CAN SOMEONE DO OR LOOK UP THE PIE CHART FOR THIS ANSWER PLS AND I WILL MARK YOU BRAINLIEST BUT PLSSS HELP MEEEE!!!
CAN SOMEONE DO OR LOOK UP THE PIE CHART FOR - 1

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Answer 1
Answer:

Answer:

I highly recommened you use ggl charts.

Explanation:

It's free. ALL YOU NEED IS AN GGL ACCOUNT. You can also choose many types of graph you want.


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Develop a program that asks the user to enter a capital for a U.S. state. Upon receiving the user input, the program reports whether the user input is correct. For this application, the 50 states and their capitals are stored in a two-dimensional array in order by state name. Display the current contents of the array then use a bubble sort to sort the content by capital. Next, prompt the user to enter answers for all the state capitals and then display the total correct count. The user's answer is not case-sensitive.

Answers

Answer:try redoing everything step by step and see if that solves it

Explanation:

How is a WAN different from a LAN

Answers

They make it easier for computers to connect to one another. WANs provide more options for communication than LAN networks, which are more constrained and limited in scope.

How are LANs and WANs different from one another?

A local area network, or LAN, is a network of computers created within a restricted area, like a home, business, or group of buildings. On the other hand, a wide-area network (WAN) is a computer network that spans a large geographic area. Users can transport data more quickly across LANs than they can via WANs, which have a significantly slower data transmission rate.

What distinguishes LAN and WLAN from one another?

LANs are straightforward networks that are used to link computers and other gadgets in a constrained space, such as a home, business, or campus. WLANs are entirely wireless in comparison to traditional LANs, which connect the devices using Ethernet cables. WLANs

To know more about LAN visit:-

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Assume hosts A and B are each connected to a switch Svia 100-Mbps links. The propagation delay on each link is 25μs. The switch Sis a store-and-forward device and it requires a delay of 35μs to process a packet after is has received the last bit in the packet. Calculate the total time required to transmit 40,000 bits from Ato B in the following scenarios. (The total time is measured from the start of the transmission of the first bit at A, until the last bit is received at B. We always assume that links are bi-directional with the same transmission rate and propagation delay in each direction unless specifically instructed otherwise.)

Answers

Answer:

885 μs

Explanation:

Given that:

Switch via = 100 Mbps links

The propagation delay for each link = 25μs.

Retransmitting a received packet = 35μs

To determine:

The total time required to transmit 40,000 bits from A to B.

Considering the fact as a single packet:

Transmit Delay / link = size/bandwith

= 4×10⁴ bits / 100 × 10⁶ bits/sec

= 400 μs

The total transmission time = ( 2 × 400 + 2 × 25 + 35) μs

= (800 + 50 + 35) μs

= 885 μs

Write a program that reads the contents of a text file. The program should then create a structure that has 3 fields: a word, the frequency of the word, the list of line numbers where the word appears. Then the program will open a text file and read the content of the file. It will create another text file as output file. The output file should contain an alphabetical listing of the words, their frequency, and the list of line numbers where the word appears. -g

Answers

Answer:

See explaination

Explanation:

#include <iostream>

#include <fstream>

#include <string>

#include <vector>

#include <map>

#include <sstream>

using namespace std;

// structure to hold the word, frequency and list of lines in which word appears

struct wordFrequency

{

string word;

int frequency;

vector<int> lineNumber;

};

// main method

int main()

{

// input file name. You can change the input file name if your file name is different

string inputFileName = "data.txt";

// creating a map class object to hold words uniquely

map<string, wordFrequency> map_word;

// ifstream class object to open and read from file

ifstream fin(inputFileName);

// validating if file is opened or not

if (!fin.is_open())

{

cout << "Error in opening file!";

exit(1);

}

// string to hold line from file

string line;

// int variable to keep track of line number

int lineNumber = 0;

// fetching lines from file

while (getline(fin, line))

{

// increasing the lineNumber count because we fetch another line

++lineNumber;

// breaking a line into words using stringstream class object

string word;

stringstream iss(line);

// iterating over all the words in a line

while (iss >> word)

{

// if the word is not in the map then we create and add a new pair

auto it = map_word.find(word);

if (it == map_word.end())

{

// creating a new struct object to store new word

wordFrequency w;

w.word = word;

w.frequency = 1;

w.lineNumber.push_back(lineNumber);

map_word.insert({word, w});

}

else

{

// if the word is already there then incresing frequency and push line number into list

it->second.frequency += 1;

it->second.lineNumber.push_back(lineNumber);

}

}

}

// closing the input file

fin.close();

// creating a new output file

ofstream fout("WordFrequency.txt");

if (fout.is_open())

{

// iterating over a map

for (auto word : map_word)

{

// writing data to a output file

fout << "Word is : " << word.second.word << endl;

fout << "Frequency is : " << word.second.frequency << endl;

fout << "Appears in line : ";

for (auto i : word.second.lineNumber)

{

fout << i << " ";

}

fout << endl

<< endl;

}

// closing output file

fout.close();

}

else

{

cout << "Error! Not able to create output file!";

}

}

Question textIf operator+ is supported by a class, how many parameters should it be defined to accept?

Select one:

a. 1 or 2

b. 2

c. 3

d. 1

e. None

Answers

Answer:

b. 2

Explanation:

As we know operator + is supported by the class.Since we know that the + operator binary operator means it needs two operands to work upon it cannot work on one operand.++ operator is unary operator it works on one operand only.

For example:-

a+b

a++.

Hence we conclude that the answer is 2.

CHALLENGE 7.1.1: Initialize a list. ACTIVITY Initialize the list short.names with strings 'Gus', Bob, and 'Ann'. Sample output for the given program Gus Bob Ann 1 short_names- Your solution goes here 2 # print names 4 print(short_names[0]) 5 print(short names [11) 6 print(short_names[2])

Answers

Answer:

short_names = ["Gus", "Bob", "Ann"]

print(short_names[0])

print(short_names[1])

print(short_names[2])

Explanation:

There are some typos in your code. In addition to the missing part of the code, I corrected the typos.

First of all, initialize the list called short_names. The list starts with "[" and ends with "]". Between those, there are must be the names (Since each name is a string, they must be written between "" and there must be a semicolon between each name)

Then, you can print each name by writing the name of the list and the index of the names between brackets (Index implies the position of the element and it starts with 0)