Which equation could generate the curve in a graph below?

Answers

Answer 1

Answer: pretty sure its the 3rd one

Answer 2

Answer: Uhh maybe 3? I think???

Related Questions

What is the mean of the data set 14, 12, 23, 15?
Can anyone help me wit this!!
B) The perimeter of the rectangle below is 42cm. Calculate thelengths of the sides by forming an equation and solving it.x-2x + 5
The fraction 24/28 In simplest form is____.12/1448/566/96/7
Please only answer if you actually know how to). Some methods for graphing equations work well with certain equations and some don't. Help Asap). Knowing which method to select based on the given equation is a valuable skill. You have learned three methods to graph equations. These methods are: • y = mx+ b, • find intercepts, • use a t-chart. A) Using the following 3 equations, answer the questions: 11x + y =4, x+y = -2, x - 2y = 18. 1) How can you determine which equations can be graphed more easily using x - and y -intercepts, rewriting in slope-intercept form, or using a table of values? 2) Which method works best for you personally? When does it not work as well?

Please help me 80% of what number is 16 What is the part?
What is the total?
What is the percent?
What is the answer?

Answers

Answer:

80 percent of 16 is 12.8 I'm sorry but that's all I know

Find the perimeter of rectangle MNOP with vertices M (-2,5), N (-2, -4), O (3, -4), and P (3,5)Part B: Square ABCD has vertices, A (-3.5, 4), B (3.5, 4), C (3.5, -4) and D (-4.5, -4. What is the area of Square ABCD?

Answers

Answer:

(-3.5,4)b

Step-by-step explanation:

Does anybody know about this I'm stuckes it's about angles

Answers

Answer:

the answer is 25 degrees

Answer:

alpha = 25°

Step-by-step explanation:

The picture indicates a rectangle.

Alpha is in a straight corner of 90 °, so...

65 + alpha = 90

subtract 65 left and right of the = sign.

65 - 65 + alpha = 90 - 65

0 + alpha = 90 - 65

alpha = 25°

F (x) = 2x^2 - 4x + 1

Answers

i don't know specifically what you are looking for but:

Direction: Opens Up

Vertex: (1, -1)

Axis of Symmetry: x = 1

and i attached the graph

Answer: x = √(((-F - 4)^2)/16 - 1/2) + (F + 4)/4 or x = (F + 4)/4 - √(((-F - 4)^2)/16 - 1/2)

Step-by-step explanation:

Solve for x:

F x = 2 x^2 - 4 x + 1

Subtract 2 x^2 - 4 x + 1 from both sides:

-2 x^2 + F x + 4 x - 1 = 0

Collect in terms of x:

-1 + x (F + 4) - 2 x^2 = 0

Divide both sides by -2:

1/2 + 1/2 x (-F - 4) + x^2 = 0

Subtract 1/2 from both sides:

1/2 x (-F - 4) + x^2 = -1/2

Add 1/16 (-F - 4)^2 to both sides:

1/16 (-F - 4)^2 + 1/2 x (-F - 4) + x^2 = 1/16 (-F - 4)^2 - 1/2

Write the left hand side as a square:

(1/4 (-F - 4) + x)^2 = 1/16 (-F - 4)^2 - 1/2

Take the square root of both sides:

1/4 (-F - 4) + x = √(1/16 (-F - 4)^2 - 1/2) or 1/4 (-F - 4) + x = -√(1/16 (-F - 4)^2 - 1/2)

Subtract 1/4 (-F - 4) from both sides:

x = √(((-F - 4)^2)/16 - 1/2) + (F + 4)/4 or 1/4 (-F - 4) + x = -√(1/16 (-F - 4)^2 - 1/2)

Subtract 1/4 (-F - 4) from both sides:

Answer: x = √(((-F - 4)^2)/16 - 1/2) + (F + 4)/4 or x = (F + 4)/4 - √(((-F - 4)^2)/16 - 1/2)

You receive a fax with six bids (in millions of dollars):2.2,1.3,1.9,1.2 2.4 and x is some number that is too blurry to read. Without knowing what x is, the median a. Is 1.9 b. Must be between 1.3 and 2.2 c. Could be any number between 1.2 and 2.4

Answers

Answer:

b. Must be between 1.3 and 2.2

Step-by-step explanation:

The formula for calculating median is :

When n(number of observations in data) is odd = $((n+1)/(2) )^(th) observation$
When n is even = $(((n)/(2))^(th)obs. + ((n)/(2) + 1)^(th) obs. )/(2)$

Since in our data n is even so we use the formula for calculating median

= $(((n)/(2))^(th)obs. + ((n)/(2) + 1)^(th) obs. )/(2)$

First arranging data in ascending order we get :

1.2, 1.3, 1.9, 2.2, 2.4 and since we know nothing about our sixth value x so we assume that it may take any position in our data.

Now there may be cases for which position is x on ;

If x is the first obs in our data then our median = $(3^(rd)obs + 4^(th)obs )/(2)$ = $(1.3+1.9)/(2)$

= 1.6

If x is between 1.2 and 1.3 then also median will be 1.6 .

If x is between 1.3 and 1.9 then median will be somewhere between 1.3 and 1.9 .
If x is between 1.9 and 2.2 then median will be somewhere between 1.9 and 2.2 .

And If x is between 2.2 and 2.4 or after 2.4 then median = $(3^(rd)obs + 4^(th)obs )/(2)$

= $(1.9+2.2)/(2)$ = 2.05 .

So from all these observations we conclude that without knowing what x median of data must be between 1.3 and 2.2 .

Final answer:

The median of a set of bids can be found by arranging them in numerical order and selecting the middle value.

Explanation:

The median is the middle value of a set of data arranged in numerical order. In this case, we have a set of six bids: 2.2, 1.3, 1.9, 1.2, 2.4, and x (blurred number). To find the median, we first need to arrange the bids in numerical order:

Since there are six bids, the middle value will be the fourth number in the ordered list. Therefore, the median is 2.2.