MATHEMATICS COLLEGE

The owner of a grocery store wants to mix two kinds of candy together to make 15 lb that he can sell for $5.00 per lb. He wants to use chocolate candies that he sells for $7.00 per lb and sugar candies that he sells for $2.00 per lb. How many pounds of each should the owner use?_ pounds of chocolate candies
_ pounds of sugar candies
=OWO=

Answers

Answer 1

Answer:

Answer: 9 pounds of chocolate and 6 pounds of sugar candies

Let's define the variables:

C = pounds of chocolate candies used.

S = pounds of sugar candies used.

We know that he wants to make a total of 15lb, then:

C + S = 15

We also want that the price per pound to be equal to 5$.

This means that the price of the 15 pounds will be the same as the price of the un-mixed candies.

C*$7.00 + $2.00*S = $5.00*15

Then we have a system of equations:

C + S = 15

C*$7.00 + $2.00*S = $5.00*15

To solve this system, we need to start by isolating one of the variables, i will isolate C in the first equation:

C = 15 - S

now we can replace that in the other equation:

(15 - S)*$7.00 + $2.00*S = $5.00*15

Now we can solve this for S.

$105 - $5.00*S = $75

$105 - $75 = $5.00*S

$30 = $5.00*S

$30/$5 = S = 6

Then there are 6 pounds of sugar candy, and we can use the equation:

C + S = 15

C + 6 = 15

C = 15 - 6 = 9

There are 9 pounds of chocolate candy in the mix.

Step-by-step explanation:

Answer 2

Answer:

Final answer:

To find the pounds of chocolate and sugar candies the owner should use, set up and solve equations based on the given information.

Explanation:

Let's assume that the owner uses x pounds of chocolate candies and y pounds of sugar candies.

According to the problem, the total weight of the candies should be 15 pounds.

So, we can set up the equation:

x + y = 15

The owner wants to sell the candies for $5.00 per pound. We can set up another equation to represent the total value of the candies:

7x + 2y = 5 * 15

Now we can solve these equations to find the values of x and y.
By solving the equations, we find that x = 9 and y = 6.

Therefore, the owner should use 9 pounds of chocolate candies and 6 pounds of sugar candies.

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There are 80 participants in a competition. The average score of each participant is 58.5. The average score of the male participants is 64 and the average score of the female participants is 56. How many male participants are there in the competition?
Please help! Thank youu
Proportional relationships

1) Which number line belowshows x 4?
a)
1 2 3 4 5 6
b)
0 1 2 3 4 5 6

C)26
O i 2 3 4
D)5
0 1 2
3 4 5
6
A
B
оооо
С
D

Answers

It’s c i think or can be d but my best bet is c !!

Right triangle ABC is shown. Which of these is equal to cos(A)?A) cos(B)
B) cos(C)
C) sin(B)
D) sin(C)

Answers

Answer: C

cosA=AC/AB

sinB=AC/AB

hence cosA=sinB

Answer:

C).

Step-by-step explanation:

Since angles A and B are complementary, their cofunctions are equal. So, cos(A) = sin(B).

What is the absolute value of -4

Answers

Answer:

the answer is 4

Step-by-step explanation:

the absolute value means it doesn't consists of any sign (neither positive nor negative)

Answer:

Step-by-step explanation:

Easiest way to remember absolute value is the number always comes out positive.

l-4l=4

Consider random samples of size 40 from a population with proportion 0.15. (a) Find the standard error of the distribution of sample proportions.
Round your answer for the standard error to three decimal places.
mean=______
standard error=_______
(b) Is the sample size large enough for the Central Limit Theorem to apply?
1. Yes
2. No

Answers

The standard error of the distribution of sample proportions is 0.056 and mean is 0.15.

Yes, the sample size is enough for the Central Limit Theorem to apply.

(a). Given that, size of sample, $n=40$

Proportion, $p=0.15$

In the distribution of sample proportions, mean $\mu=p$

and, standard error = $\sqrt{(p(1-p))/(n) }$

So, mean $\mu=0.15$

Standard error = $\sqrt{(0.15(1-0.15))/(40) }=0.056$

(b). The Central Limit Theorem applies if np > 5 .

$np=40*0.15=6>5$

Thus, the Central Limit Theorem is applied.

Learn more:

brainly.com/question/22233199

Answer:

a) The mean is 0.15 and the standard error is 0.056.

b) 1. Yes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = (\sigma)/(√(n))$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For proportions p, in samples of size n, the mean is $\mu = p$ and the standard error is $s = \sqrt{(p(1-p))/(n)}$ . The Central Limit Theorem applies is np > 5 and np(1-p)>5.

In this question:

$n = 40, p = 0.15$

(a) Find the mean and the standard error of the distribution of sample proportions.

$\mu = 0.15, s = \sqrt{(0.15*0.85)/(40)} = 0.056$

So the mean is 0.15 and the standard error is 0.056.

(b) Is the sample size large enough for the Central Limit Theorem to apply?

np = 40*0.15 = 6 > 5

np(1-p) = 40*0.15*0.85 = 5.1>5

So yes

MATH

ANSWER and I will give you brainiliest

Answers

Answer:

2000

Step-by-step explanation:

If 3 days = 600 we need to know what 1 day is so we do 600 / 3

600 / 3 = 200

Then multiply 200 by 10 to find 10 days

200 * 10 = 2000

10 days = 2000

PLZ IM ON THE CLOCK!!!!! A sports memorabilia store makes $6 profit on each football it sells and $5.50 profit on each baseball it sells. In a typical month, it sells between 35 and 45 footballs and between 40 and 55 baseballs. The store can stock no more than 80 balls total during a single month. What is the maximum profit the store can make from selling footballs and baseballs in a typical month? $457.50 $460.00 $462.50 $572.50

Answers

Answer:

460

Step-by-step explanation:

Answer:

460

Step-by-step explanation:

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