How many moles of calcium chloride would be produced by the reaction below when 53.2 milliliters of water are produced, if the density of water is 0.987 g/mL? Show all steps of your calculations as well as the final answer HCl + Ca(OH) 2 → H2O + CaCl2
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Mass of water = .987 * 53.2 = 52.5084 g
Mole of water = 52.5084g/ 18= 2.917 mol
Mole of CaCl2= 2.917 mol / 2 = 1.458
This answer will definitely help you. Regards!
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It’s easier to think of it this way- the number of zeros will be the exponent
Answer: 1 x
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calcium
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B. contain carbon, hydrogen, and oxygen respectively in a 1:2:1 ratio.
C. are produced by living organisms.
D. dissolve in water.
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Organic molecules always contain carbon. They need not always be produced by living organisms and do not necessarily dissolve in water. Moreover, they are not restricted by the composition or ratio of other elements.
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The answer to this question pertains to organic molecules. Organic molecules are a type of molecules that always contain carbon. This is represented by option A. This is not restricted by the presence of certain elements or the ratio in which they exist such as hydrogen and oxygen (1:2:1 ratio as mentioned in option B). The notion that organic molecules are produced only by living organisms (option C) is not entirely accurate either. Although they are predominantly found in and produced by living organisms, they can also be synthesized in a laboratory setup. Option D states that organic molecules always dissolve in water, which is not the case, as many organic compounds are
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Answer : The number of oxygen atoms present on reactant side are, 4
Explanation :
Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.
Decomposition reaction : It is defined as the reaction in which the larger molecule decomposes to give two or more smaller molecules as a product.
The given balanced chemical reaction is,
From the balanced chemical reaction we conclude that, there 4 atoms of hydrogen and 2 atoms of oxygen present on both reactant side and product side.
Hence, the number of oxygen atoms present on reactant side are, 4