The caverns of sonora have two different tours the crystal palace and the horseshoe lake tour

Answers

Answer 1

Answer: Did that help

The total length of both tours is 3.25 miles the crystal palace toward his a half mile less than twice the distance of the horseshoe Lake tour

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The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second). (a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

Answers

Answer:

The probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day is $P(Y>190)=\frac{1}{e^{(19)/(10)}}\approx 0.1496$

Step-by-step explanation:

Let Y be the water demand in the early afternoon.

If the random variable Y has density function f (y) and a < b, then the probability that Y falls in the interval [a, b] is

$P(a\leq Y \leq b)=\int\limits^a_b {f(y)} \, dy$

A random variable Y is said to have an exponential distribution with parameter $\beta > 0$ if and only if the density function of Y is

$f(y)=\left \{ {{(1)/(\beta)e^{-(y)/(\beta) }, \quad{0\:\leq \:y \:\leq \:\infty} } \atop {0}, \quad elsewhere} \right.$

If Y is an exponential random variable with parameter β, then

mean = β

To find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day, you must:

We are given the mean = β = 100 cubic feet per second

$P(Y>190)=\int\limits^(\infty)_(190) {(1)/(100)e^(-y/100) } \, dy$

Compute the indefinite integral $\int (1)/(100)e^{-(y)/(100)}dy$

$(1)/(100)\cdot \int \:e^{-(y)/(100)}dy\n\n\mathrm{Apply\:u \:substitution}\:u=-(y)/(100)\n\n(1)/(100)\cdot \int \:-100e^udu\n\n(1)/(100)\left(-100\cdot \int \:e^udu\right)\n\n(1)/(100)\left(-100e^u\right)\n\n\mathrm{Substitute\:back}\:u=-(y)/(100)\n\n(1)/(100)\left(-100e^{-(y)/(100)}\right)\n\n-e^{-(y)/(100)}$

Compute the boundaries

$\int _(190)^(\infty \:)(1)/(100)e^{-(y)/(100)}dy=0-\left(-\frac{1}{e^{(19)/(10)}}\right)$

$\int _(190)^(\infty \:)(1)/(100)e^{-(y)/(100)}dy=\frac{1}{e^{(19)/(10)}}\approx 0.1496$

The probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day is $P(Y>190)=\frac{1}{e^{(19)/(10)}}\approx 0.1496$

Estimate the quotient by rounding the expression to relate to a one-digit fact. Explain your thinking in the space below. a. 432 ÷ 73 ___________ b. 1,275 ÷ 588 ___________

Answers

Estimations are used to get the approximated value of an expression.

The estimate of 432 ÷ 73 is 5.714
The estimate of 1,275 ÷ 588 is 1.667

$\mathbf{(a)\ 432 / 73}$

Round up to 1 digit

$\mathbf{432 / 73 \approx 400 / 70}$

Divide

$\mathbf{432 / 73 \approx 5.714}$

Hence, the estimate of 432 ÷ 73 is 5.714

$\mathbf{(b)\ 1275 / 588}$

Round up to 1 digit

$\mathbf{ 1275 / 588 \approx 1000 / 600}$

Divide

$\mathbf{ 1275 / 588 \approx 1.667}$

Hence, the estimate of 1,275 ÷ 588 is 1.667

Answers

Answer:

0.160

Step-by-step explanation:

Given that:

Percentage population with blood group o = 45%

probability that exactly 6 people in a group of 10 random people have type o blood

Using binomial probability distribution formula :

n = 10, r = 6 ;

Probability of success (p) (population with blood group o = 45% = 0.45

Probability of failure (1 - p) population without blood group o = (1 - 0.45) = 0.55

nCr * p^r * (1 - p)^(n-r)

10C6 * 0.45^6 * 0.55^4

210 * 0.00830 * 0.0915

= 0.1594845

= 0.160

Consider the quadratic function f(x) = x2 – 8x – 4. What is the value of the leading coefficient?8 оооо
4

Answers

Answer:

x = 4 + 2 sqrt(5) or x = 4 - 2 sqrt(5)

thus :

Step-by-step explanation:

Solve for x over the real numbers:

x^2 - 8 x - 4 = 0

Hint: | Solve the quadratic equation by completing the square.

Add 4 to both sides:

x^2 - 8 x = 4

Hint: | Take one half of the coefficient of x and square it, then add it to both sides.

Add 16 to both sides:

x^2 - 8 x + 16 = 20

Hint: | Factor the left hand side.

Write the left hand side as a square:

(x - 4)^2 = 20

Hint: | Eliminate the exponent on the left hand side.

Take the square root of both sides:

x - 4 = 2 sqrt(5) or x - 4 = -2 sqrt(5)

Hint: | Look at the first equation: Solve for x.

Add 4 to both sides:

x = 4 + 2 sqrt(5) or x - 4 = -2 sqrt(5)

Hint: | Look at the second equation: Solve for x.

Add 4 to both sides:

Answer: x = 4 + 2 sqrt(5) or x = 4 - 2 sqrt(5)

Answer:

-8 or option A

Step-by-step explanation:

2023

PLZ HELP ASAP SOLID GEOMETRY

Answers

The correct choice (B)
By slicing the triangular prism with a plane parallel to the equilateral base
that will produce an equilateral triangle cross section
see the attached figure

Adam bought 12 bagels. It cost him $30. How much does each bagel cost

Answers

Answer:

$2.50

Step-by-step explanation:

$30 divided by 12 = 2.5

Each bagel is $2.5

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Rod is a drummer who purchases his drumsticks online. When practicing with the newest pair, he notices they feel heavier than usual. When he weighs one of the sticks, he finds that it is 2.66 oz. The manufacturer's website states that the average weight of each stick is 2.25 oz with a standard deviation of 0.17 oz. Assume that the weight of the drumsticks is normally distributed.What is the probability of the stick's weight being 2.66 oz or greater