CHEMISTRY COLLEGE

Find the mass of oxygen in grams produced by the decomposition of 100.0 g of CO2

Answers

Answer 1

Answer:

The balanced chemical equation is :

$2CO_2->2CO+O_2\n\n$

Moles of $CO_2$ ,

$n = (100\ g)/(44.01\ g/mol)\n\nn=2.27\ mol$

Now, by given chemical equation , we can see 2 mole of $CO_2$ react with 1 mole of $O_2$ .

So , 2.27 mole react with :

$N=(2.27)/(2)\ mol\n\nN=1.135\ mol$

Mass of oxygen is :

$M = N * 16\n\nM=1.135* 16\ g\n\nM =18.16\ g$

Therefore, mass of oxygen in grams produced is 18.16 g.

Hence, this is the required solution.

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A gummie bear was tested through a flame-calorimeter test. the bear had a mass of 1.850 grams and the temperature of 100.0 milliliters of water increased by 15.0 degrees celsius. how many calories were in the gummie bear? show all of your calculations.

2Identify at least two factors which influence
periodic poperties of elements in groups
and periods

Answers

atomic radius

ionization potential

Atomic radius and Ionization Energy

Please help!!
which oneeeee

Answers

b is the correct answer

The value of delta for the [C_rF_6]^3- complex is 182 kJ/mol. Calculate the expected wavelength of the absorption corresponding to promotion of an electron from the lower-energy to the higher-energy of orbital set in this complex. (Remember to divide by Avogadro's number.) Should the complex absorb in the visible range?

Answers

Answer: Yes the absorb in the visible range.

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

$E=(Nhc)/(\lambda)$

where,

$E$ = energy of the wave = 182 kJ/mol = 182000 J/mol

N = avogadro's number = $6.023* 10^(23)$

h = plank constant = $6.6* 10^(-34)Js^(-1)$

c = speed of light = $3* 10^8m/s$

$\lambda$ = wavelength of the wave = ?

Putting all the values:

$182000=(6.023* 10^(23)* 6.6* 10^(-34)* 3* 10^8m/s)/(\lambda)$

$\lambda=0.65* 10^(-6)m=650nm$ $(1nm=10^(-9)m)$

The wavelength range for visible rays is 400 nm to 750 nm, thus the complex absorb in the visible range.

Final answer:

The expected wavelength of the absorption in the [CrF6]3- complex cannot be calculated without knowing the exact value of ΔE. Therefore, it is unclear if the complex will absorb in the visible range.

Explanation:

In this complex, the value of delta (Δ) is 182 kJ/mol. To calculate the expected wavelength of the absorption corresponding to the promotion of an electron from the lower-energy orbital to the higher-energy orbital, we can use the equation: Wavelength = (hc)/(ΔE), where h is Planck's constant and c is the speed of light. By substituting the given values and dividing by Avogadro's number, we can calculate the expected wavelength.

However, the information given in the question does not provide the exact value for ΔE. Without this information, it is not possible to calculate the expected wavelength accurately. Therefore, we cannot determine if the complex will absorb in the visible range.

Learn more about Calculating expected wavelength of absorption in a complex here:

brainly.com/question/38332205

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Which one of the following combinations cannot function as a buffer solution?A) HCN and KCN
B) NH3 and (NH4)2SO4
C) HNO3 and NaNO3
D) HF and NAF
E) HNO2 and NaNO2

Answers

Answer:

it is B

; )

Which one of the following combinations cannot function as a buffer solution?

A) HCN and KCN

B) NH3 and (NH4)2SO4

C) HNO3 and NaNO3

D) HF and NAF

E) HNO2 and NaNO2

What type of compound is disulfur dichloride?a. organic compound
b. acid (ionic compound)
c. covalent compound
d. ionic compound

Answers

Answer:

Covalent compound

Explanation:

It is formed by covalent bonds, in which the atoms share a pair of valence electrons

Three different samples were weighed using a different type of balance for each sample. The three were found to have masses of 0.6160959 kg, 3.225 mg, and 5480.7 g. The total mass of the samples should be reported as?

Answers

Answer:

6.1 kg

Explanation:

To obtain the total mass of the sample, we must first express each mass of the sample in the same unit of measurement.

Since the SI unit of mass is kilogram (kg), we shall express the total mass of the samples in kilogram (kg).

This is illustrated below:

Mass of the samples are:

M1 = 0.6160959 kg

M2 = 3.225 mg

M3 = 5480.7 g.

Conversion of 3.225 mg to kg

1 mg = 1×10¯⁶ kg

Therefore,

3.225 mg = 3.225 × 1×10¯⁶

3.225 mg = 3.225×10¯⁶ kg

Conversion of 5480.7 g to kg

1000 g = 1 kg

Therefore,

5480.7 g = 5480.7 /1000

5480.7 g = 5.4807 kg

Thus, we can obtain the total mass of the samples as follow:

M1 = 0.6160959 kg

M2 = 3.225×10¯⁶ kg

M3 = 5.4807 kg

Total mass =?

Total mass = M1 + M2 + M3

Total mass = 0.6160959 + 3.225×10¯⁶ + 5.4807

Total mass = 6.096799125 ≈ 6.1 kg

Therefore, the total mass of the samples is approximately 6.1 kg.

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