What is the process of preparing a person to perform strenuous work and to recover from that work as quickly as possible?

Answers

Answer 1

Answer: The process of preparing a person to perform strenuous work and to recover from that work as quickly as possible is called training, I bet. Such warm up exercises as like stretching and other should lead person to the recovery. Hope it will help.

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Which term best describes the important pieces of information that scientists gather and record during an experiment?

Answers

Data. Anything a scientist measures or records for an experiment is considered data, very important information.

A racecar is equipped with a computer that records the reading on its speedometer every second during a race. If you graph this data, what will be the best choice for the dependent variable?

Answers

Since the device is a speedometer, the data it read is the speed of the racecar. Data recording involving time usually uses time as the independent variable. It was also said in the problem that it records the speed every second which shows that the time interval is constant. This means that only other data, the car's speed, is the dependent variable.

"The radius of a sphere is increased by 25%. Find the percentage increase in surface area."

Answers

Answer:

Therefore, when the radius of a sphere is increased by 25%, the surface area increases by approximately 56.25%.

Explanation:

The surface area of a sphere is given by the formula: Surface Area = 4πr^2 where r is the radius of the sphere.

To find the percentage increase in surface area when the radius is increased by 25%, we can follow these steps:

1. Let's assume the initial radius of the sphere is r.

2. If the radius is increased by 25%, the new radius will be 1.25r (since 25% is equivalent to multiplying by 1.25).

3. Now, we can calculate the initial surface area (A1) using the formula: A1 = 4πr^2. 4.

Similarly, we can calculate the new surface area (A2) using the formula: A2 = 4π(1.25r)^2 = 4π(1.5625r^2) = 6.25πr^2.

5. The percentage increase in surface area can be calculated as follows: Percentage Increase = ((A2 - A1) / A1) * 100

6. Plugging in the values we obtained earlier,

we have: Percentage Increase = ((6.25πr^2 - 4πr^2) / 4πr^2) * 100 = ((2.25πr^2) / 4πr^2) * 100 = 56.25%

A dog looking for its bone in the yard, first heads 160.0° for 14.0 m and then turns and heads west for 8.50 m.a. What is the magnitude of the dog's displacement?
b. What is the direction of the dog's displacement?