MATHEMATICS COLLEGE

Help please !!!! algebra question !!!

Answers

Answer 1

Answer:

Answer:

it depends on the value of x

Step-by-step explanation:

Eg. if x = 1

then, 3(1) < 4

and if, x = 2

then, 3(2) > 4

hope this helps

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HELP QUICK!!!L 18 16 12 10 4 32 34 36 38 40 14 46 54 50 08 The graph shows that as Fincreases, C o decreases increases is constant increases then decreases

You want to rent an unfurnishedone-bedroomapartment for next semester. The mean monthlyrent for a random
sample of 10 apartments advertised in the localnewspaper is $580.
Assume that the standard deviation is$90. Find a 95% confidence
interval for the mean monthly rentfor unfurnished one bedroom
apartments available for rent in thiscommunity.

Answers

Answer: $(\$524.22,\ \$635.78)$

Step-by-step explanation:

Confidence interval for population mean is given by :-

$\overline{x}\pm z^* (\sigma)/(√(n))$

, where $\overline{x}$ = Sample mean

z* = critical z-value.

$\sigma$ = Population standard deviation.

n= Sample size.

Let x be the denotes the monthly rent for unfurnished one bedroom apartments available for rent in this community.

As per given , we have

n= 10

$\overline{x}=\$580$

$\sigma=\$90$

Critical value for 95% confidence : z* = 1.96

So the 95% confidence interval becomes,

$580\pm (1.96) (90)/(√(10))$

$=580\pm (1.96) (90)/(3.162278)$

$=580\pm (1.96)(28.46)$

$=580\pm 55.78$

$=(580-55.78,\ 580+55.78)=(524.22,\ 635.78)$

Hence, a 95% confidence interval for the mean monthly rent for unfurnished one bedroom apartments available for rent in this community= $(\$524.22,\ \$635.78)$

In year 3 it is expected that the total value of clothing sales will reach 32 million if the total value of ASCO sells Remains the Same as year 2what percentage of sales clothing account for in year three

Answers

Answer:

The sales account for year 3 is $[\frac{32\ \text{mn}-x\ \text{mn}}{x\ \text{mn}}* 100\%]$ .

Step-by-step explanation:

As the sales for year 2 is not provided, assume it is x million.

The total sales in year 3 is, 32 million.

Compute the sales account for year 3 as follows:

$\text{Percentage of sales for year 3}=\frac{\text{Total Sales in year 3}-\text{Total Sales in year 2}}{\text{Total Sales in year 2}}* 100\%$

$=\frac{32\ \text{mn}-x\ \text{mn}}{x\ \text{mn}}* 100\%$

Consider the polygon shown. Determine the value of y. PLEASE HELP

Answers

Answer:

y = 64°

Step-by-step explanation:

From the picture attached,

m(∠E) = 90°

m(∠E) = m(∠D)

m(∠B) + 67° = 180° [pair of linear angles]

m(∠B) = 113°

m(∠C) + 75° = 180°

m(∠C) = 180° - 75°

= 105°

Since, sum of interior angles of a polygon = (n - 2) × 180°

Here, n = number of sides

For n = 5,

Sum of interior angles = (5 - 2) × 180°

= 540°

m(∠A) + m(∠B) + m(∠C) + m(∠D) + m(∠E) = 540°

m(∠A) + 113° + 105° + m(∠D) + 90° = 540°

(m∠D) + m(∠D) = 540 - 308 [Since, m(∠A) = m(∠D)]

2(m∠D) = 232

m(∠D) = 116°

m(∠D) + y° = 180° [Linear pair of angles]

116 + y = 180

y = 64°

Let C be the unit circle in the xy-plane, oriented counterclockwise as seen from above. The divergence of the vector field F~ = (z, x, y) is zero, and as a result the flux through every surface with boundary C should be the same. Confirm that this is the case with the upper half of the unit sphere, the lower half of the unit sphere, and the unit disk in the xy-plane

Answers

Upper half of the unit sphere (call it $S_1$ ): parameterize by

$\vec s(u,v)=(\cos u\sin v,\sin u\sin v,\cos v)$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take the normal vector to be

$(\partial\vec s)/(\partial v)*(\partial\vec s)/(\partial u)=(\cos u\sin^2v,\sin u\sin^2v,\cos v\sin v)$

Then the flux of $\vec F$ over this surface is

$\displaystyle\iint_(S_1)\vec F\cdot\mathrm d\vec S=\int_0^(\pi/2)\int_0^(2\pi)(\cos v,\cos u\sin v,\sin u\sin v)\cdot(\cos u\sin^2v,\sin u\sin^2v,\cos v\sin v)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^(\pi/2)\int_0^(2\pi)\cos u\sin^2v\cos v+\cos u\sin u\sin^3v+\sin u\cos v\sin^2v=\boxed{0}$

Lower half of the sphere (call it $S_2$ ): all the details remain the same as above, but with $\frac\pi2\le v\le\pi$ . The flux is again $\boxed{0}$ .

Unit disk (call it $D$ ): parameterize the disk by

$\vec s(u,v)=(u\cos v,u\sin v,0)$

with $0\le u\le1$ and $0\le v\le2\pi$ . Take the normal vector to be

$(\partial\vec s)/(\partial u)*(\partial\vec s)/(\partial v)=(0,0,u)$

Then the flux across $D$ is

$\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^(2\pi)\int_0^1(0,u\cos v,u\sin v)\cdot(0,0,u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^(2\pi)\int_0^1u^2\sin v\,\mathrm du\,\mathrm dv=\boxed{0}$

Final answer:

The flux through every surface with boundary C, such as the upper half of the unit sphere, the lower half of the unit sphere, and the unit disk in the xy-plane, should be the same and it is zero.

Explanation:

The divergence of the vector field F~ = (z, x, y) is zero. Therefore, the flux through every surface with boundary C, such as the upper half of the unit sphere, the lower half of the unit sphere, and the unit disk in the xy-plane, should be the same.

This can be confirmed by considering that the electric flux through a closed surface is zero if there are no sources of electric field inside the enclosed volume. Since there are no charges inside the surfaces mentioned, the flux through each surface is zero.

Therefore, the flux through the upper half of the unit sphere, the lower half of the unit sphere, and the unit disk in the xy-plane is the same, and it is zero.

Learn more about Electric Flux here:

brainly.com/question/38239959

#SPJ3

In the right triangle shown m

Answers

I needa see it tho for I could help

you can’t see anything

HELP!How do you derive the equation of a circle?
How do you identify the center and radius of a circle?
How do you define the radian measure of an angle?
How are arc length and area of a sector related to proportionality?

Answers

Answer:

How do you derive the equation of a circle?

you can reverse the circle formula

How do you identify the center and radius of a circle?

You can identify the center because it is the middle of the circle and the radius can be draw from the center to the round part.

How do you define the radian measure of an angle?

it is the ratio of the length of the arc the angle forms÷the radius of the circle

How are arc length and area of a sector related to proportionality?

sector x radian

area = (r^2 x)/2

arc length = r x

they are not propotional

because Area / arc length = r/2 , (it's not a constant)

High Hopes

Barrii