given that the only known ionic charges of lead are pb(ii) and pb(iv), how can you explain the existence of the pb2o3 salt

Answers

Answer 1

Answer:

Answer:

See Explanation

Explanation:

Pb2O3 is better formulated as PbO.PbO2. It is actually a mixture of the two oxides of lead, lead II oxide and lead IV oxide.

This implies that this compound Pb2O3 (sometimes called lead sesquioxide) is a mixture of the oxides of lead in its two known oxidation states +II and +IV.

Hence Pb2O3 contains PbO and PbO2 units.

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How many moles of atoms are in 9.00 g of 13c? express your answer numerically in moles?

Answers

Number of moles is defined as the ratio of given mass in grams to the molar mass of compound.

Number of moles = $(Given mass in g)/(Molar mass)$

Now, put the value of given mass of $^(13)C$ in grams and molar mass of $^(13)C$ in g/mol i.e. 13 g/mol.

Thus,

number of moles = $(9.00 g)/(13 g/mol)$

= 0.692 mol

Hence, number of moles of $^(13)C$ = 0.692 mol

wo reactions and their equilibrium constants are given. A + 2 B − ⇀ ↽ − 2 C K 1 = 2.57 2 C − ⇀ ↽ − D K 2 = 0.226 A+2B↽−−⇀2CK1=2.572C↽−−⇀DK2=0.226 Calculate the value of the equilibrium constant for the reaction D − ⇀ ↽ − A + 2 B .

Answers

Answer: The value of equilibrium constant for the net reaction is 11.37

Explanation:

The given chemical equations follows:

Equation 1: $A+2B\xrightarrow[]{K_1} 2C$

Equation 2: $2C\xrightarrow[]{K_2} D$

The net equation follows:

$D\xrightarrow[]{K} A+2B$

As, the net reaction is the result of the addition of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

$K=K_1* (1)/(K_2)$

We are given:

$K_1=2.57$

$K_2=0.226$

Putting values in above equation, we get:

$K=2.57* (1)/(0.226)=11.37$

Hence, the value of equilibrium constant for the net reaction is 11.37

What is the freezing point of a solution of 7.15 g MgCl2 in 100 g of water? K f for water is 1.86°C/m. What is the freezing point of a solution of 7.15 g MgCl2 in 100 g of water? K f for water is 1.86°C/m. -0.140°C -2.80°C -1.40°C -4.18°C

Answers

Answer:

THE NEW FREEZING POINT IS -4.196 °C

Explanation:

ΔTf = 1 Kf m

molarity of MgCl2:

Molar mass = (24 + 35.5 *2) g/mol

molar mass = 95 g/mol

7.15 g of MgCl2 in 100 g of water

7.15 g = 100 g

(7.15 * 100 / 1000) = 1000 g or 1 L or 1 dm3

= 0.715 g /dm3

Molarity in mol/dm3 = molarity in g/dm3 / molar mass

= 0.715 g /dm3 / 95 g/mol

m = 0.00752 mol/ dm3

So therefore:

ΔTf = i Kf m

1 = 3 (1 Mg and 2 Cl)

Kf = 1.86 °C/m

M = 0.752 moles

So we have:

ΔTf = 3 * 1.86 * 0.752

ΔTf = 4.196 °C

The new freezing point therefore will be 0 °C - 4.196 °C which is equals to - 4.196 °C

Chloride is nearly twice the size of chlorine even though it only gains one electron. Explain why.

Answers

Chloride is nearly twice the size of chlorine due to the fact that when it does gain an electron, the atomic radius also increases. Chloride ion has a bigger atomic radius due to an increase in number of electrons

True or False: Observations are just things that you see

Answers

Answer:

False

Explanation:

"Observations is the action of observing something or someone carefully or in order to gain information" - google dictionary. This definition does not completely match the definition given, so the answer is false.

I hope this helps!

Answer: true

Explanation: the action or process of observing something or someone carefully or in order to gain information that is the real definition

What is the molecular geometry if you have a double bond, a single bond and 1 lone pair around the central atom?

Answers

Answer:

4 pairs are needed for the bonds, leaving 1 lone pair. Each double bond uses 2 bond pairs and can be thought of as a single unit. There are 2 double bond units and 1 lone pair, which will try to get as far apart as possible - taking up a trigonal planar arrangement.

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