Solar energy is used to produce energy-rich compounds in which structure?A.A
B.B
C.C
D.D
Solar energy is used to produce energy-rich compounds in which - 1

Answers

Answer 1
Answer:

Chloroplast is the site for photosynthesis in plants. Thus, option A is correct.

What are chloroplasts?

Chloroplasts are the cell organelles present in the plants. Chloroplasts are one such type of plastids.

Chloroplasts are green in colour. They contain a green coloured pigment called chlorophyll which traps the solar energy.

The solarenergy is converted into chemicalenergy by a process called photosynthesis. The organic molecules so produced are the energyrich compounds.

Chloroplasts are chiefly found in the mesophyll region of the leaves.

Chloroplast consists of grana and stroma regions. The grana contain disc shaped coin like structures called thylakoids. The matrix of chloroplasts constitutes stroma region.

Various enzymes, DNA, ribosomes etc are found within the chloroplasts. Hence, they are also referred as 'cellwithinthecell'.

Chloroplasts have unique feature of self-replication. Chloroplasts are similar in function to mitochondria in animal cells.

Therefore, chloroplasts are important plant structures for photosynthesis.

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Answer 2
Answer:

In plants, photosynthesis takes place in chloroplasts. Option A is correct.

What is Chloroplast ?

Plant, algae, and certain protist cells have membrane-bound organelles called chloroplasts.

So, They are in charge of the process known as photosynthesis, which turns light energy into chemical energy in the form of glucose in green plants and some other animals. Life on Earth is supported by this essential mechanism of energy conversion.

Therefore, In plants, photosynthesis takes place in chloroplasts.

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Plasmodesmata in plant cells are most similar in function to which of the following structures in animal cells?A. tight junctions
B. desmosomes
C. peroxisomes
D. extracellular matrix
E. gap junctions

Answers

Answer:

E

Explanation:

Gap junctions in animals, like plasmodesmata in plants, connect the cytoplasm of two cells through dedicated and regulated channels. A gap junction is made of two hemichannels connected together leaving a channel that is 2-4 nm across -tranversing the two cells' cell membranes. The gap junctions allow for the cells to signal each other through allowing exchange of ions and other moelcules. One significance of gap junction is in enhancing communication between cells in the development of tissues and embryo.

Final answer:

Plasmodesmata in plant cells are most similar in function to gap junctions in animal cells.

Explanation:

Plasmodesmata are channels that connect plant cells and allow for the exchange of various materials, including nutrients and signaling molecules. They are most similar in function to gap junctions in animal cells. Gap junctions are specialized channels that connect neighboring animal cells, allowing for the direct transfer of small molecules and ions.

Like plasmodesmata, gap junctions play a crucial role in cell-cell communication and coordination within tissues. They facilitate the rapid passage of substances, such as ions and small metabolites, between adjacent cells, allowing for coordinated responses and sharing of resources.

Therefore, the answer to this question is E. gap junctions.

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(c) Based on the data in Table 1, describe why the dominant alleles for body color and wing shape are the alleles that produce a gray body and long wings, respectively. Based on the data, describe why the two genes are most likely on different chromosomes or why they are most likely on the same chromosome. Calculate the probability of producing flies that have gray bodies and vestigial wings if a cross is performed between one of the F1 flies from the first analysis and a fly that is homozygous for a gray body and vestigial wings.

Answers

Mendel was the first to explain the transmission of phenotypic characters and the independent assortment of the genes.

In the given data, F2 progeny of phenotypic traits are shown.

In the above observations, the gray body long wings and ebony body vestigial wing are parental combinations.

Also, the gray body and vestigial wings, and ebony body long wings are the recombinants.

The given ratio in the progeny indicates that gray bodies and long wings are expressed.

The genes for the two traits are independently assorted, which means that genes are unlinked present on the samechromosome.

Now,

For the F1 progeny:

  • Gg Ll - G for Grey and L for Long
  • The cross between F1 progeny and true gray vestigial will be:
  • GGll x GgLl
  • Gametes:  GL Gl gL gl Gl

The cross between Gl and hybrid will result in a 50% chance of flies having the gray body and vestigial wings.

b) In the above given F2 progeny, the cross between true gray body and long wings with true ebony body and vestigial wings, will result in the independent assortment of the genes.

Given:

  • Parental gametes - GGLL x ggll
  • Gametes produced - GL and gl

For the F1 progeny, all the offspring will have genotype GgLl  (Gray body and long wings but in heterozygous condition)

The above cross can be shown in the Punnett square, which is given in the attachment below.

To know more about Mendelian ratio, refer to the following link:

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Answer:

Check the explanation

Explanation:

Consider the below table of F2 data of phenotypic flies: we can reconstruct the table as seen in the second attached image below:

From the above observations it is clear the Gray body long wings and Ebony body vestigial wings are the parental combinations and that the Gray body vestigial wings and Ebony body long wings are the recombinants.

Also the ratio indicates that Gray body is dominant over ebony body and that long wings is dominant over vestigial wings.

here the genes for the two characters have shown independent assortment which means that the genes are unlinked if located on the same chromosome or are located  on different chromosomes.

Now F1 hybrid= GgLl (G for Grey and L for Long)

Cross between F1 hybrid and true breeding Gray vestigial (GGll)

GgLl x GG ll

Gametes-----------> GL Gl gL gl Gl

        GL                          Gl                      gL                  gl

Gl    GGLl                      GGll                  GgLl               Ggll

   (Gray long)      (Gray vestigial)     (gray Long)     (Gray vestigial)

Therefore the probability of getting the flies with gray body vestigial wings= 2/4= 50%

b) The reason why the students obtained the above given F2 results involving a cross between true breeding Gray body and long wings with true breeding Ebony body and vestigial wings is that the genes for the two charcters asssort independently in F2 generation and that the genes are not linked as:

Parents------------------> GGLL x ggll

Gametes -----------------> GL gl

F1---------------------> GgLl (Gray long but in heterozous condition)

Now GgLl x GgLl

Gametes GL Gl gL gl   GL Gl gL gl

Here gametes assorted independently and hence in F2 generation we got the above results (U can show the results in the form of punnett square.

Clamworms and earthworms both belong to phylum Annelida. Curiously, earthworms have a thin cuticle outside of their epidermis and clamworms do not. Considering the relationship between an organism's form/function and its environment, which of the following provides the MOST logical explanation for this difference?a. The cuticle maintains salt balance in a marine environment.
b. The cuticle provides protection against predators.
c. The cuticle prevents water loss in a terrestrial environment.
d. The cuticle allows for improved gas exchange.

Answers

Answer: c. The cuticle prevents water loss in a terrestrial environment.

Explanation:

The earthworms have a thin cuticle outside their epidermis. The cuticle performs different functions in the worm body. The cuticle protects the worm from predators. The thin cuticle remains moist with the slimy mucus. The cuticle helps in the exchange of gases from the external environment. The cuticle helps in absorbing the oxygen from the external environment whereas it expels the carbon dioxide to the external environment. The cuticle prevents the loss of moisture and allows the gaseous exchange which facilitates the survival of the worm in a harsh terrestrial environment.

In guinea pigs, a single gene with two alleles (B and b) determines coat color. Black (B) is dominant over white (b). A guinea pig from a true-breeding black strain is mated with a guinea pig from a true-breeding white strain. The F1 progeny are all black. Two of the F1 progeny are mated with each other. What proportion of the black F2 progeny is expected to be heterozygous?

Answers

Answer: Half of the black F2 progeny is expected to be heterozygous.

Explanation: I used a Punnett square to predict the next generations’ alleles.

Which organism can process more complex information due to a central brain? anemone, jellyfish, fish or planarian?

Answers

Jellyfish, they are consider the smartest and they have found things in them to help treat cancer.

What is Central brain?

The brain and spinal cord make up the central nervous system (CNS). It is one of the nervous system's two components. The peripheral nervous system, which consists of nerves linking the brain and spinal cord to the rest of the body, is the other component.

The body's processing center is the central nervous system. The majority of bodily processes, including awareness, movement, thought, speech, and the five senses of sight, hearing, feeling, tasting, and smelling, are controlled by the brain.

A brain extension is the spinal cord. It communicates with the brain by way of a network of peripheral nerves that are attached to it.

Therefore, Jellyfish, they are consider the smartest and they have found things in them to help treat cancer.

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Jellyfish, they are consider the smartest and they have found things in them to help treat cancer.

Which equipment is best to hold and to measure liquids?

Answers

Answer:

Flash and Graduated cylinder

Explanation:

Answer:

Volumetric Flasks and Cylinders

Explanation: