How many liters of oxygen gas can be produced if 28.7 grams of water decomposes at 294 Kelvin and 0.986 atmospheres? Show all of the work used to solve this problem. . . 2 H2O (l) --->2 H2 (g) + O2 (g)

Answers

Answer 1

Answer: 2 H₂O (l) → 2 H₂ (g) + O₂ (g)

Molar mass water = 1.01 x 2 + 16.00 = 18.02 g/mol

Number of mol water decomposed = 28.7 g H₂O x [1 mol / 18.02g] = 1.59 mol H₂O

From the balanced equation 2 mol H₂O decomposes to 2 mol H₂ and 1 mol O₂

so the mole ratio water : oxygen = 2 : 1

and number of mol O₂ produced = ½ x 1.59 = 0.796 mol O₂

The ideal gas law is PV = nRT

so V = nRT/P

P = 0.986 atm

V = ?

n = 0.796

R = 0.0821 L atm K⁻¹ mol⁻¹

T = 294K

V = 0.796 x 0.0821 x 294 / 0.986

V = 19.5 L

So 19.5 L O₂ gas are produced

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What kind of bond would a metal and a nonmetal typically make?A. An Ionic bond
B. A Metallic bond
C. A Double bond
D. A Covalent bond

Answers

A) ionic bond.......

The answer is A. An ionic bond.

When stressed, mica breaks into thin sheets. This describes mica's _____. luster color streak cleavage

Answers

Answer : The correct option is, Cleavage.

Explanation :

Mica : It is silicate mineral and also known as sheet silicate because they form in different layers.

Cleavage : It is a type of mineral properties. It describes how a crystal breaks when stress apply to the crystal and breaks into a particular plane.

If the mica breaks due to stress and breaks into thin sheet, that means the mineral has cleavage.

Therefore, the correct answer is, Cleavage.

Answer:

Cleavage

Explanation:

If you make an electromagnet using a battery circuit and a steel nail, how can you increase its magnetic strength? A. replace the nail with a copper rod B. wrap more coils of wire around the nail C. use a longer nail D. remove the plastic insulation from the wire coil

Answers

Answer: The correct answer is "wrap more coils of wire around the nail".

Explanation:

Electromagnet: When the current passes through iron core wounded by the coils then it will get magnetized. It is not a permanent magnet.

It will loose its magnetism when the current does not flow in it.

The poles of the electromagnet can be changed. They are not fixed.

In the electromagnet, the strength of the magnetism can be increased or decreased by increasing the number of turns in the coil and by increasing the current.

In the given problem, If you make an electromagnet using a battery circuit and a steel nail, the magnetic strength can be increased by wrapping more coils of wire around the nails.

Therefore, the correct option is (B).

we can increase the strength of an electromagnet by wrapping more coils of wire around the nail.

If the formic acid were replaced with a strong acid such as HCI at the same concentration (2.0 M). how would that change the volume needed to reach the equivalence point? (A) The change would reduce the amount, as the acid now fully dissociates. (B) The change would reduce the amount, because the base will be more strongly attracted to the acid. (C) The change would increase the amount, because the reaction will now go to completion instead of equilibrium. (D) Changing the strength of the acid will not change the volume needed to reach equivalence.

Answers

answer for my di0ck s!ut

What is the alpha decay of Radon-198?

Answers

The alpha decay of Radon-198 produces alpha particle and ¹⁹⁴₈₄Po.

What is alpha decay?

Alpha decay is a type of radioactive disintegration in which some unstable atomic nuclei spontaneously expel an alpha particle to dissipate excess energy.

Alpha decay of Radon-198 is shown as:

¹⁹⁸₈₆Rn → ⁴₂He + ¹⁹⁴₈₄Po

In the above decay from the parent nuclei, daughter nuclei (¹⁹⁴₈₄Po) and alpha particle (⁴₂He) is produced.

Hence daughter nuclei of the alpha decay of Radon-198 is ¹⁹⁴₈₄Po.

To know more about alpha decay, visit the below link:
brainly.com/question/13512293

#SPJ2

86198Rn => 24He + 84194Po

The radon is shown on the left, and the alpha particle, which is a helium nucleus, is shown of the right with the polonium.

When two intermediate chemical equations are combined, the same substance that appears in the same phase can be canceled out, provided thatA) it is a reactant in one intermediate reaction and a catalyst in the other reaction.
B) it is a product in one intermediate reaction and a catalyst in the other reaction.
C) it is a reactant in one intermediate reaction and a product in the other reaction.
D) it is a reactant in both of the intermediate reactions.

Answers

Answer: Option (C) is the correct option.

Explanation:

When two intermediate chemical equations are combined, the same substance that appears in the same phase can be canceled out, provided that it is a reactant in one intermediate reaction and a product in the other reaction.

For example,

$2Al(s) + 2KOH(aq) + 6H_(2)O\rightarrow 2KAl(OH)_(4)(aq)+ 3H_(2)(g)$ ....(1)

$2KAl(OH)_(4)(aq) + 4H_(2)SO_(4)(aq) + 6H_(2)O(l)\rightarrow 2KAl(SO_(4))_(2)(aq)+ 12H_(2)O(s)$ .........(2)

Cancelling the common species in both the equations as follows.

$2Al(s) + 2KOH(aq) + 6H_(2)O\rightarrow \not{2KAl(OH)_(4)(aq)}+ 3H_(2)(g)$

$\not{2KAl(OH)_(4)(aq)}+ 4H_(2)SO_(4)(aq) + 6H_(2)O(l)\rightarrow 2KAl(SO_(4))_(2)(aq)+ 12H_(2)O(s)$

Therefore, on addition we get the equation as follows.

$2Al(s)+ 2KOH(aq) + 4H_(2)SO_(4)(aq) + 22H_(2)O(l)\rightarrow 3H_(2)(g)+ 2KAl(SO_(4))_(2) + 12H_(2)O(s)$

The right answer for the question that is being asked and shown above is that: "C) it is a reactant in one intermediate reaction and a product in the other reaction." When two intermediate chemical equations are combined, the same substance that appears in the same phase can be canceled out, provided that it is a reactant in one intermediate reaction and a product in the other reaction.

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