4272/6 use partial qutiants to divide
Answers
Answer:
712
Step-by-step explanation:
Hope this helps :D
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Answers
one way is to factor the expressions
(a)
(1.2 + (5.35 ×
))
= (1.2 + 53.5)
= 54.7 × = 5.47 ×
×
= 5.47 ×
(b)
((6.91 ×
) + 2.4)
= (69.1 + 2.4)
= 71.5 × = 7.15 ×
×
= 7.15 ×
(c)
((9.7 ×
) + 8.3)
= (97 + 8.3)
= 105.3 × = 1.053 ×
×
= 1.053 ×
(d)
((3.67 ×
) - 1.6)
= (36.7 - 1.6)
= 35.1 × = 3.51 ×
×
= 3.51 ×
(e)
((8.41 ×
) - 7.9)
= (84.1 - 7.9 )
= 76.2 × = 7.62 ×
×
= 7.62 ×
(f)
((1.33 ×
) - 4.9 )
= (13.3 - 4.9) = 8.4 ×
Answers
Answer:
x=2.5+sqrt(300)/4, 2.5-sqrt(300)/4
Step-by-step explanation:
1. Need to factor or can use the quadratic formula
2x^2-10x-3=0
a=2, b=-10, c=-3
[-b+-sqrt(b^2-4*a*c)]/(2*a)
[10+-sqrt(100-4*(-200)]/4
[10+- sqrt(300)]/4
x=2.5+sqrt(300)/4, 2.5-sqrt(300)/4
Answers
Answer:
the missing length is 5
Step-by-step explanation:
Since we are given similar triangles, we can simply use proportions to solve the problem:
we say that 2 is to side of length 4, the same as m is to side lengths 10. And in math terms:
Answers
Answer:
6y +52
Step-by-step explanation:
6(2y + 8) - 2(3y - 2)
Distribute
12y + 48 - 6y +4
Combine like terms
6y +52
Answers
Answer:
72 is 45% of 160.I hope this helps :D
Answers
Answer:
9
Please mark BRAINLIEST!!!!!
Step-by-step explanation:
180-(63+38)=9x-2
9x-2=79
9x=81
x=9
Final answer:
To solve for x in a triangle, you can use known values or relationships among the sides and angles of the triangle. The Pythagorean theorem can help find the hypotenuse in a right triangle. Trigonometric functions can be used to solve for x once the values are known.
Explanation:
To solve for x in a triangle, we need to have known values or relationships among the sides and angles of the triangle. The given equation 0 = tan-¹ (A₂/Ax) can help us find one such relationship. Since this is a right triangle, we can use the Pythagorean theorem (x² + y² = h²) to find the hypotenuse. Once we have known values for the sides and angles of the triangle, we can use trigonometric functions like sine, cosine, and tangent to solve for x.