PHYSICS HIGH SCHOOL

Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p. a. 1/2
b. 2 times
c. 1/4
d. 4 times

Answers

Answer 1
Answer:

Answer : The correct option is, (d) 4 times

Solution :

According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.

Formula used :

F=k_e(q_1q_2)/(r^2)

where,

F = electrostatic force of attraction or repulsion

k_e = Coulomb's constant

q_1 and q_2 are the charges

r = distance between two charges

First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'

F_(sq)=k_e(qq)/(1^2)=k_e* q^2       ..........(1)

Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.

F_(sp)=k_e(qq)/(2^2)=k_e(q^2)/(4)     ...........(2)

Equation equation 1 and 2, we get

(F_(sq))/(F_(sp))=(1)/(4)

F_(sq)=4* F_(sp)

Therefore, the force exerted between S and q is 4 times the force exerted between S and p.

Answer 2
Answer:

I believe the answer is "4 times".

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