Would the following errors increase, decrease, or have no effect on the calculated moles of gas collected in the experiment? Explain your answers in complete sentences.a) The measured mass of the magnesium was smaller than the true mass.
b) The actual temperature of the hydrogen gas is less than room temperature.
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b. when gas was cooler than its surroundings its density would be greater and the volume would appear to be smaller. This is because the gas molecules are very active and when heated they will expand.
so they both bound increase the calculated moles of gas collected in the experiment
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2) Ester
3) Aldehyde
4) Amino Acid
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Answer:
base
Explanation:
carbonic acid - H2CO3 - is a weak acid. Therefore, HCO3 itself is its conjugate base. The Na(sodium) ion is neutral.
This means that NaHCO3 is a base. (a weak one)
Answers
Answer: molecules
Explanation:
To calculate the moles, we use the equation:
For
Given mass= 165 g
Molar mass of = 44 g/mol
Putting values in above equation, we get:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number of particles.
1 mole of contains =
molecules of
Thus 3.75 moles contains =
molecules of
Thus there will be molecules of
The molar mass of CO2 is 44 grams per mole.
165 grams / 44 grams per mole of CO2 = 3.75 moles CO2
Using Avogadro’s law where 1 mole of substance equals 6.023 x 10^23 molecules
3.75 moles CO2 (6.023 x 10^23 molecules /mole) = 2.26 x 10^24 molecules CO2
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The total mass of the solution is 15 g (Na₂CO₃) + 235 g (H₂O) = 250 g (solution).
Now, let's calculate the mass percent of Na₂CO₃:
Mass percent of Na₂CO₃ = (mass of Na₂CO₃ / total mass of solution) * 100
= (15 g / 250 g) * 100
= 6%
Therefore, the mass percent of Na₂CO₃ in the solution is 6%.
Final answer:
The mass percent of a solution is calculated by dividing the mass of the solute by the total mass of the solution and multiplying by 100%. In this case, the solute is Na₂CO₃ and the solvent is H₂O. The calculation yields a mass percent of 6% for Na₂CO₃ in the solution.
Explanation:
To calculate the mass percent of a solution, we need the mass of the solute and the mass of the solution (which is the sum of the masses of the solute and the solvent). In your given solution, you have 15 g of Na₂CO₃ (solute) and 235 g of H₂O (solvent). Therefore, the total mass of the solution is 15 g (Na₂CO₃) + 235 g (H₂O) = 250 g.
Now, to find the mass percent of Na₂CO₃ in the solution, we use the following formula:
Mass percent = (mass of solute / total mass of solution) × 100%
Substitute the known values into the formula, we get:
Mass percent = (15 g / 250 g) × 100% = 6%
So, the mass percentage of Na₂CO₃ in the H₂O solution is 6%.
Learn more about mass percent here:
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Energy = mCΔT
Energy = 59.7 (0.231) (100-25)
Energy = 1034.30 J
The amount of heat energy needed to raise the temperature of 59.7g of cadmium from 25°C to 100°C is 1,034.3J.
How to calculate amount of energy?
The amount of heat energy needed to raise a temperature can be calculated using the following expression;
Q = mc∆T
Where;
- Q = amount of energy released or absorbed
- m = mass of substance
- c = specific heat capacity
- ∆T = change in temperature
According to this question, 59.7g of cadmium is needed to be raised from 25°C to 100°C. The amount of heat needed can be calculated as follows:
Q = 59.7 × 0.231 × (100 - 25)
Q = 1,034.3J
Learn more about energy at: brainly.com/question/33447128
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