Solve the following system of equations by the substitution method.8x = 2y + 5

3x = y + 7

What is the solution set?

{(-41/2, -9/2)}
{(-9/2, -41/2)}
Ø

Answers

Answer 1
Answer: 8x = 2y + 5
3x = y + 7

We will use the second equation to substitute in the first one. Here's how to do it:
3x = y + 7
y = 3x - 7 (now substitute this in the first equation)

8x = 2y + 5
8x = 2(3x - 7) + 5
8x = 6x - 14 + 5
8x = 6x - 9
6x - 9 = 8x
6x - 8x = 9
-2x = 9
x = -9/2 (this is the first coordinate, now we need to find y)

We use the second equation again:
3x = y + 7
y + 7 = 3x
y + 7 = 3(-9/2)
y + 7 = -27/2
y = -27/2 - 7
y = -27/2 - 14/2
y = -41/2 (this is the second coordinate)

This means that the solution set is the second option: {(-9/2, -41/2)}
Answer 2
Answer:

Answer:

{(-9/2, -41/2)}

Step-by-step explanation:


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question is ,four children saved £29 to go on a coach. They each saved the same amount. How much did each saved

Answers

If they saved £29 all together, and if each of them saved the same amount,
then each saved £29/4 = £7.25 or £7 and 25p.

(Before decimalization in 1971, £7.25 would have been £7 and 5s .)
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If one liter of water was poured equally into 1,000 small cubes, then each cube would contain:A.1 mL
B.1 cm³
C.1 m³
D.1 mm
select all that apply

Answers

your answer is 1 ml that's a tiny cube lol

I believe it’s A and B

prove algebraically that the straight line with the equation x=2y+5 is a tangent of the circle with the equation x^2+y^2=5

Answers

Answer:

Step-by-step explanation:

To prove the straight line is tangent to the circle:

  1. substitute the straight line into the circle equation
  2. discriminant of the new equation has to be equals to 0

(1)

substitute x = 2y + 5 into x² + y² = 5

x² + y² = 5

(2y + 5)² + y² = 5

4y² + 20y + 25 + y² = 5

5y² + 20y + 20 = 0

y² + 4y + 4 = 0

(2)

discriminant of y² + 4y + 4 = 0 has to be equals to 0

\boxed{D=b^2-4ac}

D = 4² - 4(1)(4)

D = 0

∴ Proven

What is the period of the graph of the equation y=3cos2x

Answers

the\ period\ cosx\ is\ 2\pi\n\nthe\ period\ 3cosx\ is\ 2\pi\n\nthe\ period\ 3cos2x\ is\ 2\pi:2=\pi\leftarrow Answer

Hopefully y'all can help me on this

Answers

Find the area of one triangle ( half base times height ) and times it by the height of the prism. (12x9=) 108m. 108m is your answer.

Write an equation in point-slope form for the line through the given point with the given slope. (9,-1); m=4/3. I need help!

Answers

(y-y_(1) )=m(x-x_(1))

m= (4)/(3)

y_(1)=-1

x_(1) = 9

(y-(-1) )= (4)/(3) (x-(9))

(y+1)= (4)/(3) (x-9)

y - y1 = m(x - x1)

y - (-1) = (4)/(3) (x - 9)

y + 1 = (4x - 36)/(3)

y + 1 = (4x)/(3) - 12

y = (4x)/(3) - 13