Nina wants to download games for her video game console. Older games cost 100 points and new releases cost 200 points to use. The equation 100a+200b=4000, where a is the number of der games and b is the number of new releases, models the situation. How many older games can she download if she downloads 4 new games? 5 new games?

Answers

Answer 1

Answer: Replace b with 4: 100a+200(4)=4000. 100a+800=4000. Combine like terms: 100a=3,200. Get the unknown by itself: A=32. She can download 32 old games if she downloads 4 new ones. Same steps: 100a+200(5)=4000. 100a+1000=4000. 100a=3000. A=30. She can download 30 old games if she downloads 5 new ones. :)

Answer 2

Answer:

Final answer:

If Nina downloads 4 new games, she can additionally download 16 older games. If she downloads 5 new games, she can download 15 older games.

Explanation:

The problem can be solved by substituting the number of new games into the equation and solving for 'a' which represents the number of older games.

For 4 new games, the equation becomes 100a+200*4=4000. Solving this, we get 'a' as 16. Hence, Nina can download 16 older games.

For 5 new games, the equation becomes 100a+200*5=4000. Solving this, we get 'a' as 15. Hence, Nina can download 15 older games when she downloads 5 new games.

Learn more about Algebraic Equations here:

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