Anna baked 3 batches of cookies with c cookies in each batch. She then ate 888 cookies!How many cookies does Anna have left?

Answers

Answer 1

Answer:

You have 12 cookies left because C=300

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Let f(x)=-4x+7 and g(x)=10x-6. Find f(g(x))

Answers

$\bf \begin{cases}f(x)=-4x+7\ng(x)=10x-6\end{cases}\qquad \qquad f(~~g(x)~~)=-4[g(x)]+7\n\n\nf(~~g(x)~~)=-4[10x-6]+7\implies f(~~g(x)~~)=-40x+24+7\n\n\nf(~~g(x)~~)=-40x+31$

A businessman has 10 employees. His salary is equal to 6 times the average of employees salaries. If the 11 of them receive a total of $64,000 in one year, what was the business mans salary that year ?? a) $4000, b) $6000, c) $24,000, d) $ 40,000, e) $44,000

Answers

business man's salary = x
employee's salary = y

x + 10y = 64000
x = 6y

(6y) + 10y = 64000
16y = 64000
y = 4000

x = 6(4000)
x = 24000

Answer: (c) $24,000

HELP PLEASE MATH 1 QUESTION !!

Answers

220,000 x (1.055)^15 = 491,145

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The expression b/c=b/c is an example of (n)

Answers

equality equaiton
a=a

Kate is at a T-shirt sale where she can buy one and get a second one for 30% off. She wants to buy two T-shirts listed at $19 each. How much will she pay?

Answers

So in this problem we can state that each T-shirt costs S19 each. And if Kate buys two she gets a 30% off with the second shirt she buys. And how much will she pay?

Solution:
1.       19 for each t-shirt
2.       Total of $38 if not provided with 30% off
3.       19 x 0.3 = 5.7
4.       Hence 30% of $19 is $5.7
5.       Next is we deduct $5.7 which is 30% of $19.
6.       19 – 5.7 = $13.3
7.       Therefore we add one shirt for $19 and the second, less 30% off which now only costs for $13.3.
8.       19 + 13.3 = 32.3
9.       Conclusively, she will pay $32.3 for the shirts.

Need to find the product of (3a+3)(4a+1)

Answers

I used the FOIL method First outer inner last
I multiplied the first variables together (3a*4a) and got 12a^2
So just do what common sense tells you to do
Multiply the first parts of the quantities, the outer parts of the quantities, the inner parts of the quantities and the last parts of the quantities to get
12a^2+3a+12a+ 3
Then group it together
$12a^(2) + 15a + 3$

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