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If 49 jules of work is done when a 7 newton wagon of cheeseburgers is pulled, how far does it move?​

Answers

Answer 1
Answer: W=f*d
d=w/f
d=49/7
d=7 meter

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If gear a rotates with a constant angular acceleration of aa = 90 rad>s2, starting from rest, determine the time required for gear d to attain an angular velocity of 600 rpm. Also, find the number of revolutions of gear d to attain this angular velocity. Gears a, b, c, and d have radii of 15 mm, 50 mm, 25 mm, and 75 mm, respectively.

Answers

solution:

Given: (let a = alpha)</p><p>aA = 90 rad/s^2</p><p>(wd) = 600 rpm = 62.831 rad/s</p><p>(w0) = 0 rpm</p><p>ra = .015 m</p><p>rb = .05 m</p><p>rc = .025 m</p><p>rd = .075</p><p>aB = aA*(ra/rb) = 90 * (.015/.05)</p><p>aB = 27 rad/s^2</p><p>aC = aB, Therefore aC = 27 rad/s^2</p><p>aD = aC*(rc/rb) = 27 * (.025/.075)</p><p>aD = 9 rad/s^2

What is the medium through which the wave is moving?

Answers

Answer:

STRING held by the man

Explanation:

Wave is defined as a disturbance that travels through a MEDIUM and transfer energy from one point to another without causing any permanent displacement of the medium itself.

The medium through which wave travels varies e.g water, string, air etc

According to the diagram, wave travels through the string held by the man. This string is referred to as the MEDIUM through which the wave moves. The wave generated produces both crest (D) and trough (C) when displaced from its initial position (A)

Rope or one could consider it to be C to B or A to D

The atmosphere on Venus consists mostly of CO2. The density of the atmosphere is 65.0 kg/m3 and the bulk modulus is 1.09 x 107 N/m2. A pipe on a lander is 75.0 cm long and closed at one end. When the wind blows across the open end, standing waves are caused in the pipe (like blowing across the top of a bottle). a) What is the speed of sound on Venus? b) What are the first three frequencies of standing waves in the pipe?

Answers

Answer:

a. 409.5 m/s b. f₁  = 136.5 Hz, f₂ = 409.5 Hz, f₃ = 682.5 Hz

Explanation:

a. The speed of sound v in a gas is v = √(B/ρ) where B = bulk modulus and ρ = density. Given that on Venus, B = 1.09 × 10⁷ N/m² and ρ = 65.0 kg/m³

So, v = √(B/ρ)

= √(1.09 × 10⁷ N/m²/65.0 kg/m³)

= √(0.01677 × 10⁷ Nm/kg)

= √(0.1677 × 10⁶ Nm/kg)

= 0.4095 × 10³ m/s

= 409.5 m/s

b. For a pipe open at one end, the frequency f = nv/4L where n = mode of wave = 1,3,5,.., v = speed of wave = 409.5 m/s and L = length of pipe = 75.0 cm = 0.75 m

Now, for the first mode or frequency, n = 1

f₁ = v/4L

= 409.5 m/s ÷ (4 × 0.75 m)

= 409,5 m/s ÷ 3 m

= 136.5 Hz

Now, for the second mode or frequency, n = 2

f₂ = 3v/4L

= 3 ×409.5 m/s ÷ (4 × 0.75 m)

= 3 × 409,5 m/s ÷ 3 m

= 3 × 136.5 Hz

= 409.5 Hz

Now, for the third mode or frequency, n = 5

f₃ = 5v/4L

= 5 × 409.5 m/s ÷ (4 × 0.75 m)

= 5 × 409,5 m/s ÷ 3 m

= 682.5 Hz

A bicycle wheel of radius 0.70 m is rolling without slipping on a horizontal surface with an angular speed of 2.0 rev/s when the cyclist begins to uniformly apply the brakes. the bicycle stops in 5.0 s. how far did the bicycle travel during the 5.0 seconds of braking?

Answers

Distance traveled by the bicycle during the 5 seconds of braking is 22m

Explanation:

initial angular velocity= 2 rev/s

final angular velocity= 0 rev/s

Angular displacement Ф=((wi+wf)/(2) )t

Ф=((0+2)/(2) )5=5 rev

so the distance travelled= 5(2πr)

distance=5(2π*0.7)

distance=22m

The bicycle traveled about 22 m during the 5.0 seconds of braking

\texttt{ }

Further explanation

Centripetal Acceleration can be formulated as follows:

\large {\boxed {a = \frac{ v^2 } { R } }

a = Centripetal Acceleration ( m/s² )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

\texttt{ }

Centripetal Force can be formulated as follows:

\large {\boxed {F = m \frac{ v^2 } { R } }

F = Centripetal Force ( m/s² )

m = mass of Particle ( kg )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

Let us now tackle the problem !

\texttt{ }

Given:

radius of wheel = R = 0.70 m

initial angular speed = ω = 2.0 rev/s = 4π rad/s

final angular speed = ωo = 0 rad/s

time taken = t = 5.0 s

Asked:

distance covered = d = ?

Solution:

d = \theta R

d = (\omega + \omega_o)(1)/(2)t R

d = ( 4 \pi + 0 ) (1)/(2)(5.0)( 0.70 )

d = 4\pi (1.75)

d = 7\pi \texttt{ m}

d \approx 22 \texttt{ m}

\texttt{ }

Learn more

\texttt{ }

Answer details

Grade: High School

Subject: Physics

Chapter: Circular Motion

Define reflection of sound?​

Answers

The reflection of sound is the movement of sound waves bouncing off of a surface and back into another direction, hope this helped :)

A sheet of aluminum alloy is cold-rolled 33 percent to a thickness of 0.096 in. If the sheet is then cold-rolled to a final thickness of 0.061 in., what is the total percent cold work done

Answers

Answer:

 The total percent cold work done is 36.46%

Explanation:

Let initial metal thickness = T

Final metal thickness = t

The percent cold work done = WC

Then

%Wc = (T - t)/T × 100

% Wc = ( 0.096 - 0.061 )/0.096 ×100

Total %WC = 36.46%

Answer:

The total percent of cold work is 57.34%

Explanation:

Let x the initial thickness of the sheet. After 33% of cold working, the thickness is 0.096 in. Then:

x - 0.33x = 0.096

x = 0.143 in

the final thickness is equal to 0.061 in. The percent of cold work done is:

percent-of-cold-work=((initial-thickness)-(final-thickness))/(initial-thickness)*100

percent-of-cold-work=(0.143-0.061)/(0.143) *100=57.34%
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