A girl that has a mass of 30 kg is hanging from a bar motionless. Determine the following forces. If no force exists, enter 0. (use 10m/s2 for gravity) Weight Newtons
Applied force Newtons
Frictional Force Newtons
Normal Force Newtons
Tension Force
Net Force Newtons

Answers

Answer 1
Answer:

Final answer:

The weight of the girl is 300 N. The applied force, frictional force, and normal force are all zero. The tension force in the bar is 300 N, and the net force is zero.

Explanation:

The weight of the girl can be calculated using the formula:

Weight = mass × gravity

where mass = 30 kg and gravity = 10 m/s2. Therefore, Weight = 30 kg × 10 m/s2 = 300 N.

Since the girl is motionless, the net force acting on her is zero. In this case, the tension force in the bar equals the weight of the girl, which is 300 N. The other forces (applied force, frictional force, and normal force) are also zero since the girl is not moving.

Therefore, the forces are:

  • Weight: 300 N
  • Applied force: 0 N
  • Frictional force: 0 N
  • Normal force: 0 N
  • Tension force: 300 N
  • Net force: 0 N

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Explanation :

The gravity of the Sun causes the planets to move in a circular path. This is because of Newton's first law of motion.

According to Newton's first law, the body will remain at rest or in uniform motion untill external unbalanced force acts.

There are two forces acting on planets i.e. gravitational force and inertia of their orbits. So, form Newton's first law the planets keeps on moving in a circular path.

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A blue-light photon has a wavelength of4.80 × 10^−7 meter. What is the energy of the
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(1) 1.86 × 10^22 J (3) 4.14 × 10^−19 J
(2) 1.44 × 10^2 J (4) 3.18 × 10^−26 J

Answers

Energy = hc/λ, where h is planck's constant, c is the speed of light and λ is the wavelength.

Energy = (6.626 x 10^-34*3.00 x 10^8)/(4.80 × 10^−7)= 4.14*10^-19 J, which is 3.

Normally, when solving these equations, don't forget to check the units are correct (eg. wavelength is in meters) and dont forget to include the units in the calculation.






Taking into account the definition of photon, energy of a photon, wavelength, frecuency and propagation speed, the correct answer is the option (3): The energy of a photon with aa wavelength of 4.80×10⁻⁷ meter is 4.14×10⁻¹⁹ J.

What is a photon and energy of a photon

You have to know that electromagnetic radiation carries energy, which can be absorbed or emitted. To explain the processes of emission and absorption, Plank and Einstein proposed that the energy of radiation is composed of indivisible units (quanta). In each elemental process only a quantum of light can be emitted or absorbed. Each of these quanta was called a "photon".

The exchanges of energy between matter and radiation take place not continuously, but by discrete and indivisible quantities or quanta of energy. The quantum of energy is proportional to the frequency of radiation.

The relationship between the amount of energy (E) transported by the photon and its frequency (f) is determined by the following expression, where the energy of a photon is obtained by multiplying Planck's constant h by the frequency f of electromagnetic radiation:

E=h×f

What is wavelength, frecuency and propagation speed

Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.

The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f×λ

All electromagnetic waves propagate in a vacuum at a constant speed of 3×10⁸ m/s, the speed of light.

What is the energy of the photon in this case

In this case, you know:

  • h=  6.63*10⁻³⁴ Js
  • f= v÷λ where v= 3×10⁸ m/s and  λ=4.80×10⁻⁷ m

Replacing in the definition of energy of a photon:

E=h× (v÷λ)

E= 6.63×10⁻³⁴ Js× (3×10⁸ m/s ÷4.80×10⁻⁷ m)

Solving:

E= 4.14×10⁻¹⁹ J

Finally, the correct answer is the option (3): The energy of a photon with aa wavelength of 4.80×10⁻⁷ meter is 4.14×10⁻¹⁹ J.

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