From the combinations of substances listed below, which would most likely be miscible ineach other?
(33 Points)
A.polar water, nonpolar oil
B.polar vinegar, nonpolar nail polish
C. polar bleach, polar water
D.nonpolar mineral oil, polar alcohol

Answers

Answer 1
Answer:

Answer:

C

Explanation:

polar has unequal sharing of electrons that has the lone pairs which has the electronegativity difference. can be mixed with water.

Answer 2
Answer:

Final answer:

The combination of polar bleach and polar water would likely be most miscible with each other as substances with similar molecular structures and polarities tend to mix. This is based on the rule of 'like dissolves like' in chemistry.

Explanation:

The question is asking which combination of substances would be most likely to mix, or be miscible, in one another. Miscibility is a property in chemistry relating to whether different substances can combine into a homogeneous mixture without separating.

The rule of thumb in chemistry is 'like dissolves like' which means that substances with similar molecular structures and polarities tend to be miscible with each other. Therefore, among the provided options, the combination of polar bleach and polar water (Option C) would be the most likely to mix with each other as they are both polar substances.

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A solution in which the pH is 1.6 would be described asa.
very acidic
b.
slightly acidic
c.
very basic
d.
slightly basic
e.
neutral

Answers

Answer:

a.  very acidic

Explanation:

A solution with a pH of 1.6 would be described as a very acidic solution.

The pH scale is a convenient scale for expressing the level of acidity or alkalinity of aqueous solutions.

The scale ranges from 1 to 14 in which case 1 is the lower limit and 14 the upper limit.  

  • An acidic solution has a pH value less than 7. As pH decreases, the acidity of the solution increases.
  • Neutral solutions have a pH of 7
  • An alkaline solution has a pH greater than 7 and the level of alkalinity increases as pH increases.

1. Thein an atom of that element.
number of an element equals the number of protons
2. The exact position of the electrons of an atom cannot be determined because they are
in constant
to the nucleus of an atom have the least
3. The electrons
amount of energy
4. The number of
bonds that atom can form.
in an atom tells you how many chemical

Answers

Answer:

1. Proton = electron if the element is not in an ionic state

proton = atomic number

How many moles of MgS2O3 are in 223 g of the compound

Answers

Answer: 1.63 moles

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023* 10^(23) of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}=

Given mass = 223 g

Molar mass = 136.4

\text{Number of moles}=(223g)/(136.4g/mol)=1.63moles

Thus there are 1.63 moles in 223 g of the compound.

Moles of MgS2O3 = 223/molar mass of MgS2O3
    
                              =   223/136.42 
                              =     1.634 moles.

Hope this helps!

What is the empirical formula of a compound composed of 36.7 g 36.7 g of potassium ( K K ) and 7.51 g 7.51 g of oxygen ( O O )? Insert subscripts as needed.

Answers

Answer:

K₂O

Explanation:

Given parameters:

Mass of K = 36.7g

Mass of O = 7.51g

Unknown:

Empirical formula of the compound

Solution:

The empirical formula of a compound is it's simplest ratio by which the elements in the compound combines. It differs from the molecular formula that shows the actual atomic ratios.

To find the empirical formula, follow this process;

   

Elements                     K                               O

Mass                          36.7                            7.51

Molar

mass                            39                            16

Number of

moles                       36.7/39                    7.51/16

                                   0.94                        0.47

Divide by

the smallest              0.94/0.47               0.47/0.47

                                         2                              1

  Empirical formula is        K₂O

                                     

Final answer:

The empirical formula of the compound composed of 36.7 g of potassium and 7.51 g of oxygen is K2O.

Explanation:

To determine the empirical formula of a compound, we need to find the ratio of the elements present. In this case, we have 36.7 g of potassium and 7.51 g of oxygen. To find the ratio, we need to convert these masses to moles by dividing them by the molar masses of potassium and oxygen. The molar mass of potassium is 39.10 g/mol and the molar mass of oxygen is 16.00 g/mol. Dividing the masses by the molar masses gives us 0.939 mol potassium and 0.469 mol oxygen. The ratio between these two elements is approximately 2:1, so the empirical formula of the compound is K2O.

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How is the combined gas law modified to form the ideal gas law?A) each side of the equations is divided by the number of moles
B) the temperature of the gas is stipulated to be absolute zero
C) each side of the equation is multiplied by air pressure at sea level
D) the volume of each gas particle is added to the equation

Answers

The answer is A) each side of the equations is divided by the number of moles
The combined gas law equation
     P1V1/T1 = P2V2/T2
becomes
     P1V1/n1T1 = P2V2/n2T2
with the addition of Avogadro's law relating volume and number of moles of a gas.This modification is when the number of moles of gas in a sample is allowed to change in addition to pressure, temperature and volume. This also means that pressure multiplied by the volume and divided by the product of the number of moles and temperature is a constant:
     PV/nT = constant
which if written in the form PV = nRT is the ideal gas law equation where R is the gas constant.

Answer:

A) each side of the equations is divided by the number of moles

Explanation:

Consider the dissolution of AB(s):AB(s)⇌A+(aq)+B−(aq)Le Châtelier's principle tells us that an increase in either [A+] or [B−] will shift this equilibrium to the left, reducing the solubility of AB. In other words, AB is more soluble in pure water than in a solution that already contains A+ or B− ions. This is an example of the common-ion effect.The generic metal hydroxide M(OH)2 has Ksp = 1.05×10−18. (NOTE: In this particular problem, because of the magnitude of the Ksp and the stoichiometry of the compound, the contribution of OH− from water can be ignored. However, this may not always be the case.)What is the solubility of M(OH)2 in pure water?

Answers

Answer:

S = 6.40 × 10⁻⁷ M

Explanation:

In order to calculate the solubility (S) of M(OH)₂ in pure water we will use an ICE Chart. We recognize 3 stages: Initial, Change and Equilibrium, and we complete each row with the concentration or change in concentration.

            M(OH)₂(s) ⇄ M²⁺(aq) + 2 OH⁻(aq)

I                                   0                  0

C                                 +S               +2S

E                                   S                 2S

The solubility product (Kps) is:

Kps = 1.05 × 10⁻¹⁸ = [M²⁺].[OH⁻]²=S.(2S)²

1.05 × 10⁻¹⁸ = 4S³

S = 6.40 × 10⁻⁷ M