Can someone please tell me if I’m correct thanks I really need an answer thanks
Can someone please tell me if I’m correct thanks I - 1

Answers

Answer 1
Answer:

Answer:

yeah im pretty sure you are

Step-by-step explanation:

Answer 2
Answer:

Answer:

the last one is the correct answer

Step-by-step explanation:

In order for it to be proportional it has to go through the origin (0,0)

Proportional - y=mx

Non Proportional - y=mx+b


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One month Leila rented 3 movies and 2 video games for a total of $21 . The next month she rented 8 movies and 4 video games for a total of $49 . Find the rental cost for each movie and each video game.

Answers

x = price movie = 4.25
y = price game = 5.50

Help me with this plzzz

Answers

Answer:

2/3

Step-by-step explanation:

Everytime the line moves over 3 it goes up 2, so the run is 3 and rise is 2. It is written in rise over run.

The correct answer for your question is 2/3

Choose values for a and b and use them to verify the product shown.(5a + b)(a – 6b) = 5a2 – 29ab – 6b2

Answers

just  make a=2 and b=3
(5(2)+3)(2-6(3))=5(2)^2-29(2)(3)-6(3)^2
(10+3)(2-18)=5(4)-29(6)-6(9)
(13)(-16)=20-174-54
-208=-208
correct

Please solve equations by completing square

Answers

x^2-4x+1=0\n x^2-4x+4-3=0\n (x-2)^2=3\n |x-2|=\sqrt3\n x-2=\sqrt3 \vee x-2=-\sqrt3\n x=2+\sqrt3 \vee x=2-\sqrt3

x^2+6x-9=0\n x^2+6x+9-18=0\n (x+3)^2=18\n |x+3|=√(18)=3\sqrt2\n x+3=3\sqrt2 \vee x+3=-3\sqrt2\n x=-3+3\sqrt2 \vee x=-3-3\sqrt2\n

x^2+20x+3=0\n x^2+20x+100-97=0\n (x+10)^2=97\n |x+10|=√(97)\n x+10=√(97) \vee x+10=-√(97)\n x=-10+√(97) \vee x=-10-√(97)

x^2-2x-5=0\n x^2-2x+1-6=0\n (x-1)^2=6\n |x-1|=\sqrt6\n x-1=\sqrt6 \vee x-1=-\sqrt6\n x=1+\sqrt6 \vee x=1-\sqrt6

Show that 4(a + 3) - 3(a - 2) = a + 18

Answers

4(a + 3) - 3(a - 2) = a + 18 4a+12-3a+6=a+18 a+18=a+18 true

True or false? shapes that have no right angles also have no perpendicular segments?

Answers

It's false. Sometimes shapes might not have perpendicular segments but this is false.