If you have a mass of 55 kg and you are standing 3 meters away from your car, which has a mass of 1233 kg, how strong is the force of gravity between you and the car ?
Answers
Answer:
5.03×10¯⁷ N
Explanation:
From the question given above, the following data were obtained:
Mass of the person (M₁) = 55 Kg
Mass of the car (M₂) = 1234 Kg
Distance apart (r) = 3 m
Gravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²
Force (F) =?
The force between the person and his car can be obtained as follow:
F = GM₁M₂ / r²
F = 6.673×10¯¹¹ × 55 × 1234 / 3²
F = 6.673×10¯¹¹ × 67870/ 9
F = 5.03×10¯⁷ N
Thus, the force between the person and his car is 5.03×10¯⁷ N
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I hope my answer has come to your help. God bless and have a nice day ahead!
Answer:
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Explanation:
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Answers
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This is the Correct Answer is B
Edgen Approved :)
wire has a resistance of 1.3 ohms. The crosssectional
area of this wire is
(1) 7.9 × 10^−8 m2 (3) 4.6 × 10^0 m2
(2) 1.1 × 10^−7 m2 (4) 1.3 × 10^7 m2
Answers
The cross-sectional area of the copper wire is which has 1.3 ohm at 20 degree Celsius during laboratory experiment by student is 7.9×10⁻⁸ ohm.
What is the resistance?
Resistance is obstacle for the current flow in the circuit. It is the measure of reverse act to current flow in through a material. It can be given as,
Here, (ρ) is the specific resistance (l) is the length of the wire and (A) is the cross-sectional area of the wire.
During a laboratory experiment, the student finds that at 20° Celsius, a 6.0-meter length of copper wire has a resistance of 1.3 ohms.
The value of resistivity of copper wire is 1.72×10⁻⁸ ohm-m. Put these values in the above formula as,
Thus, the cross-sectional area of the copper wire is which has 1.3 ohm at 20 degree Celsius during laboratory experiment by student is 7.9×10⁻⁸ ohm.
Learn more about the resistance here;
ρ = resistivity of copper at 20 °C = 1.72 x 10⁻⁸ ohm-m
R = resistance of the copper wire = 1.3 ohm
L = length of the copper wire = 6 meter
A = area of cross-section of the copper wire = ?
Resistivity of copper wire is given as
R = ρL/A
inserting the values in the above equation
1.3 = (1.72 x 10⁻⁸) (6)/A
A = 7.9 x 10⁻⁸ m²
Hence the correct choice is
(1) 7.9 x 10⁻⁸ m²
50 km
70 km
cannot be determined
Answers
Answer:
The answer is 70 km
Explanation:
Firstly, there are few facts that we have to know:
- The car travels northward and then eastward, so both direction are perpendicular.
- It doesn't matter the total time, because we already know the total distance in every direction.
- The question is about distance, NOT displacement. I have attached an image that shows the difference between both concepts.
Finally, the first 25 min the car traveled in total 30 km and after that, the car traveled in total 40 km during 35 min. So, the total distance is:
30+40=70 km.
makes motor vehicle move faster?
a) 0
b) 11
c) 2
d) 3
e) 4
Answers
Answer:
e.4
Explanation:
explanation - because it is
3,600 RPM
3,200 RPM
3,400 RPM
3,000 RPM
Sequence
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Answers
with the same generator, so the only factor for producing the slectric field is only the speed. The faster the rotational speed of the generator the greater it produce electric field. So the sequence is 3000 rpm < 3200 rpm < 3400 rpm < 3600 rpm
Answer: 3000
3200
3400
3600
Explanation: just took the test 5 out of 5