MATHEMATICS HIGH SCHOOL

Mrs. Rodriquez has 24 students in her class. Ten of the students are boys. Jeff claims that the ratio of boys to girls in this class must be 5:12. What is Jeff’s error and how can he correct it?Jeff found the ratio of the number of boys to the total number of students. He needed to first find that there are 14 girls to get a ratio of 10:14 or 5:7.Jeff found the ratio of the number of boys to the total number of students. He needed to first find that there are 14 girls. The ratio would be 14:10 or 7:5.Jeff did not write the ratio in the correct order. He should have written it as 24:10.Jeff did not write the ratio in the correct order. He should have written it as 12:5.

Answers

Answer 1

Answer:

Answer:

The correct option A.

Step-by-step explanation:

Total numbers of students = 24.

Number of boys = 10

Number of girls = 24 - 10 = 14

Jeff claims that the ratio of boys to girls in this class must be 5:12.

The ratio of the number of boys to the total number of students is

$(boys)/(students)=(10)/(24)=(5)/(12)=5:12$

Therefore Jeff found the ratio of the number of boys to the total number of students.

The ratio of boys to girls in this class is

$(boys)/(girls)=(10)/(14)=(5)/(7)=5:7$

Therefore the ratio of boys to girls in this class is 5:7.

Option A is correct.

Answer 2

Answer: The ratio is 10:14 or 5:7 which is the ratio of boys to girls!

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Ou have learned that given a sample of size n from a normal distribution, the CL=95% confidence interval for the mean can be calculated by Sample mean +/- z((1-CL)/2)*Sample std/sqrt(n). Where z((1-cl)/2)=z(.025) is the z score.a. help(qnorm) function. Use qnorm(1-.025) to find z(.025).b. Create a vector x by generating n=50 numbers from N(mean=30,sd=2) distribution. Calculate the confidence interval from this data using the CI formula. Check whether the interval covers the true mean=30 or not.c. Repeat the above experiments for 200 times to obtain 200 such intervals. Calculate the percentage of intervals that cover the true mean=30. This is the empirical coverage probability. In theory, it should be very close to your CL.d. Write a function using CL as an input argument, and the percentage calculated from question c as an output. Use this function to create a 5 by 2 matrix with one column showing the theoretical CL and the other showing the empirical coverage probability, for CL=.8, .85, .9, .95,.99.
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teacher asked her students write down the number of hours studied rounded to the nearest half hour. she complies the results in develops the probability distribution below for randomly selected student. what is the mean of the probability distribution

Answers

Answer:

1.5

Step-by-step explanation:

The question is incomplete due to the probability distribution table, investigating you can find it so I will attach it.

Having the table, we need to find the mean of the probability distribution, which is defined as the sum of the product of probability and value of random distribution, that is:

M = Sum (xi) * P (xi)

We replace:

M = 0.5 * 0.07 + 1 * 0.2 + 1.5 * 0.46 + 2 * 0.2 + 2.5 * 0.07

M = 1.5

Therefore, the mean of the given table is 1.5

Which one is greater 0.02 or 0.002

Answers

As you can see 0.002 has another 0 behind the decimal point, since this is the case 0.02 is greater.

Which is a bigger decimal or a number?

As discussed in the concept of whole and decimal numbers, One can guess now which number must be bigger or which one must be smaller. If the whole number and decimal number before the decimal are equal, then the decimal number is bigger.

What is least to greatest in decimals?

The smallest number should come first in your list, and the largest number should come last. The other numbers should be listed in between in ascending order. For example, the numbers listed from least to greatest are 11.47, 12.45, and 12.457. You can also write them using the less than a symbol: 11.47 < 12.45 < 12.457.

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Answer:

0.02

Step-by-step explanation:

As you can see 0.002 has another 0 behind the decimal point, since this is the case 0.02 is greater. :)

Please brainliest. :)

The quadratic equation y=-0.5x+4x+10 models the path of a heavy ball through the air, where y represents the height in feet and x represents time in seconds. When will the ball hit the ground?

Answers

We have been given that the quadratic equation $y=-0.5x^2+4x+10$ models the path of a heavy ball through the air, where y represents the height in feet and x represents time in seconds. We are asked to find the time when ball will hit the ground.

The ball will hit the ground, when height of ball above ground will be 0. So we will equate our given quadratic equation with 0 and solve for x.

$-0.5x^2+4x+10=0$

We will use quadratic formula to solve our given problem.

$x=(-b\pm√(b^2-4ac))/(2a)$ , where

b = Coefficient of x term,

a = Coefficient of $x^2$ term,

c = Constant.

$x=(-4\pm√((-4)^2-4(-0.5)(10)))/(2(-0.5))$

$x=(-4\pm√((16+20))/(-1)$

$x=(-4\pm√(36))/(-1)$

$x=(-4\pm6)/(-1)$

$x=(-4+6)/(-1), x=(-4-6)/(-1)$

$x=(2)/(-1), x=(-10)/(-1)$

$x=-2,x=10$

Since time cannot be negative, therefore, the ball will hit the ground after 10 seconds.

The distance in meters of a basket suspended on a spring to a tabletop below is dependent on the number of steel bearings in the basket. The function representing this relationship is d(m) = 7 – 2m, where d(m) represents the distance in meters, and m represents the number of steel bearings in the basket. Which set represents the evaluation of the function d(m) = 7 – 2m when m ∈ {0, 1, 2, 3}?

Answers

The set representing the evaluation of the function d(m) for m ∈ {0, 1, 2, 3} is {7, 5, 3, 1}.

What is the set of the evaluation?

To evaluate the function d(m) = 7 - 2m for different values of m, we simply need to substitute each value of m from the given set {0, 1, 2, 3} into the function and compute the corresponding d(m) values.

Let's calculate d(m) for each value of m:

For m = 0:

d(0) = 7 - 2(0) = 7

For m = 1:

d(1) = 7 - 2(1)= 7 - 2 = 5

For m = 2:

d(2) = 7 - 2(2) = 7 - 4 = 3

For m = 3:

d(3) = 7 - 2(3) = 7 - 6 = 1

So the set representing the evaluation of the function d(m) for m ∈ {0, 1, 2, 3} is {7, 5, 3, 1}.

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