Which component measures the potential difference across a branch in a circuit? A.switch. B.resistor. C.ammeter. D.voltmeter.

Answers

Answer 1
Answer:

Answer: The correct answer is option (D).

Explanation:

Voltmeter is a device which measures the the voltage applied across the circuit. It is an electrical instrument used to measure the electric potential between the two points in an electric circuit.

Where as:

A switch is the device which used to connect or disconnect the circuit.

Resistor is a device which opposes the flow of current is an electric circuit.

An ammeter the is an electrical device which measures the amount of current in flowing in amperes in an electrical circuit

Hence,the correct answer is option (D).

Answer 2
Answer: (D)Voltmeter measures the potential difference

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Do electromagnetic waves travel through a medium

Answers

No, they actually travel through the vacuum of outer space, but it also requires the absence of a material sedium.

What is the motion of a body when only the force of gravity is acting on it

Answers

When only the force of gravity acts on an object,
the situation is called "free fall".

The motion is uniformly accelerated.  The object falls
straight toward the center of the other object in whose
gravity it shares, and its speed increases at a constant
rate. 

When this happens on or near the surface of the Earth,
the rate is (9.8 meters per second greater) for each
second of falling.

True free-fall is never observed in daily life.  Whenever
we see an object falling, it is always falling through air,
which counteracts the force of gravity to a greater or
lesser degree, depending on the object's size, shape,
weight, surface texture, and speed through the air.

To neutralize gastric juices in your stomach antacids contain

Answers

To neutralize gastric juices in your stomach antacids contain basic chemicals. The acid in your stomach has a lower pH value. To neutralize this and reach a pH of 7, the antacid must contain a base.

Explain why plastic comb rubbed with wool attracts pieces of paper​

Answers

Answer:

Static electricity

Explanation:

Opposite charges attract each other.

What is the chance of a light car safely rounding an unbanked. Curve on an icy road as compared to that of a heavy car: worse, the same, or better? Assume that both cars have the same speed and are equipped with identical tires. Account for your answer.

Answers

Answer:)

Both cars will move in the Same way

Explanation:

Moving on an unbanked icy road, the cars will have friction which will keep them from slipping on the icy road. This friction here is called Centripetal Force. The friction force due to which the tires roll and do not slip is the static friction μsN, (μs= coefficient of static friction , N= Normal Force which is equal to the weight of the car/body, so N=mg).

Now from above description, the centripetal force( F_(c)) becomes,

                         F_(c) =f=μsN         ,       (N=mg)

so ,                    F_(c) =μs(mg)

As we know the formula of centripetal force is

                        F_(c)= mv^(2) /r

Putting the value of F_(c) from above

                        μs(mg) = mv^(2) /r

cutting the 'm' from both sides, we get

                        μs(g) = v^(2) /r

                        μs = v^(2) /rg

we see from the derivation that there is no effect of mass on the cars, so in case of both cars having same speed and same tires, they will act in the same way resulting no effect of their masses on them

Answer:

Both cars will move in the Same way

Explanation:

A object of mass 33 is dropped from a height of 85 meters. Calculate the average power developed by the object in falling through this distance.Take g as 9.81 m/s^2

give the answer in watts to three significant figures

Answers

Power  =  Work done  /  Time taken.

Work done =  mgh
Mass, m = 33kg    ( Am presuming it is 33 kg).
h =  85 m.
Work done =  33 * 9.81* 85 =  27517.05  J.

Time taken.
Since object was dropped from height, it fell under gravity.
Using    H =  ut  +  (1/2) * gt^2.              u = 0.
               H =  1/2 gt^2.
               t  =   (2H/g) ^ (1/2)
               t  =  (2*85/9.81) ^ 0.5 =  4.1628 s.

Power  =    27517.05 / 4.1628 = 6610.23 Watts.
             =  6610 W  to  3 S. f.