MATHEMATICS HIGH SCHOOL

30 = X-8
One step equation

Answers

Answer 1
Answer:

Answer:

38

Step-by-step explanation:

30 = X-8

+8    +8

38=x

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Adam tried to compute the average of his 7 test scores. He mistakenly divided the correct sum of all of his test scores by 6, which yielded 84. What is Adam’s correct average test score?

Answers

Adam got the sum of his grades right, but he divided that correct figure by 6, getting 84 Before that division, the sum of his grades must have been 84 * 6, or 504. He should have divided 504 by 7, getting 72. Answer: His correct average test score is 72.

Steven went to an arcade for his brothers birthday. His parents gave him $45.00 to spend. He purchased $14.75 in food and drinks, and put the rest of the money on a gaming card to spend at the arcade. Each game in the arcade cost $1.50.Part A: Write a linear inequality to represent how many games, , Steven can play in the arcade.
Part B: What is the maximum number of games that Steven can play in the arcade?

Answers

Answer:

20 games

Step-by-step explanation:

Part A:

45 = 14.75 + 1.50g

Part B:

45 - 14.75 = 30.25

30.25/1.5 = 20.1666666666667

20 is the maximum number of games he can play.

The lateral area of a cone is 500 pi cm.^2. The radius is 50 cm. Find the slant height to the nearest tentha. 10 cm
b. 9.1 cm
c. 14.2 cm
d. 11.2 cm

Answers

The answer is a. 10 cm

The lateral area (LA) of the cone can be expressed as:
LA = π * r * l
r - the radius of the cone
l - slant height of the cone 

It is given:
l = ?
r = 50 cm
LA = 500π cm²

Let's replace these in the equation for the lateral area of the cone:
500π = π * 50 * l
500π = 50π * l
⇒ l = 500π/50π
    l = 10 cm

If the work required to stretch a spring 2 ft beyond its natural length is 12 ft-lb, how much work is needed to stretch it 9 in. beyond its natural length?

Answers

The amount of work required to stretch 9 inches beyond the natural length will be 4.5 ft-lb

Given data:

To determine the work required to stretch the spring 9 inches beyond its natural length, use the concept of Hooke's Law.

Hooke's Law states that the force required to stretch or compress a spring is directly proportional to the displacement from its equilibrium position.

Given that stretching the spring by 2 ft requires 12 ft-lb of work, determine the constant of proportionality.

The constant of proportionality (k) represents the stiffness of the spring and can be calculated using the formula:

k = work / displacement

k = 12 ft-lb / 2 ft

k = 6 lb/ft

Now, calculate the work required to stretch the spring 9 inches (0.75 ft) beyond its natural length using the same constant of proportionality:

work = k * displacement

work = 6 lb/ft * 0.75 ft

work = 4.5 ft-lb

Hence, it would require 4.5 ft-lb of work to stretch the spring 9 inches beyond its natural length.

To learn more about Hooke's law, refer:

brainly.com/question/30379950

#SPJ12

3×4 what is the answer

Answers

Answer:

12

Step-by-step explanation:

3 + 3 + 3 + 3 = 12

Brainliest??? Plzzz!!!.....

If Jim =5x - 8 and LM =2x -6,which expression represents JL?

Answers

Answer:

The correct answer is A) 3x - 2

Step-by-step explanation:

In order to find this, take the value of JM and subtract the value of LM. This will give you JL.

JM - LM = JL

5x - 8 - (2x - 6) = JL

5x - 8 - 2x + 6 = JL

3x - 2 = JL
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