Answers
Answer:
0.432 drinks are toxic
Explanation:
The toxic dose of ethylene glycol is 0.1 mL per kg body weight (mL/kg). In grams (Density ethylene glycol = 1.11g/mL):
1.11g/mL * (0.1mL / kg) = 0.111g/kg
If the victim weighs 85kg, its letal dose is:
85kg * (0.111g/kg) = 9.435g of ethylene glycol
Using the concentration of ethylene glycol in the liquid:
9.435g of ethylene glycol * (550g liquid / 120g ethylene glycol) = 43.2g of liquid are toxic.
The drinks are:
43.2g of liquid * (1 drink / 100 g) =
0.432 drinks are toxic
Related Questions
True or False: Observations are just things that you see
Suppose of lead(II) acetate is dissolved in of a aqueous solution of ammonium sulfate. Calculate the final molarity of acetate anion in the solution. You can assume the volume of the solution doesn't change when the lead(II) acetate is dissolved in it. Round your answer to significant digits.
The entropy of a substance above absolute zero will always be: a. Negativeb. Positivec. Neither Negative nor positive
If you mix different amounts of two ideal gases that are originally at different temperatures, what must be true of the final state after the temperature stabilizes? (There may be more than one correct choice.) a) Both gases will reach the same final temperature. b) The final rms molecular speed will be the same for both gases. c) The final average kinetic energy of a molecule will be the same for both gases.
single bonds
carboxylic groups
carbon chains
Answers
Answers
Answer:
2-Phenylpropane (Cumene)
Explanation:
Famous Friedel Craft Alkylation.
Aluminum Chloride grasped the 1-chloropropane forming an intermediate product composed of Aluminum tetrachloride and n-propylcation. It is well understood that primary carbocations are unstable and therefore undergo hydrogen shifting to attain stability. n-Propylcarbocation undergone hydrogen shifting, forming isopropylcarbocation which reacted with benzene forming 2-Phenylpropane as the major product and HCl as a byproduct.
AlCl3 + CH3CH2CH2Cl --> AlCl4- + CH3CH2CH2+
CH3CH2CH2+ ---> CH3CH(+)CH3
C6H6 + CH3CH(+)CH3 ---> C6H5CH(CH3)2 + H+
AlCl4- + H+ ---> HCl + AlCl3
Answer:
From the given problem statement,he was attempting to prepare n−propylbenzene by alkylation benzene with 1−chloropropane and aluminum chloride,but 1-propyle benze was a major product in result.
Answers
Answer:
If the partial pressure of N2 in a scuba divers blood at the surface is 0.79 atm, what will the pressure be if he/she descends to a depth of 30 meters (4 atm) and stays there long enough to reach equilibrium (b)
Explanation:
for every 3m that the internal pressure is lowered, it increases in an atmosphere approximately, so when the blood pressure of nitrogen decreases 30m, it will increase by approximately 10 atm, being enough there for the body to enter into equilibrium
Answers
Answer:
All of alpha-ketoglutarate formed in the citric acid cycle would contain the radioactive while none of succinate would contain
, and all of carbon dioxide released would contain
.
Explanation:
When oxaloacetate in the citric acid cycle is labeled with in carboxyl carbon atom which is farthest from keto group, alpha ketoglutarate formed from this oxaloactetate has the full radioactive label. In the next step, the carboxylic group (that contains the
) is eliminated in the form of the release of the carbon dioxide and succinate is formed. Succinate thus will not have radioactivity.
released had all the radioactivity.
iron (III) nitrite
iron (II) nitrite
iron (1) nitrite
Answers
Final answer:
The name of the ionic compound Fe(NO2)2 is iron (II) nitrite.
Explanation:
The name of the ionic compound Fe(NO2)2 is iron (II) nitrite.
Learn more about Naming ionic compounds here:
B. two
C. three
D. four
Answers
Answer:
C. three
Explanation:
Final answer:
A lithium atom must lose one valence electron to achieve a full valence shell, resulting in a positively charged lithium cation (Lit) with a noble gas configuration similar to helium.
Explanation:
To achieve a full valence shell, a lithium atom must lose one electron. Lithium has an atomic number of 3, which means it has three electrons: two in the first shell and one in the second shell. Since the first shell (1s) is already full with two electrons, lithium has a single electron in the 2s subshell of the second shell. This single electron is the valence electron.
According to the Lewis diagram, lithium (Li) has only one valence electron in its second shell. By transferring this lone electron to another atom, lithium's electron configuration will resemble that of helium (He), with two electrons in its first shell, thus achieving a stable noble gas configuration. This transfer results in the formation of a lithium cation, denoted as Lit, with a charge of 1+.
It is important to note that when lithium becomes a cation, it does not necessarily mean it has a complete valence shell in terms of helium or neon. Instead, it has achieved stability by having a full inner shell, which mimics the noble gas configuration of helium.
Learn more about Lithium Valence Electron here:
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