The amount of light a star gives off is used to determine the star’s a.number of planets
b.position in the galaxy
c.shape
d.brightness

Answers

Answer 1

Answer: b. position in the galaxy

Answer 2

Answer: i think its b hope this helps

Related Questions

The price of a flight was increased by 2% to £700. What was the price before the increase? Give your answer to the nearest penny.
Simplify. (-5.12) - (-4.7) + (7.021) 6.79 6.601 -2.799
What are the characteristics of the graph of the inequality y>-3/5x+5
For a science experiment, Mr. Barrows divides 3/4 cup of salt into small jars, each containing 1/10 cup. If he has 1/7 cup of salt left over, how many jars does he fill? Enter an expression you could use to solve the problem.
Simplify 8d-6e - 3d + 4e.

Chris has a collection of 20 baseball cards and Kyle has collection of 40 baseball cards. Chris is adding 3 baseball cards per month to his collection while Kyle is adding one baseball card per month to his collection. After how many months will Chris and Kyle have the same number of baseball cards?

Answers

Answer:

11 months

Step-by-step explanation:

The initial number of baseball cards that Chris has is 20.

This is like the first term of a sequence.

If Chris is adding 3 baseball cards per month, then there will be a constant difference of 3.

The number of baseball cards after $n$ months is given by the formula;

$C_n=20+(n-1)3$

$\Rightarrow C_n=20+3n-3$

$\Rightarrow C_n=3n+17$ where $n\ge1$

Similarly, Kyle initially has 40 baseball cards and adds one base ball card per month to his collection;

The number of his baseball cards after $n$ months is given by the formula;

$K_n=40+(n-1)1$

$K_n=40+n-1$

$\Rightarrow K_n=n+39$

To determine the number of months that will pass before Kyle and Chris have the same number of base ball cards, we equate both equations to get;

$\Rightarrow 3n+17=n+39$

We group like terms to get;

$3n-n=39-17$

$\Rightarrow 2n=22$

$\Rightarrow n=11$

Therefore Chris and Kyle will have the same number of baseball cards after 11 months.

Final answer:

By setting equal the linear expressions for how many baseball cards Chris and Kyle have after a given number of months, we find that it will take 10 months for them to have the same number.

Explanation:

The question is essentially asking how long it will take for Chris and Kyle to have the same number of baseball cards. It's a problem about linear expressions, rooted in mathematics. Chris starts with 20 baseball cards and adds 3 per month. We can express this as C = 20 + 3m, where m is the number of months. Kyle starts with 40 baseball cards and adds 1 per month. We express this as K = 40 + m.

We want to find out when Chris and Kyle will have the same number of cards, so we set C = K, which results in 20 + 3m = 40 + m. By solving this equation, we can condense it to 2m = 20 or m = 10. Therefore, it will take 10 months for Chris and Kyle to have the same number of baseball cards.

Learn more about Linear Equations here:

brainly.com/question/32634451

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Two welders working together can complete a job in 6 h. One of the welders, working alone, can complete the task in 15 h. How long would it take the second welder, working alone, to complete the task?

Answers

ur asking a bunch of these kind of rate problems xD
$6 ( (1)/(15) + (1)/(x) )=1$
In 6 hrs, the welder who does 1/15 of the job in 1 hr and the welder who does 1/x in 1 hr, complete the job (6 hrs.)
$(1)/(15) + (1)/(x) = (1)/(6)$
Multiply 30 on both sides to cancel out the fractions and we get:
$2 + (30)/(x) =5$
Solving for x:
30/x=3
3x=30
x=10
The second welder would take 10 hours.

If F(x)=3x-1 and g(x)=2x+5a. (F o g)(x)
b. (g o f)(x)
c. (f o g)(-2)
d. (g o f)(-2)

Answers

( fog )(x) = f(g(x)) =3*g(x) - 1 = 3(2x+5) -1 = 6x + 15 - 1 = 6x + 14;
( gof )(x) = g(f(x)) = 2 *f(x) + 5 =2(3x-1) + 5 = 6x-2 + 5 = 6x + 3 ;
( fog )(-2) = 6*(-2) +14 = -12 + 14 = 2;
( gof )(-2) = 6*(-2) + 3 = -12 + 3 = - 9.

Prove that tan 225 cot 405 + cot 675 tan 765 = 0

Answers

$tan225^ocot405^o+cot675^otan765^o=0\n\nL=tan(180^o+45^o)cot(2*180^o+45^o)+\dots\n\dots+cot(4*180-45^o)tan(4*180^o+45^o)\n\n=tan45^ocot45^o+cot(-45^o)tan45^o=1-cot45^otan45^o\n\n=1-1=0\n\n===================================\n\ntan\alpha* cot\alpha=1\n\ncot(-\alpha)=-cot\alpha$

Jules kicks a soccer ball off the ground and into the air with an initial velocity of 25 feet per second. Assume the starting height of the ball is 0 feet. Approximately what maximum height does the soccer ball reach?0.8 ft

1.6 ft

9.8 ft

19.6 ft

Approximately, how long does it take until the soccer ball hits the ground again?

0.6 sec

0.8 sec

1.6 secs

2.8 secs

Answers

Answer:

Maximum height=9.8 ft and Time taken by soccer ball will be 0.8 secs

Step-by-step explanation:

Since, the ball kicked will take the motion of projectile, therefore using the equation: h(t)= $at^(2) +vt+d$ , where h(t) is the height of the soccer ball, a is the acceleration whose value is -16 ft/sec^2 and v= 35 feet and d is the starting height which is equal to zero.

Therefore, h(t)= $at^(2) +vt+d$ (1)

Differentiating this equation with respect to t,

$h^(')(t)$ = $2at+v$

$0$ = $2(-16)t+25$

$32t$ = $25$

$t= 0.781sec$

Substituting the value of t in equation (1),

$h(t)=-16(0.781)^(2) +25(0.781)$

= $(-16)(0.609)+19.525$

= $9.766$

≈9.8ft

Hence, option C is correct.

Now, In order to determine the time taken until the soccer ball hits the ground, we take the equation:

$h(t)= at^(2) +vt+d$

Since, when the ball hits the ground, the height will become equal to zero, therefore we have, h(t)=0

Now, $h(t)= at^(2) +vt+d$

$0= -32.174t^(2) +25t$

$0=t(-32.174t+25)$

Then, one solution is t=0 and the other is: $0=-32.174t+25$

$32t=25$

$t=(25)/(32.174)$

$t=0.777 sec$

$t$ ≈ $0.8 sec$

Hence, option B is correct.

Answer:

9.8 ft for the maximum height

1.6 sec for the time it’ll take for the ball to hit the ground again

I just took a test and it shows me what I got wrong alongside the correct answers. And this was a question it asked.

What is the next fraction in this sequence? Simplify your answer. 3/4, 1/4, 1/12, 1/36

Answers

hey their,

3/4
1/4
1/12
1/36
0/60

The pattern is -1/x every 2 +x/8

How i got this was 36/12=3
3*12=36
so 60-36=24
24x3/2+24=60
then 60/5=12

Hopethis helped

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