What is the kinetic energy of a 1.0-kg billiard ball that moves at 5.0 m/s? A. 5.0 J B. 6.5 J C. 10.0 J D. 12.5 J

Answers

Answer 1
Answer:

The kinetic energy of a moving body can be determined from its mass and velocity of the body. The kinetic energy of  1.0-kg billiard ball that moves at 5.0 m/s is 12.5 J. Hence, option D is correct.

What is kinetic energy?

Kinetic energy is a form of energy generated in body by virtue of its motion. It is directly proportional to the mass and square of velocity of the body. The equation of kinetic energy is written as follows:

KE = 1/2 mv²

When a body starts moving its kinetic starts to increase while the potential energy drops out. However the total mechanical energy in the system will be conserved.

The mass of the billiard ball is given 1 kg and the velocity is 5 m/s. Then the kinetic energy of the ball is calculated as follows:

KE = 1/2 1 kg × ( 5 m/s )².

    = 1/2 × 25

    = 12.5 J.

Therefore, the  kinetic energy of  1.0-kg billiard ball that moves at 5.0 m/s is 12.5 J. Hence, option D is correct.

To find more about kinetic energy, refer the link below:

brainly.com/question/12669551

#SPJ5

Answer 2
Answer: The formula for a kinetic energy (KE) is
KE = 0.5*m*v²

Given m = 1.0 kg, v = 5.0 m/s, so
KE = 0.5*1.0*(5.0)
² = 12.5 J

The answer is D.

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what is the kinetic energy of an object that has mass of 30 kilograms and move with a velocity of 20 m/s

Answers

Kinetic Energy = 1/2 * m * v² 1/2 * 30 * 20² 1/2 * 30 * 400 12000/2 6000 J.

What is relative velocity?​

Answers

Relative velocity is the velocity of an object or observer B in the rest frame of another object or observer A

Answer:

the velocity of a moving body relative to another body is called relative velocity.

Chanel has some cotton candy that came in a cloudy shape. She wants to make it more dense. Which describes the candy before and after Chanel manipulated it?

Answers

The candy before has undergone physical change after manipulation because it says that it will make the cotton candy denser. Making it denser probably doesn't have to change any chemical components of the candy.

Two asteroids bump in space. The larger one has a mass of 3000 kg and the smaller one has a mass of 100 kg. If the force of the collision is 10,000 newtons on each asteroid, what are their accelerations?a. The larger one is unaffected by the collision, while the smaller one accelerates at 100 m/s2.
b. The larger one accelerates at 3.33 m/s2, while the smaller one accelerates at 100 m/s2.
c. The larger one accelerates at 100 m/s2, while the smaller one accelerates at 3.33 m/s2.
d. The ...

Answers

Answer:

B) The larger one accelerates at 3.33 m/s² while the smaller one accelerates at 100 m/s².

Explanation:

Parameters given:

Mass of larger asteroid = 3000 kg

Mass of smaller asteroid = 100 kg

Force of collision = 10000 N

Since both of them experience the collision force, we can find how that force causes them to accelerate by using the formula of force:

F = m*a

=> a = F/m

For the larger one,

a = 10000/3000 = 3.33 m/s²

For the smaller one,

a = 10000/100 = 100 m/s²

 There's really no such thing as the force of a collision.

F = M A
A = F / M

If a 10,000N net force acts on a 3,000 kg object, then the object's
acceleration is (10,000N / 3,000kg) = 3-1/3 m/s² for as long as the
force on it persists, and zero after that.

If a 10,000N net force acts on a 100 kg object, then the object's
acceleration is (10,000N / 100kg) = 100 m/s² for as long as the
force on it persists, and zero after that.

Those appear to be the numbers in choice-b, but the description
of the event and the situation is misleading.

-g A small block is attached to an ideal spring and is moving in SHM on a horizontal frictionless surface. The amplitude of the motion is 0.165 m. The maximum speed of the block is 3.90 m/s. What is the maximum magnitude of the acceleration of the block?

Answers

Answer:

a= 92. 13 m/s²

Explanation:

Given that

Amplitude ,A= 0.165 m

The maximum speed ,V(max) = 3.9 m/s

We know that maximum velocity in the SHM  given as

V(max)  = ω A

ω=Angular speed

A=Amplitude

\omega =(3.9)/(0.165)\ rad/s

ω=23.63 rad/s

The maximum acceleration given as

a = ω² A

a= (23.63)² x 0.165 m/s²

a= 92. 13 m/s²

Therefore the maximum magnitude of the acceleration will be 92. 13 m/s².

How does an action potential differ from simple depolarization

Answers

Answer:

A simple depolarization can be defined as any change that occurs in a neuron that results to it being more positive than resting potential, but an action potential happens only when the simple depolarization reaches the threshold or optimum level.

Explanation:

A simple depolarization can be defined as any change that occurs in a neuron that results to it being more positive than resting potential, but an action potential happens only when the simple depolarization reaches the threshold or optimum level.