Sophia's Diner sold 80 milkshakes last week. 90% of the milkshakes had whipped cream on top. How many milkshakes with whipped cream were sold?

Answers

Answer 1

Answer: 80 x 90/100 = 72

Therefore there were 72 milkshakes with whipped cream that were sold.

Answer 2

Answer: you need to convert the percentage into a decimal to get your answer...

80 x .9 = 72

hope that helps :)

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A video game was originally priced at $20.it is on sale for 20% off.How much did you pay for the game?

Answers

20+ 20(0.2)
20+ 4
24 dollars

How do u simplify these radicals???

Answers

1. √48 → √16 * √3  =  4√3

3. √12 → √4 * √3 = 2√3

7. √125  → √25 * √5 = 5√5

8. √20  →  √4 *  √5 = 2√5

9.  √18  →  √9 *  √2 = 3√2

10. √32  →  √16 *  √2 = 4√2

11.  √50  →  √25 *  √2 = 5√2

12.  √27  →  √9 * √3 = 3√3

The start time is 11:00 and the Elapsed time is 4 hours 5 minutes so what is the End time?

Answers

In 24 hour time: 15:05
In 12 hour time: 3:05

The end time is 3:05. Since it's 11:00, and 4 hours and 5 minutes have passed, just add 4:05 to 11:00. Because there are 12 hours in a day, we go from 11:00 to 12:00 to 1:00 to 2:00 to 3:00 when we add 4 hours.

11:00 + 4:05 = 3:05

Hope this helps!

Mark spent half of his weekly allowance on candy to earn more money his parents let him weed the garden for four dollars what is his weekly allowance if he ended with $11?

Answers

his allowance is $14

to find this you:

11-4=7

7*2= 14

The 11 is what he had the four is what he was given extra and the multiplied by two is because he spent half of his money at the candy store

Before he got 11$ he had 7$ as he got 4$ by weeding the garden.

in the question, he spent half his weekly allowance on candy then got 4$ that means half of his weekly allowance is seven hence is weekly allowance is 2 times seven which is 14$.

Hope this helps

Q(x)=4x^2-1 find Q(-7)

Answers

$q( - 7) = 4x {}^(2) - 1$
so
$4( - 7) {}^(2) - 1$
195

$Solution, \mathrm{Isolate}\:x\:\mathrm{for}\:If\left(I,\:x\right)Q\left(x\right)=4x^2-1:\quad x=(√(f\left(I,\:x\right)Q\left(x\right)I+1))/(2),\:x=-(√(f\left(I,\:x\right)Q\left(x\right)I+1))/(2)$

$Steps: If\left(I,\:x\right)Q\left(x\right)=4x^2-1$

$\mathrm{Switch\:sides}, 4x^2-1=If\left(I,\:x\right)Q\left(x\right)$

$\mathrm{Add\:}1\mathrm{\:to\:both\:sides}, 4x^2-1+1=If\left(I,\:x\right)Q\left(x\right)+1$

$\mathrm{Simplify}, 4x^2=If\left(I,\:x\right)Q\left(x\right)+1$

$\mathrm{Divide\:both\:sides\:by\:}4, (4x^2)/(4)=(If\left(I,\:x\right)Q\left(x\right))/(4)+(1)/(4)$

$\mathrm{Simplify}, x^2=(f\left(I,\:x\right)Q\left(x\right)I+1)/(4)$

$\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=√(f\left(a\right)),\:\:-√(f\left(a\right)), x=\sqrt{(f\left(I,\:x\right)Q\left(x\right)I+1)/(4)},\:x=-\sqrt{(f\left(I,\:x\right)Q\left(x\right)I+1)/(4)},\sqrt{(f\left(I,\:x\right)Q\left(x\right)I+1)/(4)}=(√(f\left(I,\:x\right)Q\left(x\right)I+1))/(2),-\sqrt{(f\left(I,\:x\right)Q\left(x\right)I+1)/(4)}=-(√(f\left(I,\:x\right)Q\left(x\right)I+1))/(2)$

The correct answer is $x=(√(f\left(I,\:x\right)Q\left(x\right)I+1))/(2),\:x=-(√(f\left(I,\:x\right)Q\left(x\right)I+1))/(2)$

C-9.5÷1.9=-10 what does c equal

Answers

c=-15 because first I divided -9.5 and 1.9 and I got -5;
So -15 - (-5) turns into -15 + 5
= -10

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