Muscles perform what type of energy transformation?

Answers

Answer 1

Answer: Muscles perform energy transformation from chemical energy to kinetic energy which is very evident as we do our day to day activities. Hope this answers the question. Have a nice day. Feel free to ask more questions. Thank you.

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Freezing requiresa. the removal of energy.
b. the absorption of energy.
c. no energy change.

Answers

Answer:

The correct answer is option a. the removal of energy.

Explanation:

Hello!

Let's solve this!

Freezing is a process by which a lot of heat is lost, this loss of heat leads to a loss of energy as well. It means that energy is eliminated so that heat loss occurs.

Therefore the correct answer is option a. the removal of energy.

Calculate the pH of an aqueous solution of 16 mL of 0.00046 M HClO4(aq) after dilution to 42 mL.

Answers

1000 $cm^(3)$ of HClO_{4} [/tex] contain 0.00046mol
16 $cm^(3)$ of HClO_{4} [/tex] contain x
x = $(16cm ^(3) * 0.00046mol)/(1000cm x^(3) )$
x = 0.00000736mol

$M_(1) V_(1) = M_(2) V_(2)$
(0.00000736mol)(16 $cm^(3)$ )= $(x) (42cm^(2))$
$x= ((0.00000736mol) * (16cm^(3)) )/(42cm^(3) )$
= 0.000002803mol

pH= -log [ $H^(+)$ ]
= -log (0.000002803cm $^(3)$
= 5.55

Do the same volumes of H2O and H2SO4 have the same number of molecules?

Answers

no, they do not. Hope I helped! :)

Which one of the following chemicals does the body generate during regular exercise? A. Adrenaline
B. Estrogen
C. Endorphins
D. Sodium chloride

Answers

The answer is actually C. endorphins. during regular exercise, the pituitary gland and central nervous system produce endorphins

Sort the following situations into chemical change or physical change:1. salt dissolves in water
2. Hydrochloric acid reacts with magnesium to produce hydrogen gas
3. a piece of copper is cut in half
4. a sugar cube is ground up
5. water is heated and changed to steam
6. iron rusts
7. ethyl alcohol evaporates
8. ice melts
9. milk sours
10. sugar dissolves in water
11. sodium and potassium react violently with water
12. pancakes cook on a griddle
13. grass grows on a lawn
14. a tire is inflated with air
15. food is digested in the stomach
16. water is absorbed by a paper towel
17. ethyl alcohol boils at 79 egress Celsius
18. paper burns
19. water freezes at 0 degrees Celsius
20. fireworks explode
21. alka-seltzer gives off carbon dioxide when added to water
22. clouds form in the sky

Answers

Chemical
2. Hydrochloric acid reacts with magnesium to produce hydrogen gas
5. water is heated and changed to steam
6. iron rusts
9. milk sours
7. ethyl alcohol evaporates
11. sodium and potassium react violently with water
12. pancakes cook on a griddle
15. food is digested in the stomach
17. ethyl alcohol boils at 79 egress Celsius
18. paper burns
20. fireworks explode
21. alka-seltzer gives off carbon dioxide when added to water
22. clouds form in the sky

Physical
19. water freezes at 0 degrees Celsius
16. water is absorbed by a paper towel
14. a tire is inflated with air
13. grass grows on a lawn
1. salt dissolves in water
3. a piece of copper is cut in half
4. a sugar cube is ground up
8. ice melts
10. sugar dissolves in water

505 grams of KOH are required to completely react with 4.50 mole of sulfuric acid. How many moles of products are produced?

Answers

Answer : The moles of products $K_2SO_4$ and $H_2O$ are, 4.50 and 9 moles.

Explanation : Given,

Mass of water = 5.2 g

Molar mass of water = 18 g/mole

Molar mass of $O_2$ = 32 g/mole

The balanced chemical reaction will be,

$2KOH+H_2SO_4\rightarrow K_2SO_4+2H_2O$

First we have to calculate the moles of KOH.

$\text{Moles of }KOH=\frac{\text{Mass of }KOH}{\text{Molar mass of }KOH}$

$\text{Moles of }KOH=(505g)/(56g/mole)=9.018mole$

Now we have to calculate the limiting and excess reactant.

From the balanced reaction we conclude that

As, 1 mole of $H_2SO_4$ react with 2 mole of $KOH$

So, 4.50 moles of $H_2SO_4$ react with $4.50* 2=9$ moles of $KOH$

From this we conclude that, $KOH$ is an excess reagent because the given moles are greater than the required moles and $H_2SO_4$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of products $K_2SO_4$ and $H_2O$ .

From the balanced chemical reaction, we conclude that

As, 1 moles of $H_2SO_4$ react to give 1 moles of $K_2SO_4$

So, 4.50 moles of $H_2SO_4$ react to give 4.50 moles of $K_2SO_4$

and,

As, 1 moles of $H_2SO_4$ react to give 2 moles of $H_2O$

So, 4.50 moles of $H_2SO_4$ react to give $4.50* 2=9$ moles of $H_2O$

Therefore, the moles of products $K_2SO_4$ and $H_2O$ are, 4.50 and 9 moles.

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How many atoms are in 6.3 moles of calcium

As a sample of matter is cooled, its particles