How does a balanced chemical equation show that mass is never lost or gained in a chemical reaction

Answers

Answer 1
Answer: mass never changes in anything and after the solution you will notice answer has 1 same number
Answer 2
Answer:

Final answer:

A balanced chemical equation shows that mass is not lost or gained in a chemical reaction by ensuring the number of atoms and overall charge on both the reactants and products side are equal, adhering to the law of conservation of mass.

Explanation:

A balanced chemical equation is one where the number of each type of atom in the reactants side is equivalent to the number of the same type of atoms in the products side. In chemical reactions, matter cannot be created or destroyed, a principle called the law of conservation of mass. This means that all the atoms present in the reactants will be accounted for in the products, ensuring that mass is never lost or gained during the reaction process.

For instance, if we take the simple chemical reaction of hydrogen and oxygen forming water (2H2 + O2 → 2H2O), you'll see that there are four hydrogen atoms and two oxygen atoms both before and after the reaction, thus demonstrating mass conservation. Additionally, in balanced chemical equations, not only should atoms be balanced, but also charges to ensure charge conservation which is necessary when dealing with ionic substances. The mass balance and charge balance are both instrumental in maintaining the law of conservation of mass in chemical reactions.

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My sister is a peach" is a metaphor.


TrueFalse

Answers

yes that is a metaphor 

Answer:

True it is a metaphor

Explanation:

Measuring Physical Properties Lab ReportInstructions: In the Physical Properties lab, you will test the physical properties of different building materials in order to pick the appropriate materials for a new home in Tiny World. Record your observations and test measurements in the lab report below in the areas shaded in purple. You will submit your completed report to your instructor.
Student Name
Instructor
Date
Lab Objectives
In this lab you will:
• help the aliens, called Tinyians, build the best house on their planet called Tiny World.
• experiment with different building materials to collect data to see which ones best meet the criteria for building a home on Tiny World.
• test each building material for density, thermal and electrical conductivity, flexibility, and magnetism.
Background Research:
You will need to gather background research from the virtual lab to form a good hypothesis. Read the Welcome to Tiny World part of the lab. Use the background information you learn to answer the questions below.
Describe the gravity of Tiny World.

Part 1:
Describe the reason your house will need magnets.


Describe the climate of Tiny World.

Hypothesis:
In this section, include the IF/THEN statements you developed during your lab activity. These statements reflect your predicted outcomes for the experiment.
A If we use _______ to build the roof of the house, then the temperature inside the house will remain cooler.

B If we use_______ to build the walls and floors of the house, then the temperature inside the house will remain cooler.
C If we use ______ to bring electricity into the home, then it will allow electricity to flow into the home at a faster rate.

D If we use_______ to construct the latches on the windows and doors, then the magnetism will keep the latches secure.

Part 2
Procedure:
1. You will test each building material for density, thermal and electrical conductivity, flexibility, and magnetism.
2. Record your observations in the data table provided below.
3. Repeat steps with all test materials.
Data:
Record the results of each of your physical property tests in the table below.
Wood Clay Brick Iron Aluminum Copper Nickel
Flexibility
(?/10)
Magnetism
(number of paper clips)
Thermal Conductivity
(W/(m·K))
Electrical Conductivity
(x107 S/m)
Mass (g) 10g 10g 10g 10g 10g 10g
Volume (cm3)
Formula:
L x W x H
Density
(g/cm3)
Formula:
D=M/V

part 3
Conclusion
Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.
1 Using two to three sentences, summarize what you investigated and observed in this lab.
2 What was the independent variable in the lab?
3 What was the dependent variable in the lab?
4 Did each of your experiment results support, or fail to support your four hypotheses? A.
B
C.
D.
5 Why do you think a building material's density is important when building homes or architectural structures?
6 Why wouldn’t you choose wood or aluminum for the latches on your house?
7 Which material has the highest thermal conductivity?

8 Which material has the highest electrical conductivity
9 Based on your data, explain why these materials have the highest thermal and electrical conductivity?
10 Think about where you live now or where you have lived in the past; use complete sentences to describe this environment and the weather.

Answers

Answer:

The purpose of the "Measuring Physical Properties Lab Report" is to test the physical properties of different building materials in order to choose the most suitable materials for a new home in Tiny World. The lab objectives include helping the Tinyians build their best house, experimenting with different materials to collect data, and testing each material for density, thermal and electrical conductivity, flexibility, and magnetism.

The background research will provide information about Tiny World, including its gravity, climate, and other relevant details. The hypothesis section requires you to make IF/THEN statements based on the lab activity. For example, IF we use a certain material for the roof, THEN the temperature inside the house will remain cooler.

In part 2, the procedure involves testing each building material for density, thermal and electrical conductivity, flexibility, and magnetism. You need to record your observations in the data table provided.

In part 3, the conclusion should summarize the lab results and provide an interpretation of the results. It also includes answering questions about the independent and dependent variables in the lab, whether the experiment results support or fail to support the hypotheses, and explanations about the importance of density in building materials, why wood or aluminum wouldn't be suitable for latches, and which materials have the highest thermal and electrical conductivity.

Finally, you are asked to describe the environment and weather of a place you have lived in the past or currently live in, using complete sentences.

Hope this helps :)

Explanation:

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A). Polonium is a rare element with 33 radioisotopes. The most common one, 210Po, has 82 protons and 128 neutrons. When 210Po decays, it emits an alpha particle, which is a helium nucleus (2 protons and 2 neutrons). 210Po decay is tricky to detect because alpha particles do not carry very much energy compared to other forms of radiation. They can be stopped by, for example, a sheet of paper or a few inches of air. That is one reason that authorities failed to discover toxic amounts of 210Po in the body of former KGB agent Alexander Litvinenko until after he died suddenly and mysteriously in 2006. What element does an atom of 210Po change into after it emits an alpha particle? b). Some undiluted acids aremore corrosive when they are diluted with water. That is why laboratory workers are told to wipe acid splashes with a towel before washing with a copious amounts of water. Explain.

Answers

Answer:

a)  Lead

b) Below

Explanation:

a) ₂₁₀ Po⁸⁴ ⇒ α + ₂₀₈Pb⁸²

b) Acids are extremely corrosive substances, so they must be cleaned soon as possible because they can damage not only the furniture but also clothes and skin of the laboratory workers.

Before cleaning the polluted area with water, acids must be clean with towels in order to reduce the amount of acid.

The reaction between the acids and water are very explosive, they are exothermic reactions, that means that they increase the temperature of the area polluted and it can cause more damage. That's why the area must be cleaned with towel before add water.

Changes to the global climate could include _______.a. changes to temperature
b. changes to pressure
c. changes to precipitation
d. all of the above

Which of the following is not released by trees into the atmosphere?
a. oxygen
b. water vapor
c. ozone
d. none of the above

Answers

1. Answer is d. all of the above.

Climate can be defined as the data collection of weather conditions of a long period of time in a certain area. The weather conditions that affect to the climate are temperature, precipitation, atmospheric pressure, wind and so on. Any changes in weather can change the global climate.

2. Answer is c. ozone.

Trees release oxygen and water vapor into the atmosphere but not ozone. The oxygen gas is released by trees as the by-product of photosynthesis. This is the natural way of production of oxygen gas. Water vapor can be released due to the transpiration of trees.

1. The correct answer is option D. all of the above.

Global climate change will bring changes in temperature such as heat waves, droughts, volcanic eruption, deforestation, extinction of species due to large shift in temperatures, changes in precipitation such as  heavy snowfall, ocean acidification, and ozone depletion.  

2. The correct answer is option C, ozone.  

Ozone is not released by trees into the atmosphere. Plants have chlorophyll and in the presence of sunlight plants uses sunlight and carbon dioxide to form glucose and oxygen.

6CO₂ + 6H₂O  ->  C₆H₁₂O₆ + 6O₂

During transpiration plants exhale water vapor through the stomata, tiny pores that are found on the surface of the leaves.

Thus trees never release ozone into the atmosphere.

#1: Which of the following is the abbreviation for a unit of energy? A. K / B. °C/ C. W / D. cal............... #2: A 200 g block of a substance requires 1.84 kJ of heat to raise its temperature from 25°C to 45°C. Use the table attached to identify the substance. A. iron/ B. aluminum/ C. gold/ D. copper.....................#3: In a calorimeter, the temperature of 100 g of water decreased by 10°C when 10 g of ice melted. How much heat was absorbed by the ice? A. 418 kJ / B. 100 kJ / C. 10 J / D. 4.18 kJ ..................#4: The amount of heat needed to raise the temperature of 50 g of a substance by 15°C is 1.83 kJ. What is the specific heat of the substance? A. 2.44 J/g-°C / B. 2.22 J/g-°C / C. 2.13 J/g-°C / D. 2.05 J/g-°C ................#5: In a calorimeter, 3.34 kJ of heat was absorbed when 10 g of ice melted. What is the enthalpy of fusion of the ice? A. 6.68 J/g / B. 334 J/g / C. 6.68 kJ/g/ D. 334 kJ/g

Answers

Among the choices, the unit of energy is calories. Answer in 1) is D. In 2) we are given with te mass , heat and temperature change. we just need to get the heat capacity and compare it with the following metals. The calculated heat capacity is 0.46 kJ/kg K. The answer is A. iron. In 3) we can compute the heat absorbed by the formula ΔH=mCpΔT. Cp of water is 4.18 J/g K. Answer of 3) is D. In 4) the formula used in Cp=ΔH/mΔT. Answer in 4) is A. The heat of enthalpy of fusion of ice is 80 cal/g. We convert this to J/g. Answer  in 5) is B.334 J/g.

Answer:

1. D. cal......

2.A. iron

3. D

4.2.44j/g°C   A

5,Lf=334J/g   B

Explanation:

1: Which of the following is the abbreviation for a unit of energy? A. K / B. °C/ C. W / D. cal...............

calorie is the unit of energy

#2: A 200 g block of a substance requires 1.84 kJ of heat to raise its temperature from 25°C to 45°C. Use the table attached to identify the substance. A. iron/ B. aluminum/ C. gold/ D. copper.....................

Q=mcdt

1840=0.2*C*(45-25)

C=460J/KgK

if the specific heat capacity is the above then he substance is iron

#3: In a calorimeter, the temperature of 100 g of water decreased by 10°C when 10 g of ice melted. How much heat was absorbed by the ice? A. 418 kJ / B. 100 kJ / C. 10 J / D. 4.18 kJ .................

Q=mcdT

Q=0.1*10*4180

Q=4180j. answer D

.#4: The amount of heat needed to raise the temperature of 50 g of a substance by 15°C is 1.83 kJ. What is the specific heat of the substance? A. 2.44 J/g-°C / B. 2.22 J/g-°C / C. 2.13 J/g-°C / D. 2.05 J/g-°C ................

Q=mcdT

1830=50/1000*C*15

C=2440j/kg/k

change it to j/g°C

2.44j/g°C   A

#5: In a calorimeter, 3.34 kJ of heat was absorbed when 10 g of ice melted. What is the enthalpy of fusion of the ice? A. 6.68 J/g / B. 334 J/g / C. 6.68 kJ/g/ D. 334 kJ/g

Q=mLf

Lf=enthalpy of fusion

3340/10=Lf

Lf=334J/g   B

Enthalpy of fusion quantity of heat to convert 1 unit mass of a solid to liquid without any noticeable change in temperature.

Silver-plated utensils were popular before stainless steel became widely used to make eating utensils. Silver tarnishes when it comes in contact with hydrogen sulfide, H2S, which is found in the air and in some foods. However, stainless steel does not tarnish when itcomes in contact with hydrogen sulfide.

76 In the space in your answer booklet, draw a Lewis electron-dot diagram for the compound that tarnishes silver. [1]

77 In the ground state, an atom of which noble gas has the same electron configuration as the sulfide ion in Ag2S? [1]

Answers

Silver tarnishes due to the chemical reaction with hydrogen sulfide, forming silver sulfide. A Lewis dot structure for H2S shows sulfur at the center bonded to two hydrogen atoms. The sulfide ion in Ag2S has the same electron configuration as the noble gas neon.

The chemical compound that tarnishes silver is hydrogen sulfide, H2S. In terms of Lewis electron dot structures, hydrogen sulfide, H2S, would be modelled as an S atom at the center surrounded by two H atoms. Each H atom is bonded to the S atom by a shared pair of electrons, represented by a single line. In the sulfide ion S2- (which is a part of Ag2S), there are additional 2 electrons to the sulfur atom, making a total of 8 valence electrons, which is the same electron configuration as the noble gas neon.

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Final answer:

The compound that tarnishes silver is silver sulfide (Ag2S), and its Lewis electron-dot diagram can be drawn by representing the valence electrons. The sulfide ion in Ag2S has the same electron configuration as the noble gas argon (Ar).

Explanation:

A Lewis electron-dot diagram is a representation of the valence electrons in an atom or a compound. The compound that tarnishes silver is silver sulfide (Ag2S). The Lewis electron-dot diagram for Ag2S can be drawn by representing the valence electrons of each element.

The sulfide ion in Ag2S has the same electron configuration as the noble gas argon (Ar). This means that the electron configuration of the sulfide ion is 1s2 2s2 2p6 3s2 3p6.

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