Calculate angle ACD

please help​
calculate angle ACD please help​ - 1

Answers

Answer 1
Answer:

Answer:

∠ ACD = 70°

Step-by-step explanation:

The angle on the circle subtended by arc AB is half the angle at the centre subtended on the same arc, that is

∠ ACD = (1)/(2) ∠ AOB = (1)/(2) × 140° = 70°


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Isoke is solving the quadratic equation by completing the square. 10x2 + 40x – 13 = 0        10x2 + 40x = 13         A(x2 + 4x) = 13 What is the value of A?

Answers

Answer:

 A = 10

Step-by-step explanation:

We have given that : A quadratic equation 10x^2+40x-13=0

                                   another equation A(x^2+4x)=13

To find:  The value of A

Solution: Taking the quadratic equation  10x^2+40x-13=0

and try to reduce this equation in form of another equation

10x^2+40x-13=010(x^2+4x)=13

Comparing with another equation A(x^2+4x)=13

we get that 10 takes the place of A

which implies value of A = 10


I hope this helps you




10x^2+40=13


10 (x^2+4)=13



A=10

What is 6 divided by 2(1+2)

Answers

Answer:

The answer is 1

Step-by-step explanation:

Remember PEMDAS,  1+2 is 3. 2x3 is 6, then 6 divided by 6 is 1.

Answer:

1

Step-by-step explanation:

6 / 2(1 + 2)

6 / 2(3)

6 / 6 = 1

Expand (3x-4y)^3 please answer thank you

Answers

27x^3-108x^2y+144xy^2-64y^3

Answer:

Step-by-step explanation:

Solve for x. x/a+b=c

Answers

x=c×a-b because Every thing you do to 1 side you have to do to the other

According to the Fundamental Theorem of Algebra, how many roots exist for the polynomial function?f(x) = 4x5 – 3x
1 root
2 roots
4 roots
5 roots

Answers

Answer:

Option 4 is correct that is according to fundamental theroem of algebra the given polynomial function will have 5 roots

Step-by-step explanation:

The fundamental theorem of algebra says that the polynomial will have  the number of roots  equal to the degree of the polynomial.

Degree is the highest power of polynomial.

Here we have given the polynomial 4x^5-3x where degree is 5.

Hence, the given polynomial will have 5 roots.

Therefore, option 4 is correct that is 5 roots

Hello,

I say one more time in C there are 5 roots.
4x^5-3x=x(4x^4-3)\n =x(2x^2+ √(3) )(2x^2- √(3) )\n =x( √(2)x- \sqrt[4]{3} ) ( √(2)x+ \sqrt[4]{3} ) ( √(2)x- i\sqrt[4]{3} ) ( √(2)x+i \sqrt[4]{3} )

What is the value of the expression when a = 3 and b = 2?3a^3 + 2b^3
--
A. 78
B. 97
C. 135
D. 745

Please don't respond with the answer alone, I'd like to know how to work through it. :)

Answers

3a³ + 2b³ = ?

Substitute for values:

3a³ + 2b³
a = 3
3 × 3³ + 2b³

b = 2
3a³ + 2 × 2³

Full question:

3 × 3³ + 2 × 2³

3 × 3³ + 2 × 2³
3 × 27 + 2 × 2³
3 × 27 + 2 × 8
81 + 16
97

The value of the expression 3a³ + 2b³ when a = 3 and b = 2 is 97.

3 × 3³ + 2 × 2³ = 97