time a dilution is further diluted;
The dilution ratio is; 1 : 11; In essence, 0.5 mL of agent was added to 5.0 mL of nutrient broth.
- For the first tube; dilution factor is; 1 : 11 = 9.1× 10-²
- For the second tube; 0.5mL of the first tube was added to 5.0mL of the nutrient broth; The dilution factor is then; (1/11) × (1/11) = 1/121 = 8.26 × 10-³.
- For the third tube; 0.5mL of the second tube was added to 5.0mL of the nutrient broth; The dilution factor is then; (1/11) × (1/11) ×(1/11) = 1/121 = 7.5 × 10-⁴.
- For the fourth tube; 0.5mL of the third tube was added to 5.0mL of the nutrient broth; The dilution factor is then; (1/11) × (1/11) × (1/11) × (1/11) = 1/14641 = 6.83 × 10-⁵.
Read more;
Answer:
Tube 2: 8.26 * 10^-3; Tube 4: 6.83 * 10^-5
Explanation:
In the serial dilutions for MIC test, the volume of nutrient broth in each tube should be equal: 5.0 mL. And the volume of agent in each dilution should also be similar: 0.5 mL.
The serial dilutions was as following:
- Tube 1: 0.5/5.5
- Tube 2: 0.5 mL of tube 1 was diluted with 5.0 mL broth. Then, the dilution of tube 2 is (1:11) * (1:11) = (0.5/5.5) * (0.5/5.5) = 1:121 = 8.26 * 10^-3
- Tube 3: We perform the similar calculation. Thus, the result is 1:1331 = 7.51 * 10^-4
- Tube 4: It is 1:14641 = 6.83 * 10^-5.
Answers
Pb(NO₃)₂ ⇒limiting reactant
moles PbI₂ = 1.36 x 10⁻³
% yield = 87.72%
Further explanation
Given
Reaction(unbalanced)
Pb(NO₃)₂(s) + NaI(aq) → PbI₂(s) + NaNO₃(aq)
Required
- moles of PbI₂
- Limiting reactant
- % yield
Solution
Balanced equation :
Pb(NO₃)₂(s) + 2NaI(aq) → PbI₂(s) + 2NaNO₃(aq)
mol Pb(NO₃)₂ :
= 0.45 : 331 g/mol
= 1.36 x 10⁻³
mol NaI :
= 250 ml x 0.25 M
= 0.0625
Limiting reactant (mol : coefficient)
Pb(NO₃)₂ : 1.36 x 10⁻³ : 1 = 1.36 x 10⁻³
NaI : 0.0625 : 2 = 0.03125
Pb(NO₃)₂ ⇒limiting reactant(smaller ratio)
moles PbI₂ = moles Pb(NO₃)₂ = 1.36 x 10⁻³(mol ratio 1 : 1)
Mass of PbI₂ :
= mol x MW
= 1.36 x 10⁻³ x 461,01 g/mol
= 0.627 g
% yield = 0.55/0.627 x 100% = 87.72%
Answers
Answer:
C4H4O8
Explanation:
The molecular formula of a compound with empirical formula: CHO2 can be calculated as follows:
(CHO2)n = 180g/mol
{12 + 1 + 16(2)}n = 180
(12+1+32)n = 180
(45)n = 180
n = 180/45
n = 4.
The molecular formula = (CHO2)4
= C4H4O8