A force of 450 N accelerates a box across a frictionless surface at a rate of 15 m/s2. Find the mass of the box?A) 30 N

B) 30 kg

C) 6,750 N

D) 6,750 kg

Answers

Answer 1

Answer: Second Law of Newton: Net force equals mass times acceleration

F = m*a => m = F/a

m = 450N / 15 m/s^2 = 30 kg

Answer: option B) 30 kg

Answer 2

Answer: It would be: m= F/a = 450 N / 15 m/s^2 = 30 Kg

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How to covert ma into amphere?

Answers

1 ampere = 1,000 milliamperes

1 A = 1,000 mA

To calculate the number of Amperes, divide the number of milliamperes by 1,000.

which is heavier a one ton box or a one metric ton box? How many pounds heavier is one than the other?

Answers

1 metric ton is bigger than 1 ton. 1 metric ton = 1.102311 tons or 2,204.622 pounds. on ton only = 2,000 pounds.

You travel 20.0 mph for 0.500 hour, 40.0 mph for 1.00 hour, 30.0 mph for 0.500 hour, and 50.0 mph for 2.00 hours. What is the total distance traveled?

Answers

Speed is $(distance)/(time)$ , so because you already know the time(.5 + 1 + .5 + 2 = 4 hours), you want to find the distance traveled.
$(Speed)/(time) = ((distance)/(time))/(time)=(distance)/((time)/(time))=distance$
So you set it up like this:
$(20mph)/(.5\ hour)= 10 miles \n (40mph)/(1\ hour)= 40 miles\n (30mph)/(.5\ hour)= 15miles\n (50mph)/(2\ hours)=100miles \n Add\ them:\n 10+40+15+100=165miles$
You traveled 165 miles total.

A _______ satellite records reflected wavelengths from Earth's surface.

Answers

A visible satellite images records reflected wavelengths from Earth's surface.

Visible satellite images record visible light coming from the sun that is reflected by clouds, land, oceans or snow and ice.
There is a big difference between visible and infrared images since visible images record reflected light rather then emitted radiation.

Generally , people water their plants with 100% H2o--- no solutes added. What sort of environment does this create around the roots of the plant? (Hypotonic, hypertonic or isotonic ) EXPLAIN!!

Answers

This is difficult to explain, but it's hypotonic. HypERtonic is where there is where the cells shrivel up because there is more solute (salt is an example of a solute) on the outside, so the water rushes outward towards it and shrivels the cell. Plants like lots of water so they like to be hypotonic, and since you're adding pure H2O, there is no solute being added, so the solute is in the cell, causing the water to rush in. Isotonic is equal throughout the solution.

Problem 5. A bullet leaves a rifle with a velocity of 452 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.93 m. Determine the acceleration of the bullet.

Answers

Answer:

1.1 x 10⁵m/s²

Explanation:

Given parameters:

Velocity = 452m/s

distance = 0.93m

Unknown:

Acceleration of the bullet = ?

Solution:

To solve this problem, we use one of the kinematics equation which is given below:

V² = U² + 2aS

V is the final velocity

U is the initial velocity = 0m/s

a is the unknown acceleration

S is the distance traveled

So;

452² = 0² + (2 x a x 0.93)

204304 = 1.86a

a = 1.1 x 10⁵m/s²

Final answer:

The acceleration of the bullet in the gun barrel can be calculated using the kinematic equation for motion. By substituying the given values into the equation, we find the acceleration to be approximately 1.095 x 10^5 m/s^2.

Explanation:

The subject of this question is Physics, specifically a topic under mechanics known as kinematics. The problem given can be solved using kinematic equations which are used to describe the motion of an object without considering the forces that cause it to move. In this case, the final velocity (vf) of the bullet is given as 452 m/s, the initial velocity (vi) is assumed to be 0 as it starts from rest, and the distance (d) is given as 0.93 m. We are asked to determine the value of acceleration (a).

Using the kinematic equation vf2 = vi2 + 2ad and substituting the given values, we get (452 m/s)2 = 0 + 2*a*0.93 m. We can rearrange to solve for acceleration to get: a = (452 m/s)2 / (2*0.93 m) = 109523.66 m/s2.

So, the acceleration of the bullet in the gun barrel is approximately 1.095 x 105 m/s2.