Claire and her partner, Grace, are throwing for the javelin event as a team. Claire threw the javelin 42 5/8 feet and Grace threw it 39 3/5 feet. How far did the team throw the javelin? Show your work.

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

Claire................42 5/8

grace.............39 5/3

the team throw 42 5/8 + 39 5/3=

lets add first the 42+39=81

5/8+5/3  common denominator is 24

15/24+40/24=55/24=2 7/24

81+ 2 7/24=83 7/24

Answer 2
Answer:

Answer:

Claire - 42 5/8

grace - 39 5/3

the team throw 42 5/8 + 39 5/3=

lets add first the 42+39=81

5/8+5/3  common denominator is 24

15/24+40/24=55/24=2 7/24

81+ 2 7/24=83 7/24

Step-by-step explanation:

The person above is correct. Have a nice day :]


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if a boy grows 5 inches, he will be one-half as tall as his sister. His sister is 68 inches tall. How tall is the boy?

Answers

If the boy grows another 5 inches, he will be 1/2 as tall as his sister. HIs sister is 68 inch tall

Let sister = g, and boy = b

2b + 5 = g

g = 68

Plug in 68 for g

2b + 5 = 68

Isolate the b. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

first, subtract 5 from both sdies

2b + 5 (-5) = 68 (-5)

2b = 68 - 5

2b = 63

Isolate the b. Divide 2 from both sides

2b/2 = 63/2

b = 63/2

b = 31.5

The boy is 31.5 inches tall

hope this helps

Answer:

The height of boy is 29 inches.

Step-by-step explanation:

Given : If a boy grows 5 inches, he will be one-half as tall as his sister. His sister is 68 inches tall.

To find : How tall is the boy?  

Solution :

Let x be the boy's height and y be his sister's height.

We have given, His sister is 68 inches tall i.e. y=68 inches

Now,  If a boy grows 5 inches i.e. x+5

then he will be one-half as tall as his sister i.e. x+5=(1)/(2)y

or  y=2x+10

We know, y=68 substitute in above equation

68=2x+10

2x=58

x=(58)/(2)

x=29

Therefore, The height of boy is 29 inches.

Mr. Martin is giving a math test next period. The test, which is worth 100 points, has 29 problems. Each problem is worth either 5 points or 2 points. Write a system of equations that can be used to find how many problems of each point value are on the test.

Answers

x - the number of 5 points worth problems
y - the number of 2 points worth problems

The test has 29 problems.
x+y=29

The test is worth 100 points.
5x+2y=100

The system of equations:
x+y=29 \n5x+2y=100

The solution:
x+y=29 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |* (-2) \n5x+2y=100 \n \n-2x-2y=-58 \n\underline{5x+2y=100 \ \ \ \ \ } \n3x=42 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |/ 3 \nx=14 \n \nx+y=29 \n14+y=29 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |-14 \ny=15

There are 14 problems worth 5 points and 15 problems worth 2 points.

Final answer:

The system of equations to find the number of 5-point and 2-point problems on the math test is x + y = 29 and 5x + 2y = 100, where x and y are the numbers of 5-point and 2-point problems respectively.

Explanation:

The question posed involves setting up a system of equations to determine how many of each type of problem are on a math test. There are two types of problems: those worth 5 points and those worth 2 points, with the test having a total of 29 problems and worth 100 points in all. To solve this, we can define two variables, let's say x represents the number of problems worth 5 points and y represents the number of problems worth 2 points.



We can set up the following system of equations:




  1.  
  2. x + y = 29 (This represents the total number of problems.)

  3.  
  4. 5x + 2y = 100 (This represents the total points for the test.)



Solving this system will give the number of 5-point problems and 2-point problems on the test.

Learn more about System of Equations here:

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Write the equation of the line, given the y- and x-intercepts. x-intercept (–6, 0), y-intercept (0, –8)

Answers

neverminding for a second that they're intercepts at all, they're points on the line, so


\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad(\stackrel{x_2}{0}~,~\stackrel{y_2}{-8})\n\n\n slope = m\implies\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-8-0}{0-(-6)}\implies \cfrac{-8-0}{0+6}\implies \cfrac{-8}{6}\implies -\cfrac{4}{3}\n\n\n \begin{array}{|c|ll}\cline{1-1}\textit{point-slope form}\n\cline{1-1}\ny-y_1=m(x-x_1)\n\n\cline{1-1}\end{array}\implies y-0=-\cfrac{4}{3}[x-(-6)]\n\n\ny=-\cfrac{4}{3}(x+6)\implies y=-\cfrac{4}{3}x-8

Graph the second equation to find the solution of the system of equations.y = –x,

y = 2x + 6

What is the point of intersection

Answers

Answer: (-2,2)

Explanation: I plugged it into a graphing calc!

Answer:

So the point of intersection would be -x=2x+6

and then we'll subtract 2x on both sides and get -3x=6

this will result in x=-2

Then we'll substitute that into y=-x, so y=2

Therefore the point of intersection is (-2,2)

Hope I helped, have a nice day :)

The base length of a triangle is 8 feet and the height is 4 feet. What is the area of the triangle?4 square feet
8 square feet
16 square feet
32 square feet

Answers

8x4=32
32 divided by 2 = 16
the answer is 16 square feet

hope this helps :)

Answer:

16 square feet

Step-by-step explanation:

I got it right on my FLVS test :D

F is the mid point of EG . If EF = 5x and EG = 7x + 5, what is EG?

Answers

7.5 is the answer sur

Final answer:

To find EG, we equate EF to EG and solve for x. Substituting the value of x back into EG gives us a final answer of 22.5.

Explanation:

In the given question, F is the midpoint of EG. We are given that EF = 5x and EG = 7x + 5. To find the value of EG, we need to equate EF to EG and solve for x.

Given: EF = EG = 5x

Substituting the values, we get: 5x = 7x + 5

Simplifying the equation: 2x = 5

Dividing both sides by 2, we find: x = 2.5

Now, substituting the value of x back into EG, we get: EG = 7(2.5) + 5 = 17.5 + 5 = 22.5

Therefore, EG is equal to 22.5

Learn more about EG here:

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