MATHEMATICS HIGH SCHOOL

State the triangle congruence theorem that can be used to prove triangles congruent.SSS
SAS
AAS
ASA
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Cannot Be Determined
State the triangle congruence theorem that can be used to - 1

Answers

Answer 1
Answer:

Answer:

ASA

Step-by-step explanation:

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Find the solution of cos^2xsinx-3sinx=0

Answers

\cos^2 x\sin x-3\sin x=0\n\n \sin x\cdot (\cos^2 x-3)=0\n\n \begin{array}{rcl} \sin x=0&~\text{ or }~&\cos^2 x - 3=0\n\n \sin x=0&~\text{ or }~&\cos^2 x=3\n\n \sin x=0&~\text{ or }~&\cos x=\pm √(3) \end{array}


Since |\cos x|\le 1, the 2nd equation has no solutions for x. So

\sin x=0\n\n x=k\pi~~~~\text{where }k\text{ is an integer.}


Solution: S=\{x:~x=k\pi,~k\in\mathbb{Z}\}

A display of gift boxes has 1 box in the top row, 3 boxes in the next row, 5 boxes in the next row, and so on. there are 7 rows in all. how many gift boxes are in the display?

Answers

There would be 49 gifts on display because 1+3+5+7+9+11+13=49

If sin θ = 0.57 then sin (π-θ)=?

Answers

In trigonometry laws, there's a equation to solve this problem : 
sin (a-b) = sin(a) . cos(b) - sin (b) . cos(a),

so by assuming that a = π, b = θ, so the equation will be like this..
sin (π-θ) = sin(π) . cos(θ) - sin (θ) . cos(π), 
             = 0 . cos(θ) - sin(θ) . (-1) 
             = sin(θ) = 0.57

Hope this will help you :)

The range of which function is (2,infinity)?y = 2x?
y = 2(5x)?
y = 5x +2?
y = 5x + 2?

Answers

For a function: y = 5^x
range is ( 0 , + ∞ )
And we have: y = 5^x + 2 , which is translated 2 units up.
So the range is ( 2, + ∞ ) or ( 2, infinity ).
Answer:
D ) y = 5^x + 2

The exponential function that has range of (2, infinity) is given by:

y = 5^x + 2

What is an exponential function?

It is modeled by:

y = ab^x + c

In which:

  • a is the initial value.
  • b is the rate of change.
  • The range is (c, infinity).

Hence, the exponential function that has range of (2, infinity) is given by:

y = 5^x + 2

More can be learned about exponential functions at brainly.com/question/25537936

In which one of the following pairs of angles are the angles always equal to each other

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Although you have not presented any choices for this question, I will proceed on discussing what the possible answer might be depending on the description you gave. The answer to this mathematical question would be vertical angles. This is because vertical angles are always equal to each other.

What is if g(x,y,z) = x + y and S is the first octant portion of the plane 2x + 3y + z = 6 ?

Answers

The question asks for the value of I=\int\int_Sx+y\textrm{ }dS where S=\{(x,y,z)\mid2x+3z+y=6,x\ge0,y\ge0,z\ge0\}.

First let's look at what that surface looks like.

Letting y=z=0 yields x=3
Letting x=z=0 yields y=2
Letting x=y=0 yields z=6

Therefore S is the area of the triangle defined by the three points (3,0,0),(0,2,0),(0,0,6).

We can thus reformulate the integral as I=\int_(z=0)^6\int_(x=0)^(6-z)x+ydxdz.

By definition on the plane y=\frac{6-2x-z}3 thus I=\int_(z=0)^6\int_(x=0)^(6-z)x+\frac{6-2x-z}3dxdz=\int_(z=0)^6\int_(x=0)^(6-z)2+\frac x3-\frac z3 dxdz

I=\int_(z=0)^6\left[2x+\frac{x^2}6-\frac{zx}3\right]_(x=0)^(6-z)dz=\int_(z=0)^62(6-z)+\frac{(6-z)^2}6-\frac{z(6-z)}3\right]dz

I=\int_(z=0)^6\frac{z^2}2-6z+18=\left[\frac{z^ 3}6-3z^2+18z\right]_(z=0)^6=36-108+108

Hence \boxed{I=\int\int_Sx+y\textrm{ }dS=36}
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