What is the greatest common factors of 12 and 27

Answers

Answer 1

Answer:

The value of the Expression 7+ 14 using the GCF is 21.

What is Greatest Common Factor?

The largestfactor that splits both numbers is said to be the greatest common factor. List the prime factors of each integer before calculating the greatest common factor. One 2 and one 3 are shared by those aged 18 and 24. The GCF of 18 and 24 is 2 * 3 = 6, which we multiply to obtain.

Given:

We have to find GCF of 12 and 27.

Factorise the terms separately

12 = 2 x 2 x 3

27 = 3 x 3 x 3

So, the Greatest Common Factor is 3.

Learn more about Greatest Common Factor here:

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Answer 2

Answer: 12 is divisible by 1,2,3,4,6,12 and 27 is by 1,3,9,27 so the GCF is 3

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Evaluate b^2c^1 for b=-4 and c= 2.

What is the remainder when (2x3 + 4x2 – 32x + 18) ÷ (x + 3) ?2

12

96

110

Answers

For the answer to the question above,

Let f(x)=2x3 + 4x2 − 32x +1 8

The remainder when f(x) is divided by (x−a) is f(a).

So when divide by (x + 3 ) = (x − (−3)) the remainder is:

f(−3) = 2(−27) + 4(9)− 32 (−3) +18=−54 +3 6 + 96 + 18 =96Yes, the remainder is 96I hope my answer helped you

96 because if you use synthetic or long division the remainder will be 96

Alfred is practicing typing. The first time he tested himself, he could type 23 words per minute. After practicing for a week, he could type 26 words per minute. After two weeks he could type 29 words per minute. Based on this pattern, predict how fast Alfred will be able to type after 4 weeks of practice

Answers

first time 23 words
after week 26 words
after two weeks 29 words
so after 1 week Alfred is faster on 3 words
so after 4 weeks he could type 35 words per minute

2x -y=-1
3x-2y=1
elimination somebody do this for me

Answers

2x-y=-1 (1)
3x-2y=1 (2)
(1) * 2--> 4x-2y=-2 (3)
(3) - (2)
x= -3

sub x= -3 into (1)
2(-3)-y=-1
-6-y=-1
-y=5
y= -5

-2(2x-y)=-1
3x-2y=1

-4x+2y=2
3x-2y=1

-x=3 (x=-3)
(-3,__)

2(-3)-y=-1
-6-y=-1
-y=-1+6
-y=5
y=-5
so..(-3,-5)

The correlation coefficient r between a child age x and the number of minutes spent doing homework each day y is 0.694.What percent of the variation?

A. 30.6%
B. 48.2%
C. 51.8%
D. 69.4%

Answers

The final answer to your question is that the percent variation of the correlation coefficient between a child age x and the number of minutes spent doing homework each day y with r = 0.694 is C. 51.8%.

Hope my answer would be a great help for you.

Answer:

The answer is 48.2%

Step-by-step explanation:

The correlation coefficient r between a child age x and the number of minutes spent doing homework each day y is 0.694 i.e r=0.694

Now, we have to find percent of the variation.

The coefficient of determination is $r^(2)$