Which rule should be followed when naming binary acids
Answers
Acids are divided into two groups: Binary and Oxyacids. NAMING BINARY ACIDS: The name of the binary acid consists of two words. The first word has three parts: the “hydro” prefix the root of the nonmetal element the “ic” ending The second word is always “acid” Examples: HCl = hydro chlor ic acid = hydrochloric acid HBr = hydro brom ic acid = hydrobromic acid HF = hydro fluor ic acid = hydrofluoric acid 2. NAMING OXYACIDS: These are more difficult to name because these acids have hydrogen, a nonmetal, and may have varying numbers of oxygen atoms. For example, H2SO5, H2SO4, H2SO3, and H2SO2 are all acids. How do we name them? To begin, we need a point of reference. Our reference point is this: The “ate” ions (sulfate, nitrate, etc) make the “ic” acids (sulfuric acid, nitric acid) Examples: SO4 2- = sulfate ion H2SO4 = sulfuric acid NO3 - = nitrate ion HNO3 = nitric acid Once we have our point of reference, the acid with one more oxygen than the -ic acid is called the per-_________-ic acid. The acid with one less oxygen then the -ic acid is called the ___________-ous acid. If the acid has one less oxygen than the -ous acid, it is called the hypo-____________-ous acid. Examples: H2SO5 = persulfuric acid HNO4 = pernitric acid H2SO4 = sulfuric acid HNO3 = nitric acid H2SO3 = sulfurous acid HNO2 = nitrous acid H2SO2 = hyposulfurous acid HNO = hyponitrous acid The KEY:
Related Questions
Why can't alpha particles penetrate deeply into solids?
Limestone is primarily a crystal form of caco 3 . How many moles of oxygen are in a 1.25 mol sample of caco 3 ? Only include the numerical value in your answer. Do not include units.
Choose all of the examples where there would be an increase in the electric or magnetic force
Calculate the decrease in temperarure when 2.00 L at 20.0 degrees celsius is compressed to 1.00 L.
(2) grams of NaCl per liter of solution
(3) moles of NaCl per liter of water
(4) moles of NaCl per liter of solution
Answers
Answer:
The correct option is (4)
Explanation:
Molarity (M) is generally defined as the number of moles of a solute per liter of the solution.
The formula for molarity (from the definition above) is
M = number of moles (n) ÷ volume (in liters or dm³)
The unit for molarity is mol/L or mol/dm³
From the above, it can be deduced that the molarity of an aqueous solution of common salt (NaCl) is the number of moles of NaCl per liter of the salt solution.
Answer (4)
hope this helps!
Answers
Answer: The alpha particle is released after alpha radiation.
Explanation:
Alpha decay is defined as the decay process in which a heavier nucleus decays into a lighter nuclei. This decay process releases alpha particle which is also known as helium nucleus.
The general alpha decay reaction is given as:
The particle released will carry a mass of 4 units and carries a charge of +2 units.
Hence, the alpha particle is released after alpha radiation.
B. Kidney
C. Colorectal
D. Stomach
Answers
Studies suggest that consumption of large amounts of red and processed meats, along with low intake of fiber and phytochemicals, may be responsible for colorectal.
NOT:
A. Liver
B. Kidney
D. Stomach
Answers
Alloys are used because of their strength, resistance to corrosion, appealing appearance and ability to be easily formed.
What is corrosion resistance?
Corrosion resistance: Alloys are resistant to corrosion and rust, which makes them an ideal material for the outer casing of ballpoint pens.
The pen's exterior can be exposed to air and moisture, but the alloy will not corrode or rust, ensuring that the pen remains in good condition for a longer period.
Durability: Alloys are typically stronger and more durable than pure metals, which makes them ideal for use in ballpoint pens.
Ballpoint pens undergo a lot of wear and tear during regular use, such as being dropped, knocked around, or exposed to high temperatures. Using an alloy ensures that the pen will not bend, break, or become deformed easily, which prolongs the life of the pen.
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Answers
Density is defined as the ratio of mass to volume of a substance.
The density of water is generally known to be 1.0 g/mL. Substances that are less dense than water will float on water while substances that are denser than water will sink in water.
We have to calculate the density of the block material in units of g/ml.
Volume of the block = = 19.66 mL
Mass of the block = 350 lb = 158757 g
Density of the block =
Density of block =
= 8075.13 g/mL
Hence the block material will sink in water.
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density of water is approximately 1.0 g/mL
block of material
volume of 1.2 x 10^4 in^3
and weighing 350 lb
Required:
Which will float
Solution:
D = M/V where D is density, M is mass and V is volume
convert 1.2 x 10^4 in^3 into mL
1.2 x 10^4 in^3 (16.39 mL/ 1 in3) = 196,980 mL
convert 350 lb into grams
350 lb (454 grams/1 lb) = 158,900 grams
D = M/V = 158,900 grams/ 196,980 mL
D = 0.807 g/mL
The block will float in water because it is less dense than water
C6H12O6 + 6O2 → 6CO2 + 6H2O
Which compounds are the reactants and which are the products?
A.
reactants: C6H12O6 + 6O2
products: 6CO2 + 6H2O
B.
reactants: 6CO2 + 6H2O
products: C6H12O6 + 6O2
C.
reactants: 6CO2 + C6H12O6
products: 6H2O + 6O2
D.
reactants: 6H2O + 6O26CO2 + C6H12O6
products: 6CO2 + C6H12O6
Answers
Reactants on left (see on the arrow), products on right.
Final answer:
For the given chemical equation illustrating cellular respiration, the reactants comprise glucose (C6H12O6) and oxygen (6O2), and the products are carbon dioxide (6CO2) and water (6H2O). This symbolizes how in living cells, glucose and oxygen are transformed into energy, leading to the release of carbon dioxide and water as byproducts.
Explanation:
In the given chemical equation for cellular respiration, C6H12O6 (glucose) and 6O2 (oxygen) are the reactants and 6CO2 (carbon dioxide) and 6H2O (water) are the products.
This represents the process in living cells where glucose and oxygen are transformed into energy, releasing carbon dioxide and water as byproducts. Therefore, the correct answer is option A: Reactants are C6H12O6 + 6O2 and products are 6CO2 + 6H2O.
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