Answers
The current will be "2 A".
Given values are:
- Charge, Q = 20 C
- Time, t = 10 seconds
As we know,
→
or,
→
BY substituting the values, we get
Thus the answer above is right.
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Answer:
2 A
Explanation:
From the question,
Q = it..................... Equation 1
Where Q = Quantity of charge, i = cudrrent, t = time.
Make i the subject of the equation
i = Q/t.......................... Equation 2
Given: Q = 20 C, t = 10 seconds.
Substitute these values into equation equation 2
i = 20/10
i = 2 A.
Hence the current is 2A
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An Australian emu is running due north in a straight line at a speed of 13.0 m/s and slows down to a speed of 9.40 m/s in 3.50 s. (a) What is the magnitude and direction of the bird’s acceleration? (b) Assuming that the acceleration remains the same, what is the bird’s velocity after an additional 1.20 s has elapsed?
(B) False
Answers
Answer:
(B) False
Explanation:
No, it is not possible to have thunder without lightning. Thunder is a direct result of lightning.
B. Sprouted bean seeds increase.
C. Sprouted bean seeds remain constant.
D. None of the above
Answers
As we go up the y-axis, the number of sproutedbean seeds increase (option B).
What is a graph?
Graph is a data chart intended to illustrate the relationship between a set (or sets) of numbers (quantities, measurements or indicative numbers) and a reference set.
In a graph, there are two axes as follows;
- Y-axis or vertical axis
- X-axis or horizontal axis
According to this question, a graph of number of sprouted bean seeds on the y-axis is plotted against temperature on the x-axis.
We can observe that as we go up the y-axis, the number of sprouted bean seeds increase.
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Answers
Answer:
correct answer is 1 and 3
Explanation:
In direct measurement with an instrument, the precision or absolute error of the instrument is given by its appreciation, in this case we see that the measurements have two decimal places, so the appreciation of the instrument must be 0.01 cm
Based on this appreciation, the valid measurements are 5.52 and 5.5.
the other two measurements have errors much higher than the assessment of the instrument, for which there must have been some errors in the measurement.
The correct answer is 1 and 3
Answers
Answer:
The 1.5V battery can power the flashlight bulb drawing 0.60A for 83.33 minutes before it is depleted.
Explanation:
To determine how long a 1.5V battery can power a flashlight bulb drawing 0.60A, you can use the formula for calculating the energy (in joules) consumed by an electrical device over time:
Energy (Joules) = Power (Watts) × Time (Seconds)
In this case, the power (P) is given by the product of the voltage (V) and current (I):
Power (Watts) = Voltage (Volts) × Current (Amperes)
So, first, calculate the power consumption of the flashlight bulb:
Power (Watts) = 1.5V × 0.60A = 0.90 Watts
Now, you want to find out how long the battery can power the bulb, so rearrange the energy formula to solve for time:
Time (Seconds) = Energy (Joules) / Power (Watts)
Given that the battery stores 4.5 kJ (kilojoules), which is equivalent to 4,500 joules, and the power consumption is 0.90 watts:
Time (Seconds) = 4,500 J / 0.90 W = 5,000 seconds
Now, to express the time in more practical units, convert seconds to minutes:
Time (Minutes) = 5,000 seconds / 60 seconds/minute ≈ 83.33 minutes
So, the 1.5V battery can power the flashlight bulb drawing 0.60A for approximately 83.33 minutes before it is depleted.
Answers
The ratio of the electric force on the proton after the wire segment is shrunk to three times its original length to the force before the segment was shrunk is 3.
The electric force between a point charge and a segment of wire with a distributed charge is given by Coulomb's law.
The formula for the electric force on a point charge q due to a segment of wire with charge Q distributed along its length L is:
where:
F is the electric force on the point charge,
k is Coulomb's constant ( 8.988 × 1 0⁹ Nm²/ C²),
q is the charge of the point charge,
Q is the charge distributed along the wire segment, and
L is the length of the wire segment.
When the wire segment is shrunk to one-third of its original length, the new length becomes 1/3 L.
The chargedistribution remains the same, only the length changes.
So, the new electric force on the proton after the segment is shrunk becomes:
The original electric force on the proton before the segment was shrunk is:
let's find the ratio :
Hence, the ratio of the electric force on the proton after the wire segment is shrunk to the force before the segment was shrunk is 3.
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Final answer:
The ratio of the electric force on the proton after the wire segment is shrunk is equal to the ratio of their charges.
Explanation:
The ratio of the electric force on the proton after the wire segment is shrunk to the force before the segment was shrunk can be found using Coulomb's law. Coulomb's law states that the electric force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
In this case, the charges involved are the charge of the wire segment and the charge of the proton. Since the wire segment contains 10 nC of charge, we can consider it as one of the charged objects. The proton is very far from the wire, so we can assume that the distance between them remains the same before and after the wire segment is shrunk. Therefore, the ratio of the electric force on the proton after the segment is shrunk to the force before the segment was shrunk is equal to the ratio of their charges.
Let's assume that the initial force on the proton is Fi and the final force on the proton is Ff. Using the given information, we have:
Fi = k(q1 * q2) / r^2
where k is the electrostatic constant, q1 and q2 are the charges of the wire segment and the proton respectively, and r is the distance between them.
After the wire segment is shrunk to one-third of its original length, the charge of the wire segment remains the same and the distance between the wire segment and the proton also remains the same. Therefore, the ratio Ff/Fi can be calculated as:
Ff/Fi = (q1 * q2) / (q1 * q2) = 1
Answers
Answer:
A light-year is the distance light travels in one year.
Answer:
Explanation:
a unit of astronomical distance equivalent to the distance that light travels in one year, which is 9.4607 × 1012 km (nearly 6 million million miles).