PHYSICS HIGH SCHOOL

Two students are studying for a Science Test. On the table, they had a glass of water and identical cell phones. Both of their phones had run out of battery, therefore they were both charging in the same wall outlet. One student’s charging cord was 3ft and the other student’s charging cord was 9ft. which of the phones charged the fastest using Ohm’s Law. Cite evidence to support your theory.

Answers

Answer 1

Answer:

Answer:

The student with the 3ft charger

Explanation:

Because the electricity from the 3ft charger has a shorter distance to mooves than the 9ft one

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two cylinders p and q are made of copper the height of p is twice the height of q . the diameter of p is half the diameter of q

Answers

Answer:

Explanation:

Cylinder P is taller than cylinder Q. In fact, it's twice as tall. So if cylinder Q is, let's say, 10 inches tall, cylinder P would be 20 inches tall.

Cylinder P is also wider, but not by a lot. It's only half as wide as cylinder Q. So if cylinder Q has a width of 10 inches, cylinder P would have a width of 5 inches.

Now, let's talk about the insides of these cylinders, how much stuff they can hold. If we filled them up with something, like water, the bigger one (cylinder P) can hold twice as much as the smaller one (cylinder Q).

So, cylinder P can hold more stuff because it's both taller and a little wider than cylinder Q.

Which of the following colors has the highest photon energy?A. Blue
B. Green
C. Yellow
D. Red
Explain your reasoning.

Answers

The energy of a photon is directly proportional to its frequency.
That means it's inversely proportional to its wavelength.

The end of the visible spectrum the highest frequency /shortest
wavelength is the blue end.

Green because in a physical form a photon IS green

Cliff divers at Acapulco jump into the sea from a cliff $30.7 m$ high. At the level of the sea, a rock sticks out a horizontal distance of $9.34 m$.The acceleration of gravity is $9.8 m / s ^{2}$.
With what minimum horizontal velocity must the cliff divers leave the top of the cliff if they are to miss the rock?
Answer in units of $m / s$.

Answers

Answer:

To solve this problem, we can use the kinematic equation for horizontal motion, which relates the initial velocity ($v_{0}$), final velocity ($v_{f}$), acceleration ($a$), and displacement ($d$) of an object:

$d = v_{0} t + \frac{1}{2}at^{2}$

In this case, we want to find the minimum initial velocity ($v_{0}$) that the divers must have to clear the rock. To do this, we can assume that the divers just graze the rock at the start of their trajectory, so the displacement in the horizontal direction is equal to the distance from the cliff to the rock ($d = 9.34 m$). We also know that the acceleration in the horizontal direction is zero, so the only force acting on the divers is gravity in the vertical direction, which gives an acceleration of $a = 9.8 m/s^{2}$.

At the instant the divers leave the cliff, they have zero horizontal velocity, so $v_{0} = 0$. We can use the equation above to solve for the time it takes for the divers to fall from the cliff to the level of the rock:

$d = \frac{1}{2}at^{2} \Rightarrow t = \sqrt{\frac{2d}{a}}$

Plugging in the numbers, we get:

$t = \sqrt{\frac{2(9.34 m)}{9.8 m/s^{2}}} \approx 1.44 s$

Since the cliff divers want to clear the rock, they need to travel a horizontal distance of at least $9.34 m$ during this time. We can use the equation for horizontal motion again to solve for the minimum initial velocity:

$d = v_{0}t \Rightarrow v_{0} = \frac{d}{t} = \frac{9.34 m}{1.44 s} \approx 6.49 m/s$

Therefore, the minimum horizontal velocity that the cliff divers must have to clear the rock is approximately $6.49 m/s$.

the jamaican bobsled team hit the brakes on their sled so that it decelerates at a uniform rate of 0.43 m/s, how long does it take to stop if it travels 85 m before coming to rest

Answers

here's a cheap trick
it would take the same time to accelerate from rest to top speed
as it would take to decelerate from top speed to zero
so
instead of
d = Vi t + 1/2 a t^2 where Vi is positive and a is negative
we'll use
Vi = 0 and a is positive
giving
85 = 0 + 1/2 (0.43) t^2 = 0.215 t^2
t^2 = 395.345
t = 19.88s or 20. s to 2 sig figs

or we ccould find Vi from
Vf*2 = Vi^2 + 2 a d
0 = Vi^2 + 2 (0.43) 85
Vi^2 = 71.4
Vi = 8.45m/s
then
85 = 8.45 t + 1/2 (-0.43) t^2
85 = 8.45 t - 0.215 t^2
0.215 t^2 - 8.45 + 85 = 0
t = 19.65s or 20. s to 2 s.f.(minor difference arises from rounding Vi)
or another cheap trick
when a is constant
Vavg = (Vf + Vi) /2 = 8.45/2 = 4.225
and
d = Vavg t
85 = 4.225 t
t = 20.12 or 20. s to 2 s.f. (minor differences from intermidiate roundings)

anyway you choose you get 20. s

suppose that a particle at rest with mass m decays into a photon and another particle with mass m/2 , which recoilds in a direction opposite to the photon. Using the conservation of energy and momentum find the momentum of the recoiling particle

Answers

Answer:

$p_r=(h)/(\lambda)$

Explanation:

To find the momentum of the recoiling particle you can use the momentum formula for a photon:

$p=(h)/(\lambda)$

before the decay the momentum is zero. Hence, after the decay the momentum of the photon plus the momentum of the recoiling particle must be zero:

$p_a=p_b\n\n(h)/(\lambda)-(m)/(2)v=0\n\np_r=(m)/(2)v=(h)/(\lambda)$

where pr is the momentum of the recoiling particle.

The acceleration due to gravity on the surface of Jupiter is about 2.5 times the acceleration due to gravity on Earth’s surface. What would be the weight of a space probe on the surface of Jupiter?A.2.5 times lighter than on Earth
B.6.25 times heavier than on Earth
C.2.5 times heavier than on Earth
D.6.25 times lighter than on Earth