6 At STP, which element is a good conductor of electricity?(1) chlorine (3) silver(2) iodine (4) sulfur

Answers

Answer 1

Answer: For an object to conduct electricity it should have free or delocalised electrons that are free to pass the charge and hence take part in conducting electricity.
From the given choices
Chlorine is a halogen existing as a diatomic gas. Iodine too is a halogen and 2 Iodine atoms held together by covalent bond. Cl - Cl bonds and I-I bonds are covalent bonds. the outer electrons of Cl and I take part in covalent bonds therefore they are fixed and not free to move about. therefore no free electrons to conduct electricity.
Sulfur is a solid that too is held together by covalent bonds so it does not have free electrons to conduct electricity.

Silver is a metal and a general property of metals are their ability to conduct electricity.
metal structure are metal ions tightly packed together. when the metal atoms are tightly packed their valence electrons are removed and delocalised. Positively charged metal ions are embedded in a sea of delocalised electrons.
therefore there are delocalised electrons that can conduct electricity

answer is 3) silver

Answer 2

Answer: It would be Silver because it is metal.

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Which of these pairs of elements have the same number of valence electrons?hydrogen (H) and helium (He)
sodium (Na) and potassium (K)
carbon (C) and oxygen (O)
boron (B) and beryllium (Be)

Answers

The correct answer is the second option; sodium (Na) and potassium (K.)
Both sodium and potassium have the same number of valence electrons.

Answer:

The correct answer is the second option; sodium (Na) and potassium (K.)

Both sodium and potassium have the same number of valence electrons.

Explanation:

The volume of 6.00M HCl needed to make 319 ml of 6.80M HCl

Answers

Answer : The volume of 6.00 M HCl needed are, 361.5 ml

Solution :

According to the neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of HCl solution = 6.00 M

$V_1$ = volume of HCl solution = ?

$M_2$ = molarity of another HCl solution = 6.80 M

$V_2$ = volume of another HCl solution = 319 ml

Now put all the given values in the above law, we get the volume of HCl solution.

$(6.00M)* V_1=(6.80M)* (319ml)$

$V_1=361.5ml$

Therefore, the volume of 6.00 M HCl needed are, 361.5 ml

The mole number of the solute after dilution is constant. So the mole number of 319 ml of 6.80 M HCl is 6.80*319*10^(-3)=2.17 mol. So the volume of 6.00 M HCl needed is 2.17/6.00=0.362 L=362 ml.

What point were the authors of the Declaration trying to make in the Preamble?

HELP.

Answers

Answer:

To explain why they are revolting against the king

Explanation:

. The density of gold is 19.32 g/mL. A U.S. $5.00 gold coin has a diameter of 1.62 cm and a thickness of 0.085 cm. The price of gold is currently $53.90 per gram. What is the value of the gold in the coin. V = π r2 h.

Answers

Answer:

$182 is the value of the gold in the coin

Explanation:

Diameter is 2r, the ratio of the coin is = 1.62cm / 2 = 0.81cm

Following the formula of the volume of the coin:

V = π r² h

V = π*(0.81cm)²*0.085cm

V = 0.172cm³ = mL

As the density of the gold is 19.32g/mL, the mass of 0.1752mL of gold is:

0.1752mL * (19.32g / mL) =

3.385g is the mass of the coin

As the price of the gold is $53.90 / g, the value of the gold in the coin is:

3.385g * ($53.90 / g) =

$182 is the value of the gold in the coin

Final answer:

To find the value of the gold in the coin, calculate its volume using the formula for the volume of a cylinder. The value of gold in the coin is $185.37.

Explanation:

To calculate the value of gold in the coin, we need to find its volume first using the formula for volume of a cylinder:

$V = \pi r^2h.$

The radius (r) of the coin is half its diameter, so it is 0.81 cm. The height (h) is 0.085 cm. Plugging in these values, we can find the volume of the coin. Next, we calculate the mass of the gold in the coin using its density and the volume we just calculated. Finally, we multiply the mass by the price per gram of gold to find the value of the gold in the coin.

The volume of the coin is:

$V = \pi (0.81 cm)2(0.085 cm)$

= 0.178 cm3.

The mass of the gold is:

m = density x volume

= 19.32 x 0.178

= 3.443 g.

The value of the gold in the coin is the value as -

= mass x price per gram

= 3.443 g x $53.90/g

= $185.37.

Learn more about value of gold in a coin here:

brainly.com/question/33661518

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Which statement best describes the effect of low ionization energies and low electronegativities on metallic bonding? a. The valence electrons are easily delocalized.
b. The valence electrons stay in a single orbital.
c. The valence electrons break free of the crystals.
d. The valence electrons move closer to the nuclei.

Answers

Answer: The valence electrons are easily delocalized. As the ionization energy increases the energy required to remove the valance electrons from the atom also increases. So the valance electrons move closer to the nuclei. But low ionization energy makes the atom to lose valance electrons much easier.

Answer: THE answer is A

Explanation: took the exam

if you had a sample of beryllium, would all the atoms be identical? what about a sample of lithium? explain your answers.

Answers

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