Is 1/8 bigger than 1/2
Answers
Related Questions
If y is 5 when x is 2.5 and y varies directly with x, find y when x is 10.57.512.520
CAN SOMEONE PLEASE HELP ME!!!????One 1700 lb load of feed mixture contains 25% corn and 40% bran; the rest is roughage. How many pounds of corn should be added to a load of feed mixture to make the mixture 40% corn?
jimmy has a 60 gallon limit if he already has 1/4 of it how much more does he need to fill up the entire 60 gallons of gas? why?
What is the slope of the line which passes through (−2, 0) and (0, 4)? (5 points) 2 Undefined −2 0
Answers
Answer:
$172.5 hope this helps
Step-by-step explanation:
O Table 1
O Table 2
O Table 3
O Table 4
Answers
Answer:
Table 2
Step-by-step explanation:
Answer:
O Table 4 is the table describes a linear function that has a slope of 2.
Step-by-step explanation:
find Jeremy’s age, j, if he is the younger man?
(1) j^2 + 2 = 783 (3) j^2 + 2j = 783
(2) j^2 - 2 = 783 (4) j^2 - 2j = 783
Answers
j - Jeremy's age
j+2 - Sam's age
The product of their ages is 783.
The answer is (3).
1,3,5,7,9...
since jeremy iis younger, he is 2 less than sam
j
s=j+2
sj=783
in terms of j
(j+2)j=783
distribute
j^2+2j=783
the answe ris the 3rd equation
b. Express the temperature of the roast 30 minutes after being put in the oven in functional notation, and then calculate its value.
c. By how much did the temperature of the roast increase during the first 10 minutes of cooking?
d. By how much did the temperature of the roast increase from the first hour to 10 minutes after the first hour of cooking?
Answers
Answer:
Step-by-step explanation:
a. We are not given enough information to determine the temperature of the refrigerator.
b. We can express the temperature of the roast 30 minutes after being put in the oven as R(30). Its value depends on the specific function R(t) given in the problem.
c. To find the increase in temperature during the first 10 minutes of cooking, we need to find the difference between the temperature of the roast after 10 minutes and the temperature of the roast when it was put in the oven. This is given by:
R(10) - R(0)
d. To find the increase in temperature from the first hour to 10 minutes after the first hour of cooking, we need to find the difference between the temperature of the roast at 1 hour and 10 minutes and the temperature of the roast at 1 hour. This is given by:
R(70) - R(60)
Final answer:
The temperature of the refrigerator is the initial temperature of the roast. The temperature of the roast 30 minutes after being put in the oven can be expressed as R(30), but its value cannot be determined without a specific function. The temperature increase during specific time intervals can be calculated by finding the difference between the temperatures at the respective times.
Explanation:
a. To find the temperature of the refrigerator, we need to use the given information. Since the roast was in the refrigerator for several days before being placed in the oven, we can assume that the temperature of the refrigerator matches the temperature of the roast initially, which is denoted as R(0). Therefore, the temperature of the refrigerator is R(0).
b. Expressing the temperature of the roast 30 minutes after being put in the oven in functional notation is R(30). To calculate its value, we need the specific function or equation that relates the temperature to time. Without this information, we cannot determine the exact numerical value of R(30).
c. To determine the temperature increase during the first 10 minutes of cooking, we need the temperature difference between the initial temperature of the roast (R(0)) and the temperature after 10 minutes of cooking (R(10)). The increase is given by R(10) - R(0).
d. To find the temperature increase from the first hour to 10 minutes after the first hour of cooking, we need the temperature at the start of the first hour (R(60)) and the temperature at 10 minutes after the first hour (R(60 + 10)). The increase is given by R(60 + 10) - R(60).
Learn more about temperature of the roast here:
#SPJ2
Driver B had a mean race time of 3.96 seconds and a standard deviation of 0.12 seconds.
Driver C had a mean race time of 3.99 seconds and a standard deviation of 0.19 seconds.
Answers
Answer: driver a
Step-by-step explanation: because the time was 4.01
Answers
Answer: 13 cookies
Step-by-step explanation: 13 divided by 2 is 6 with a remainder of 1. 13 divided by 3 is 4 with a remainder of 1. 13 divided by 4 is 3 with a remainder of 1.
Answer:
B
Step-by-step explanation:
Divide each option by 4.
13/4= 3.25
.25 x 4 =1(whole cookie)