Assume hosts A and B are each connected to a switch Svia 100-Mbps links. The propagation delay on each link is 25μs. The switch Sis a store-and-forward device and it requires a delay of 35μs to process a packet after is has received the last bit in the packet. Calculate the total time required to transmit 40,000 bits from Ato B in the following scenarios. (The total time is measured from the start of the transmission of the first bit at A, until the last bit is received at B. We always assume that links are bi-directional with the same transmission rate and propagation delay in each direction unless specifically instructed otherwise.)

Answers

Answer 1
Answer:

Answer:

885 μs

Explanation:

Given that:

Switch via = 100 Mbps links

The propagation delay for each link = 25μs.

Retransmitting a received packet = 35μs

To determine:

The total time required to transmit 40,000 bits from A to B.

Considering the fact as a single packet:

Transmit Delay / link = size/bandwith

= 4×10⁴ bits / 100 × 10⁶ bits/sec

= 400 μs

The total transmission time = ( 2 × 400 + 2 × 25 + 35) μs

= (800 + 50 + 35) μs

= 885 μs


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The computer output for integer programs in the textbook does not include reduced costs, dual values, or sensitivity ranges because these variables are not meaningful for integer programs. TrueFalse

Answers

Answer:

The answer is True

Write a program to complete the task given below: Ask the user to enter any 2 numbers in between 1-10 and add both of them to another variable call z. Use z for adding 30 into it and print the final result by using variable results.

Answers

Answer:

a = int(input("Enter first value between 1 - 10"))

b = int(input("Enter second value between 1 - 10"))

z = a + b

z += 30

print("The value of z = ", z)

Explanation:

The code is written above in python language to perform the given task.

Now, let us explain each statement of code.

Step 1: The first two lines take input from the user prompting the user to enter the values between 1 to 10.

Then the values are type casted to int using int().

The values are stored in variables a and b.

Step 2: Then, the values of a and b are added to get another variable z.

Step 3: The statement 'z += 30' is equivalent to z = z+30

It adds 30 to the variable z and stores it in the same variable z.

Step 4: Finally the value of variable 'z' is printed using print() command.

What is not recyclable in a
hybrid car
hydrogen car
petrol car

Answers

There are different aspect of cars that cannot be recyclable. In petrol cars, The aspect that cannot be recycled is  used gear oil, windshield wiper solution, brake fluid, power steering fluid, etc.

This is because they are very toxic substances, as they have lead and poisonous ethylene glycol in them.

  • A lot of electric and hybrid cars often uses different kinds of lithium-ion batteries and nickel metal hydride batteries that are used and not all part are recyclable.

  • In hydrogen car, their fuel cells is not to have some measure of recyclable.  The Fuel cells has some recyclable materials but not all.

Learn more about recyclable from

brainly.com/question/376227

Laptop components that can be replaced relatively easily include the ____ and the ____first part
screen
power supply
RAM

second part
hard disk
keyboard
touchpad​

Answers

Answer:

Power supply and Hard disk

Explanation:

How many times will the following loop display "Looping again!"? for(int i=0; i<=20; i++) cout << "Looping again!" << endl;

Answers

Answer:

21 times

Explanation:

Following are the description of output:

  • As it is for loop and The loop is started from the i=0 , after that check the condition 0<=20 condition is true .The control moves to the body of loop and it print Looping again! on the console window .After that it increment the value of i=i+1 .
  • Now i=1  1<=20  condition is true .The control moves to the body of loop and it print Looping again! on the console window .After that it increment the value of i=i+1 .
  • i=2 2<=20 condition is true .The control moves to the body of loop and it print Looping again! on the console window .After that it increment the value of i=i+1 .
  • ............soon
  • This process is executed again and again but when the value i=21 the loop condition is false .The loop is terminated .
  • As the loop is starts from the i=0 and executed less then equal to 20 therefore 21 times the loop is executed .

Assume you're running a query on your orders in the past year. You want to see how many orders were placed after May. What type of query would you use to find this data? A. Select
B. Range
C. Complex
D. Parameter

Answers

Your answer is A. Because a query is a question about a an organization to check how it's going