Light of wavelength 550 nm falls on a slit that is 3.50 x 10^-3 mm wide. How far from the central . maximum will the first diffraction maximum fringe be if the screen is 10.0 m away?

Answers

Answer 1

Answer: λ $= 550 * 10^(-9)\] m. D = 3.50*10^-6 m.$
$d = 10 m. m = 1 2x = ?$

Then you need to find x when n=1
or
$sinθ=λ/w=524x10^-9/0.0033=1.59x10^-4$
≈θ for θ<<1 , so θ= $1.59x10^-4 radians$

Then you can find rhe distance of bright fringe from the center: $d= θD=1.59x10^-4x10m ≈ 1.6 mm$

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Answers

The correct answer is a

Evidence gathered from publicly observable behavior is known as _________ evidence.

Answers

Empirical because it is what you need to know the source of knowledge gather by observation or experimentation.

A concave mirror has a radius of curvature of 10 cm. Find the location an height of the image if the distance of the object is 8cm and the height of the object is 1.5 cm, using a scaled ray diagram

Answers

R=10
F=R/2
F=10/2=5
F=-5(CONCAVE MIRROR)
U=-8(CONCAVE MIRROR)
HEIGHT OF OBJECT=1.5
V=?
HEIGHT OF IMAGE=?
I/F=1/U+1/V
-I/5=-1/8-1/V
-1/V=-1/5+1/8
-1/V=-8+5/40
-1/V=-3/40
1/V=3/40
V=40/3

HEIGHT OF IMAGE/HEIGHT OF OBJECT =-V/U
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=-20/8
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What is the kinetic energy of a 108 kg object that is moving with a speed of 11.1 m/s ?

Answers

Answer:

6,653.34 J

Explanation:

Kinetic energy can be found using the following formula.

$KE=(1)/(2) mv^2$

where m is the mass in kilograms and v is the velocity in m/s.

The object is 108 kilograms and is moving at a speed of 11.1 m/s. Therefore, the mass is 108 kg and the velocity is 11.1 m/s.

m=108 kg

v=11.1 m/s

Substitute these values into the formula.

$KE=(1)/(2)*108*11.1^2$

Evaluate the exponent first. 11.1^2 is the same as 11.1*1.11, which is equal to 123.21

$KE=(1)/(2) *108*123.21$

Multiply 108 and 123.21

$KE=(1)/(2)*13306.68$

Multiply 1/2 and 13306.68

$KE=6653.34$

The kinetic energy of the object is 6,653.34 Joules (kg m2/s^2)

Which type of wave can be transmitted through the vacuum of space ?

Answers

Answer: The correct answer is electromagnetic wave.

Explanation:

Electromagnetic wave is wave in which the electric field and the magnetic field are perpendicular to each other. Both fields are directed to the direction of the propagation of the wave.

Electromagnetic wave is transverse in nature. It travels with the speed of the light. It does not need medium to travel. It can be transmitted through the vacuum of space.

Therefore, the correct answer is electromagnetic wave.

How many types of quarks are there?
a. 2
b. 4
c. 6
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Answers

There are 6 types of quarks.

Answer: C. 6

The are 6 types of quarks: up, down, strange, charm, top, and bottom.
The answer:

C.6

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