Choose the correct mixed number for the quotient. 38 ÷ 5 = 7 R3

A)7 5/3

B)7 3/38

C)9 4/85

D)7 3/5

Answers

Answer 1

Answer: That would be D. 7 3/5 because 7 is the answer but 3 isn't greater than 5 so it cant make a whole so it makes a fraction of 7 3/5.

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The image point of A after a translation left 1 uint and down 2 units is the point B (1,-4). Determine the coordinates of the pre-image point A

Answers

Answer:0,2

Step-by-step explanation:

Select the best answer 7 x (-3) x (-2)^2=

Answers

7(-3)(-2)²

-21(-2)²

-21(4)

= -84

I hope that's help !

-4^2=?

PLEASE ANSWER QUICKLY!!!!

Answers

Answer:

Step-by-step explanation:

-16

Answer: -16

Step-by-step explanation:

-4 x -4 = -16

squaring is basically just multiplying the # by itself.

Find a • b.

a = 4i + 3j, b = -4i + 4j

Answers

The required dotproduct of the given vector is given as -4.

Given that,
a = 4i + 3j, b = -4i + 4j
a • b is to be determined.

What is dot products of vector?

The dot × of twovectors is described as the sum of the products of the relevant directionalvector.

Here,
a.b = (4i + 3j).(-4i + 4j)
a.b = 4×-4 (i.i) + 3×4 (j.j) + 4×4 (i.j) + 3×-4(i.j)
a.b = -16 + 12
a.b = -4 (since i.j or j.i for dot product gives zero.)

Thus, the required dotproduct of the given vector is given as -4.

Learn more about dot product here:
brainly.com/question/29097076
#SPJ2

Hello,

I suppose a and b are vectors
and i and j unit's vectors

$\vec{i}*\vec{i}=1\n \vec{j}*\vec{j}=1\n \vec{i}*\vec{j}=0\n$
$\vec{a}\ .\ \vec{b}=(4\vec{i}\ +3 \vec{j}).(-4\vec{i}\ +4 \vec{j})\n =-16-3*4*0+4*4*0+12=-4$

Which function has a minimum and is transformed to the right and down from the parent function, f(x) = x2?g(x) = –9(x2 + 2x + 1) – 7
g(x) = 4(x2 – 6x + 9) + 1
g(x) = –3(x2 – 8x + 16) – 6
g(x) = 8(x2 – 6x + 9) – 5

Answers

Answer:

g(x) = 8(x2 – 6x + 9) – 5

Step-by-step explanation:

A function with a form (x - a)^2 - b where a and b are some constants are a transformation to the right and down from the parent function, f(x) = x^2. Then, option:

g(x) = 4(x2 – 6x + 9) + 1 = 4(x - 3)^2 + 1

is discarded

The vertex form of a quadratic equation is f(x) = c*(x - h)^2 + k, where c, h and k are all constant, and point (h,k) is the vertex of the quadratic function. If c > 0, then the vertex is a minimum and if c < 0 then the vertex is a maximum. Therefore, options:

g(x) = –9(x2 + 2x + 1) – 7 = -9(x + 1)^2 - 7

g(x) = –3(x2 – 8x + 16) – 6 = -3(x - 4)^2 - 6

are dicarded

In consequence, the correct option is:

g(x) = 8(x2 – 6x + 9) – 5 = 8(x - 3)^2 - 5

Answer:

The last choice is the one you want

Step-by-step explanation:

First of all, a parabola has a minimum value if it is a positive parabola, one that opens upward. The first and the third parabolas are negative so they open upside down. That leaves us with choices 2 and 4. We find the side to side and up or down movement by finishing the completion of the square that has already been started for us. Do this by factoring what's inside the parenthesis into a perfect square binomial.

The second one factored becomes:

$g(x)=4(x-3)^2+1$

which reflects a shift to the right 3 and up 1. Not what we are asked to find.

The fourth one factored becomes:

$g(x)=8(x-3)^2-5$

which reflects a shift to the right 3 and down 5. That's what we want!

Joe will go to the swimming pool on 20 different days this month. • a one-day pass to the pool is $2.25. • a monthly pass to the pool is $30.00. how much money will joe save by buying a monthly pass